@BGTech1 it's bernoullies equation, if you look into it you'll see increasing one on one side makes it so you need to decrease on the other to balance out
@@BGTech1For when you do look at Bernoullis equation, the obstruction I believe you're talking about is what would be the static pressure. The hint is in the name, static, ie not moving. Ik it seems trippy since air is rushing by around the obstructions but there is actually always a thin boundary of air/fluid that isn't moving at the surface. Thats also where pitot static tubes get their name from. Those also work on Bernoulli's principle where if you know the static pressure and ambient / upstream pressure, you can calculate the velocity. If what you instead meant was the "piling up" of air at the entrance of the nozzle, yes that air is at a higher pressure, but it isnt moving nearly as fast. Think about sand in a funnel or an hour glass. The sand on top is barely moving but provides pressure while the sand exiting the nozzle is going as fast as it can. Why is that the case? Because mass / volume is conserved. In your search you will come across this What you wanna do (or what i believe your goal is) is to increase your mass/volume flow rate. How do you do that? Well the equation for that is Q=AV, where: - Q is the volumetric flow rate, - A is the Area - and V is the velocity. It's known as the continuity equation. It goes hand in hand with the Bernoulli Equation. I havent checked your other videos but given the area of the fan is fixed, your best bet is to increase its speed(without burning it up). Now, if you don't care about the volume/mass of air and just want a faster exit velocity, in your nozzle design you wanna play with the ratios of the inlet area to the outlet area because with volume being conserved, again that is: - Qin = Qout, - which is Ain •Vin = Aout • Vout - and if you rearrange for Vout, - it'll be [Ain • Vin]/ Aout = Vout. Your inlet area is gonna be fixed to the size of the fan and the speed will be whatever you set it to but don't worry because as the equation shows, Vout is inversely proportional to Aout, so the smaller Aout is, the faster Vout will be aaaaannnnddd in the end thats 1 way how we arrived at the orignal statemnt of nozzles increasing velocity! (Because remember, if flow is to be conserved and the speed increased, it has to come at the cost of something, and that something happens to be pressure.) Anyways sorry for the blob but i do get excited about fluid mechanics and i love seeing others try new things. Most importantly have fun! You can ignore everything I've said, Im just 1 stranger sharing
@@BGTech1 For when you do look at Bernoullis equation, the obstruction I believe you're talking about is what would be the static pressure. The hint is in the name, static, ie not moving. Ik it seems trippy since air is rushing by around the obstructions but there is actually always a thin boundary of air/fluid that isn't moving at the surface. Thats also where pitot static tubes get their name from. Those also work on Bernoulli's principle where if you know the static pressure and ambient / upstream pressure, you can calculate the velocity. If what you instead meant was the "piling up" of air at the entrance of the nozzle, yes that air is at a higher pressure, but it isnt moving nearly as fast. Think about sand in a funnel or an hour glass. The sand on top is barely moving but provides pressure while the sand exiting the nozzle is going as fast as it can. Why is that the case? Because mass / volume is conserved. In your search you will come across this What you wanna do (or what i believe your goal is) is to increase your mass/volume flow rate. How do you do that? Well the equation for that is Q=AV, where: - Q is the volumetric flow rate, - A is the Area - and V is the velocity. It's known as the continuity equation. It goes hand in hand with the Bernoulli Equation. I havent checked your other videos but given the area of the fan is fixed, your best bet is to increase its speed(without burning it up). Now, if you don't care about the volume/mass of air and just want a faster exit velocity, in your nozzle design you wanna play with the ratios of the inlet area to the outlet area because with volume being conserved, again that is: - Qin = Qout, - which is Ain •Vin = Aout • Vout - and if you rearrange for Vout, - it'll be [Ain • Vin]/ Aout = Vout. Your inlet area is gonna be fixed to the size of the fan and the speed will be whatever you set it to but don't worry because as the equation shows, Vout is inversely proportional to Aout, so the smaller Aout is, the faster Vout will be aaaaannnnddd in the end thats 1 way how we arrived at the orignal statemnt of nozzles increasing velocity! (Because remember, if flow is to be conserved and the speed increased, it has to come at the cost of something, and that something happens to be pressure.) Anyways sorry for the blob but i do get excited about fluid mechanics and i love seeing others try new things. Most importantly have fun! You can ignore everything I've said, Im just 1 stranger sharing
YT keeps deleting my comment in response to the nozzle thing by Momo1285_. I think you might find it useful: If what you meant by obstruction was the "piling up" of air at the entrance of the nozzle, yes that air is at a higher pressure, but it isnt moving nearly as fast. Think about sand in a funnel or an hour glass. The sand on top is barely moving but provides pressure while the sand exiting the nozzle is going as fast as it can. Why is that the case? Because mass / volume is conserved. In your search you will come across this What you wanna do (or what i believe your goal is) is to increase your mass/volume flow rate. How do you do that? Well the equation for that is Q=AV, where: - Q is the volumetric flow rate, - A is the Area - and V is the velocity. It's known as the continuity equation. It goes hand in hand with the Bernoulli Equation. I havent checked your other videos but given the area of the fan is fixed, your best bet is to increase its speed(without burning it up). Now, if you don't care about the volume/mass of air and just want a faster exit velocity, in your nozzle design you wanna play with the ratios of the inlet area to the outlet area because with volume being conserved, again that is: - Qin = Qout, - which is Ain •Vin = Aout • Vout - and if you rearrange for Vout, - it'll be [Ain • Vin]/ Aout = Vout. Your inlet area is gonna be fixed to the size of the fan and the speed will be whatever you set it to but don't worry because as the equation shows, Vout is inversely proportional to Aout, so the smaller Aout is, the faster Vout will be aaaaannnnddd in the end thats 1 way how we arrived at the orignal statemnt of nozzles increasing velocity! (Because remember, if flow is to be conserved and the speed increased, it has to come at the cost of something, and that something happens to be pressure.) Anyways sorry for the blob but i do get excited about fluid mechanics and i love seeing others try new things. Most importantly have fun! You can ignore everything I've said, Im just 1 stranger sharing
Thanks for commenting! This is pretty interesting, especially since I don’t need to take a fluid mechanics class for the branch of engineering I’m going into. (Electronics Engineering). I’m definitely planning on doing more with this project in the future.
@@BGTech1 no problem, I love sharing knowledge. I'm a mechatronics student, so I get to have fun in both worlds. I'm not sure, but maybe you'd do thermodynamics since electronics give off heat. Thermo/Heat Transfer and Fluid Mech are very closely related and, in some instances are analogies of one another. Ex. in fluid, we might have a pressure gradient and that determines fluid flow, but in thermo/heat transfer, you'll have a temperature gradient. All the conservation laws apply the same. Fluid is mass / volume, thermo is that OR energy. Anyway, have fun! It'll be a challenging degree, but your interests and effort already puts you ahead of so many ppl. Theory is fundamental, but in practice it's about what you can do
I never said it was a jet engine. I said I was going to make it more like one. It does create some thrust though, Just by holding even without the mods you can certainly feel it pushing back. (Every force has an equal and opposite reaction). I do plan on measuring it with and without the mods, so we can tell if it’s helping or not.
Explore using the scientific method! Like seriously do it and share the results @@BGTech1 however their comment is right. The Velocity stack is useful/designed for moving bodies. It's to ensure smooth and laminar flow into a jet engine / fan. In your case, if the trumpet is large enough and you do smoke tests it could make for great visuals
It’s a standard sized computer fan so you could use it in your build if you wanted. It would be really loud though and you can’t use Your motherboard fan headers.
A nozzle does increase velocity but not pressure
Why? Your creating an obstruction so isn’t the pressure going to increase too?
@BGTech1 it's bernoullies equation, if you look into it you'll see increasing one on one side makes it so you need to decrease on the other to balance out
Interesting, I’ll have to look into it some more. That’s not what I expected.
@@BGTech1For when you do look at Bernoullis equation, the obstruction I believe you're talking about is what would be the static pressure. The hint is in the name, static, ie not moving. Ik it seems trippy since air is rushing by around the obstructions but there is actually always a thin boundary of air/fluid that isn't moving at the surface. Thats also where pitot static tubes get their name from. Those also work on Bernoulli's principle where if you know the static pressure and ambient / upstream pressure, you can calculate the velocity.
If what you instead meant was the "piling up" of air at the entrance of the nozzle, yes that air is at a higher pressure, but it isnt moving nearly as fast. Think about sand in a funnel or an hour glass. The sand on top is barely moving but provides pressure while the sand exiting the nozzle is going as fast as it can. Why is that the case? Because mass / volume is conserved. In your search you will come across this
What you wanna do (or what i believe your goal is) is to increase your mass/volume flow rate. How do you do that? Well the equation for that is Q=AV, where:
- Q is the volumetric flow rate,
- A is the Area
- and V is the velocity.
It's known as the continuity equation. It goes hand in hand with the Bernoulli Equation. I havent checked your other videos but given the area of the fan is fixed, your best bet is to increase its speed(without burning it up). Now, if you don't care about the volume/mass of air and just want a faster exit velocity, in your nozzle design you wanna play with the ratios of the inlet area to the outlet area because with volume being conserved, again that is:
- Qin = Qout,
- which is Ain •Vin = Aout • Vout
- and if you rearrange for Vout,
- it'll be [Ain • Vin]/ Aout = Vout.
Your inlet area is gonna be fixed to the size of the fan and the speed will be whatever you set it to but don't worry because as the equation shows, Vout is inversely proportional to Aout, so the smaller Aout is, the faster Vout will be aaaaannnnddd in the end thats 1 way how we arrived at the orignal statemnt of nozzles increasing velocity! (Because remember, if flow is to be conserved and the speed increased, it has to come at the cost of something, and that something happens to be pressure.)
Anyways sorry for the blob but i do get excited about fluid mechanics and i love seeing others try new things. Most importantly have fun! You can ignore everything I've said, Im just 1 stranger sharing
@@BGTech1 For when you do look at Bernoullis equation, the obstruction I believe you're talking about is what would be the static pressure. The hint is in the name, static, ie not moving. Ik it seems trippy since air is rushing by around the obstructions but there is actually always a thin boundary of air/fluid that isn't moving at the surface. Thats also where pitot static tubes get their name from. Those also work on Bernoulli's principle where if you know the static pressure and ambient / upstream pressure, you can calculate the velocity.
If what you instead meant was the "piling up" of air at the entrance of the nozzle, yes that air is at a higher pressure, but it isnt moving nearly as fast. Think about sand in a funnel or an hour glass. The sand on top is barely moving but provides pressure while the sand exiting the nozzle is going as fast as it can. Why is that the case? Because mass / volume is conserved. In your search you will come across this
What you wanna do (or what i believe your goal is) is to increase your mass/volume flow rate. How do you do that? Well the equation for that is Q=AV, where:
- Q is the volumetric flow rate,
- A is the Area
- and V is the velocity.
It's known as the continuity equation. It goes hand in hand with the Bernoulli Equation. I havent checked your other videos but given the area of the fan is fixed, your best bet is to increase its speed(without burning it up). Now, if you don't care about the volume/mass of air and just want a faster exit velocity, in your nozzle design you wanna play with the ratios of the inlet area to the outlet area because with volume being conserved, again that is:
- Qin = Qout,
- which is Ain •Vin = Aout • Vout
- and if you rearrange for Vout,
- it'll be [Ain • Vin]/ Aout = Vout.
Your inlet area is gonna be fixed to the size of the fan and the speed will be whatever you set it to but don't worry because as the equation shows, Vout is inversely proportional to Aout, so the smaller Aout is, the faster Vout will be aaaaannnnddd in the end thats 1 way how we arrived at the orignal statemnt of nozzles increasing velocity! (Because remember, if flow is to be conserved and the speed increased, it has to come at the cost of something, and that something happens to be pressure.)
Anyways sorry for the blob but i do get excited about fluid mechanics and i love seeing others try new things. Most importantly have fun! You can ignore everything I've said, Im just 1 stranger sharing
YT keeps deleting my comment in response to the nozzle thing by Momo1285_. I think you might find it useful:
If what you meant by obstruction was the "piling up" of air at the entrance of the nozzle, yes that air is at a higher pressure, but it isnt moving nearly as fast. Think about sand in a funnel or an hour glass. The sand on top is barely moving but provides pressure while the sand exiting the nozzle is going as fast as it can. Why is that the case? Because mass / volume is conserved. In your search you will come across this
What you wanna do (or what i believe your goal is) is to increase your mass/volume flow rate. How do you do that? Well the equation for that is Q=AV, where:
- Q is the volumetric flow rate,
- A is the Area
- and V is the velocity.
It's known as the continuity equation. It goes hand in hand with the Bernoulli Equation. I havent checked your other videos but given the area of the fan is fixed, your best bet is to increase its speed(without burning it up). Now, if you don't care about the volume/mass of air and just want a faster exit velocity, in your nozzle design you wanna play with the ratios of the inlet area to the outlet area because with volume being conserved, again that is:
- Qin = Qout,
- which is Ain •Vin = Aout • Vout
- and if you rearrange for Vout,
- it'll be [Ain • Vin]/ Aout = Vout.
Your inlet area is gonna be fixed to the size of the fan and the speed will be whatever you set it to but don't worry because as the equation shows, Vout is inversely proportional to Aout, so the smaller Aout is, the faster Vout will be aaaaannnnddd in the end thats 1 way how we arrived at the orignal statemnt of nozzles increasing velocity! (Because remember, if flow is to be conserved and the speed increased, it has to come at the cost of something, and that something happens to be pressure.)
Anyways sorry for the blob but i do get excited about fluid mechanics and i love seeing others try new things. Most importantly have fun! You can ignore everything I've said, Im just 1 stranger sharing
Thanks for commenting! This is pretty interesting, especially since I don’t need to take a fluid mechanics class for the branch of engineering I’m going into. (Electronics Engineering). I’m definitely planning on doing more with this project in the future.
@@BGTech1 no problem, I love sharing knowledge. I'm a mechatronics student, so I get to have fun in both worlds. I'm not sure, but maybe you'd do thermodynamics since electronics give off heat. Thermo/Heat Transfer and Fluid Mech are very closely related and, in some instances are analogies of one another.
Ex. in fluid, we might have a pressure gradient and that determines fluid flow, but in thermo/heat transfer, you'll have a temperature gradient. All the conservation laws apply the same. Fluid is mass / volume, thermo is that OR energy.
Anyway, have fun! It'll be a challenging degree, but your interests and effort already puts you ahead of so many ppl. Theory is fundamental, but in practice it's about what you can do
Hey bro can’t you make me like a fan case that can sit on a desk with just a 12V fan,
It’s not a jet engine. Therefore it’s not moving forward. Your velocity stack probably isn’t doing what you think it is.
I never said it was a jet engine. I said I was going to make it more like one. It does create some thrust though, Just by holding even without the mods you can certainly feel it pushing back. (Every force has an equal and opposite reaction). I do plan on measuring it with and without the mods, so we can tell if it’s helping or not.
Explore using the scientific method! Like seriously do it and share the results @@BGTech1 however their comment is right. The Velocity stack is useful/designed for moving bodies. It's to ensure smooth and laminar flow into a jet engine / fan. In your case, if the trumpet is large enough and you do smoke tests it could make for great visuals
They do move forward and lift themselves up
Add crossbars to support a cone just in front of the fan hub.
That’s a good idea! I might try that eventually
Hey this is cool man
Thanks I appreciate it!
Let’s go
Is this a 3phase delta fan? If so why is it 4 wire?
No, it’s 12v DC. Red and black for power, and the other two wires are for PWM speed control and the tachometer
@@BGTech1 thank you sire
wow
is it 3d printed?
Yes, the red parts are
Get a delta contra-rotator
I would like too, but they are not that common
OK but how do I put 4 of those in my mid atx case?
Your computer would fly away like a plane and it would sound like one too!
@@BGTech1 🤣
@@BGTech1 I thought of implementing this at a lower scale ofcourse, but for the exhaust fan of a pc 😅
It’s a standard sized computer fan so you could use it in your build if you wanted. It would be really loud though and you can’t use Your motherboard fan headers.
>>>STL files plz :)
Send me an email (link in my about page) and I will send them.
@@BGTech1 Okay, thanks to you, bro.
Throw it in a pc😂