I was bashing my head against a wall after missing 10 straight graphing polar problems in my assigned homework until I saw this just now. You're technique is amazing with setting the argument of 2Theta = pi/2, then finding it in its actual x\y graph, then translating into polar. Very helpful. Subscribed!
Thank you very much for this video. I reviewed the book several times and studied my notes and could not understand it. Your video cleared it all up perfectly. Please continue doing what you do, your videos are the best.
I've been watching your videos since I took AP calc my junior yr in high school. I'm now taking vector calc in college and here I am again. This really helped. Thank you!
Great explanation on graphing polar equations the whole strategy of equaling theta to pi/2 is not taught in my book which is just an amazing tool to know, thank you so much your are the best !
OOOOOMMMMMMHHHHHHGGGGGGGGG! I get it now... sitting in a 4 hour lecture of math is really conterproductive/mind numbing...I zone out all the time. You saved me and my grade!
Wow u seem to pretty talented and smart, thank u very much for this video. I understood everything, and I feel like I'm in your brain from how professionaly u teach. 🤩🤩🤩🤩
Watching as many of these polar sketching vids as I can, precalculus honors final will probably have a ton of these problems and I never took notes on the basic patterns to do quick sketches
Thank you so much! A really great video on how to sketch polar curves and this helped me a lot! But I got a doubt, why do we set theta equals pi over 2?
Because the sine and cosine values at multiples of π/2 are always 0, 1, or -1, which makes them really easy to calculate. I'm so glad you liked the video! :)
Hi. Thanks a lot. I have the same question as Justin Jackson: "So on r=6+4sin(θ), how do you know that for the angle between π and 3π/2 and 3π/2 to 2π the line curves like that, rather than just being a half of a parabola like the other two?"
no, because the purple section is over the interval pi to 5pi/4, and when you translate that to polar axes, the angle pi to 5pi/4 is where we graphed the purple section. hope that helps!
So on r=6+4sin(θ), how do you know that for the angle between π and 3π/2 and 3π/2 to 2π the line curves like that, rather than just being a half of a parabola like the other two?
For the region from pi/2 to 3pi/4, r = -7 is in the 4th quadrant however why u choose to draw the region below the line(green line region)? why not above the line(blue line region?
Thank u profesor, but I still get very confused about finding the angles qhen plotting this type of graphs, I'd seen some people making the equation equal to zero and then they add a constant Is teally frustrating , because I get diferent values..worst is that my test is next monday.
You're the best teacher ever !! Very simple but very understandable!
Thank you so much, I'm so glad you liked it! :)
I was bashing my head against a wall after missing 10 straight graphing polar problems in my assigned homework until I saw this just now. You're technique is amazing with setting the argument of 2Theta = pi/2, then finding it in its actual x\y graph, then translating into polar. Very helpful. Subscribed!
Awesome, thank you so much! I'm so glad it helped!!
Krista is saving lots of math goers by sharing these elegant videos. Thank you very much!
I could listen to you teach calculus all day. You'r much prettier than the mean old man at school!
Thank you so much. I was struggling for AGES on this. Thank you so much for clearing this out for me. Your help is deeply appreciated.
Thank you very much for this video. I reviewed the book several times and studied my notes and could not understand it. Your video cleared it all up perfectly. Please continue doing what you do, your videos are the best.
Thanks! I'm so glad I could help! :)
Took me quite some time to try and figure it out, almost gave up and then stumbled on this video. Thanks and keep up the good work!
+Jason Lau You're welcome, I'm so glad it helped!
You are such a life saver! i've tried to understand this stuff for days and in 17 mins you explained everything perfectly! Definitely subscribed! :)
Awesome! :D I'm so glad it helped!! :D
very clear explain and very useful.Knowing how to draw is essentially for calculating the problem about polar coordinate
I've been watching your videos since I took AP calc my junior yr in high school. I'm now taking vector calc in college and here I am again. This really helped. Thank you!
love that! :D
I've never heard it referred to as rapid sketching, but it might be and I just haven't heard of it. I'm glad the video made sense! :D
Great explanation on graphing polar equations the whole strategy of equaling theta to pi/2 is not taught in my book which is just an amazing tool to know, thank you so much your are the best !
steve khan I'm so glad it helped!
very good video how you go at agood pace for people trying to learn this and you show a range of graphs well done!
Thank you so much! :)
Very helpful! I just needed to brush up on polar sketching for my Calc II final tomorrow and this was perfect. Thanks!
Good luck on your final!
Wow I have been watching lots of videos on how to graph polar and yours is by far the best pie/2 👍
Ive been watching your videos for some time now, really amazing work. everything I have a calc question I come to this channel .
+Tyler Johnson Wow thanks! I'm glad I've been able to help!
A very succinct explanation, especially with the use of different colours for the different regions. Thank you for this! :)
Polar coordinates make me wonder if flowers know trigonometry.
Again, you are an awesome teacher!
Aww thanks! :)
Wow, you are an awesome teacher indeed!! You made it so easy to understand
You're a life saver.
U r a great teacher !!! even better than my lecturers. Excellent work and keep it up. oh and yeah, thank you so much
+Hishaam Ahmad You're welcome! Glad I could help.
OOOOOMMMMMMHHHHHHGGGGGGGGG! I get it now... sitting in a 4 hour lecture of math is really conterproductive/mind numbing...I zone out all the time. You saved me and my grade!
I'm so glad I could help!! :D
I love your teaching, inspiring and colorful
+Kuro Hanaku Thank you very much!
Simple and to the point... great for revision (actually better then the lecture).. thanks..
That's so awesome! So glad I could help. :D
Excellent video. Much simpler explanation than my textbook!
That was amazing. Thank you, Krista!
Thank you so much! I feel a lot more comfortable with sketching polar curves now :)
You're welcome, I'm so glad it helped!
Glad you liked it!
You have just saved my life... Thumbs up!!!
I'm glad I could help! :)
you're welcome, i'm so glad it helped!! :D
well presented and wonderfully drawn/annotated
Thanks!
Very nifty way of doing this stuff. Thanks for sharing
your advice for setting up the increment value is really handy, thx
You're welcome, I'm so glad it helped! :)
Thank you!! Thank you!! This makes so much sense! I did not understand what my teacher was saying.
i'm so glad it makes sense!! :D
@Snappy4Snapple That makes me so happy! :) I'm glad I can help.
You have the twist to teach that kind of thing thanks!
you killed this one... thanks so much~!!!!!
This was very helpful. I forgot how to work with these. Thank you so much.
You're welcome! I'm glad it could help. :)
You're so welcome!
Glad I could help! :)
Wow u seem to pretty talented and smart, thank u very much for this video. I understood everything, and I feel like I'm in your brain from how professionaly u teach. 🤩🤩🤩🤩
You definitely helped! Now to calculate areas and lengths of polar curves...
+Victor Salas I'm glad it helped!
elaborately explained ..... really helpful.....
Thanks!
Watching as many of these polar sketching vids as I can, precalculus honors final will probably have a ton of these problems and I never took notes on the basic patterns to do quick sketches
Thank you so much! A really great video on how to sketch polar curves and this helped me a lot! But I got a doubt, why do we set theta equals pi over 2?
Because the sine and cosine values at multiples of π/2 are always 0, 1, or -1, which makes them really easy to calculate. I'm so glad you liked the video! :)
Perfect explanation.
thanks so much! your video helps me a lot !
That was very helpful.....Thanx Krista you are awesome.......
Glad you liked it! :D
You are literally the reason I passed Calculus II hahaha. Well, my final is in 8 hours but I am gonna kill it because of you. So thanks!
Good luck on the final! I hope you crush it!
Hi. Thanks a lot. I have the same question as Justin Jackson: "So on r=6+4sin(θ), how do you know that for the angle between π and 3π/2 and 3π/2 to 2π the line curves like that, rather than just being a half of a parabola like the other two?"
omg thank you so much for this video my calculus teacher didn't teach us this and just gave use homework.
+TheDrunkMexicano You're welcome, I'm so glad it helped!
This was so helpful!! Thank you so much!!
+Sydney Le Cras You're welcome, I'm so glad it helped!
You're welcome!
glad you liked it! :)
You make me love math thanks again
+MoGunnz24 Yay! Love that!
OMG, this was so helpful! Thank you so much!!!!
You're welcome, Isaiah! I'm so glad it helped! :D
Awesome! Glad to hear that. :)
quick question though, 11:47 for the purple line is positive 7 right ? should it be on top left side instead?
no, because the purple section is over the interval pi to 5pi/4, and when you translate that to polar axes, the angle pi to 5pi/4 is where we graphed the purple section. hope that helps!
thank you, very well taught.
super explanation,better than class teacher,do upload more!!!!
Will do! :)
ok thanks a lot
do upload on topic finding limits on triple integral..........
You're welcome!! :)
Thank you so much about that video, it is really help. by the way you scared me at the last second! lol
李昕洋 lol, sorry about that!
thank you Krista
You're welcome! :)
gracias Profesora King!
So on r=6+4sin(θ), how do you know that for the angle between π and 3π/2 and 3π/2 to 2π the line curves like that, rather than just being a half of a parabola like the other two?
thank u very much,nice lecture
thanks a lot!!!! this video is very helpful for me !!
You're welcome, I'm so glad it helped!
For the region from pi/2 to 3pi/4, r = -7 is in the 4th quadrant however why u choose to draw the region below the line(green line region)? why not above the line(blue line region?
Thank you very much for great tutorials.. :)
+mustafa ssk You're welcome!
Thank you so much! You're AMAZING!!!!
Aw thanks!
@medeepu1 Thanks for the feedback. :)
totally helpful and informative :P Thanks a lot for posting this video :)
You're welcome! :)
how when we go from 0 to pi/2 it was towards positive 7 and also when we go opposite to it from pi to 5pi/2 it is also towards 7 not negative 7
there is no negative 7. Your r value is positive regardless of theta.
Awesome help!
Amazing! Life saver !
best explanation!
:D
i'm so glad! :)
when you graph 2 sin(5theta) i am getting a circle. i set 5theta=pi/2. is seting pi/2 to the inside angle works only for even numbers?
you're welcome!! :)
whats the chalkboard program/software called? looks neat
Well explained.
Thanks!
Assume you were given an equation with cos(thetha). Would you also set thetha equal to pi/2?
It can be, yes.
i'm glad! you're welcome. :)
Thank u profesor, but I still get very confused about finding the angles qhen plotting this type of graphs, I'd seen some people making the equation equal to zero and then they add a constant Is teally frustrating , because I get diferent values..worst is that my test is next monday.
Thank you so much!!!
This should work for non linear equations also right?? like r=sin^2(theta)+ sin(theta)
Can u comment upon how x(n)=e^i((π/2)n + (π/2)) is a power signal,
PLZ...
thank you really helped a lot :)
Grade saver
So u set = to pi/2 when is sin, do you work it the same way when is cosine?
yes, you still use pi/2 with cosine.
And how do you use the unit circle for cos()?
What application are you using to create the chall board and chalk effect?
The little piece of chalk is just an image I made, and I edit it into my videos using Screenflow. :)
@twowinds lol :) I wish I could say otherwise....but ya, some aspirin comes in handy. :)
U R AN ANGEL
How do you know which way to curve the line?