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Well explained..💕
Thank you.
You're welcome!
Maybe you should write more on how to calculate ∫exp(ax)sin(bx)dx which is calculated by ∫ v du = uv - ∫ u dvbut anyway thank you
Thanks for watching and commenting ..The said integral is evaluated in this lecture ua-cam.com/video/hluQclB0-s4/v-deo.html
Well explained..💕
Thank you.
You're welcome!
Maybe you should write more on how to calculate
∫exp(ax)sin(bx)dx
which is calculated by
∫ v du = uv - ∫ u dv
but anyway thank you
Thanks for watching and commenting ..The said integral is evaluated in this lecture ua-cam.com/video/hluQclB0-s4/v-deo.html