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I am mathematical novice, but I love to watch the easy to understand steps you present to solve this problem. Thank you. New subscriber.
2^x*2^x=202^x+x=202^2x=202^2x=2^log2(20)2x=log2(20)x=(log2(20)/2)Thia is right?
{10+10}=20 10^10 5^5^5^5 2^3^2^3^2^3^2^3 1^1^1^1^1^1^2^1 2^1 (a ➖ 2a+1).
I am mathematical novice, but I love to watch the easy to understand steps you present to solve this problem. Thank you. New subscriber.
2^x*2^x=20
2^x+x=20
2^2x=20
2^2x=2^log2(20)
2x=log2(20)
x=(log2(20)/2)
Thia is right?
{10+10}=20 10^10 5^5^5^5 2^3^2^3^2^3^2^3 1^1^1^1^1^1^2^1 2^1 (a ➖ 2a+1).