Відео

Even if there are alternative procedures to solve this equation, this is still a good review of an area of algebra that I studied some time (some LONG time!) ago. Thanks for posting this.

Sir very good question ❤❤❤❤❤❤❤

i suggest to subtract root 2 on both sides

X=1 is The Only solution. You can't take log from complex number!

3(n^1/2)=2 n=(2/3)^2=4/9

Much easier is to leave square roorh x on 1 side and then square both side. I got x1 only, not x2.

8*9^6=8*81^3=648*6 561=4 251 528

Can't we do sum like this 3^3x = 27 We can write 27 as 3^3 3^3x = 3^3 The bases are same so We will get this equation 3x = 3 x=3/3 x=1 1 satisfy the equation Check 3^x = 27 Substitute the x value 3^3(1) = 27 3^3 = 27 27 = 27 L.H.S = R.H.S IS IT RIGHT SIR?

3^4^5+3^4^2 3^2^2^2^3+3^2^2^2 1^1^1^1^1+3^1^1^2 3^2 (x ➖ 3x+2).

{0+0 ➖} ^1=1^1 (x ➖1 x+1).

2^5^2^5vs9^11^1 1^1^2^1vs^3^2^1^1 (x ➖ 2x+1) .2^1vs3^1(x ➖ 3x+1).2^1<3^1. 10^10<9^11.

{2+2 ➖ }+n^2+{n+n ➖ }={4+n^2+n^2}=4n^4 2^2n^2^2 2^1n^1^1 2n^1(n ➖ 2n+1).

{3+3 ➖ }+x^2+{x+x ➖ }={6+x^2+x^2}=6x^4 3^3x^2^2 3^1x1^2 3x^2 (x ➖ 3x+2).

{4+x^2}=4x^2 2^2x^2 1^1x^2 1x^2 (x ➖ 2x+1).

6^{n+n ➖ }+{7+7 ➖ }=6^{n^2+14}=6^14n^2=84n^2 6^7^7n^2 6^3^4^3^4n^2 3^3^1^2^2^1^2^2n^2 3^1^1^1^1^1n^2 3n^2 ( n ➖ 3n+2). 7^{n+n ➖ }+{6+6 ➖}7^{n^2+12 }=7^12n^2 84n^2 7^6^6n^2 3^4^3^3^3^3n^2 1^2^2^1^1^3^1n^1 2^1^3^1^n 2^3^n (n ➖ 3n+2).

2^(5) 2^(1) (m ➖ 2m+1). m^2^16 m^2^4^ m^2^2^2 m^1^1^2 m^1^2(m ➖ 2m+1).

(k ➖ 3k+3). 27 3^3 (k ➖ 3k+3).

{10+10}=20 10^10 5^5^5^5 2^3^2^3^2^3^2^3 1^1^1^1^1^1^2^3 2^3 (n ➖ 3n+2).

Go to 3:00 to skip useless filler. Nor sure why all these mathematicians are so verbose. LOL The thing is, anyone who watches one of these already knows about commutative, associative, exponents, logs, algebra, substitution, etc and do not require excruciating details. Just a suggestion.

K=3

2√n+√n=2 (2√n+√n)²=2² (2√n+√n)*(2√n+√n)=4 2√n*2√n*+2√n*√n+√n*2√n+√n*√n=4 4n+2n+2n+n=4 9n=4 n=4/9 🙂

Thank you for explaining. I think the calculation in the video is complicated. I think the next method is easier (for calculating). √2 + √x = 2 ∴ √x = 2 - √2 ∴ x = (2 - √2)^2 = 2^2 - 4√2 + 2 = 6 - 4√2

((3×(3^(1/2))^(1/2)+((2×(3^(1/2))^(1/2)

√x=2-√2 x= (2-√2)²= 6-4√2 Easily

👍👍👍

there is not only exponential growth but there is also tetrational growth, pentational growth, hexational growth, and so on...

N=0, N=(1/9)

Gringo lo hice de memoria n=0

Thumbnail says "2ⁿ + 2ⁿ = 20"

X1=6-(4×2^(1/2)),X2=6+(4×2^(1/2))

Nine Because: radical of potent 3 of 9, it is 3 And: 27^(9) = √3^(3) it will be easy. So do...: ^(3) × ^(3) is ^(9) (but under √ is ^(3)) And...: 3 ^(9) = 27 ^(9) will be 27 ^(9)/√3^(9) = 27/3 = 9 and √^(9) = ^(3). So...: 9/3^(3) make 1 And return all.

6^(n+7)=7^(n+6) 6*6^(n+6)=7^(n+6) | let m=n+6 6^(m+1)=7^m (m+1)ln6=mln7 (m+1)/m=log_6(7) 1+1/m=log_6(7) 1/m=log_6(7)-1 m=1/(log_6(7)-1) | n=m-6 n=-6+1/(log_6(7)-1) n=5.623428915369726695883976610087 6^(n+7)=6 651 766 485.3983310054880097687784 7^(n+6)=6 651 766 485.3983310054880097687784

아니 3의 1800승을 구해야 하는데 그건 안 구하고 갑자기 2로 바꼈나요?

n = 0 or 1/9

C'mon, filling a 9 min video with a 1st grade math problem and suggesting it's anything tricky.

3n=_/n........n=1/9

(7^×}`3=3^3 X=Log @7(3)

7^{3x+3x ➖}=7^6x^2=42x^2 6^7x^2 6^7^1x^2 2^3^1^1x^2 1^1^x^2 1x^2 (x ➖ 2x+1).

2401 49^49 2^2^3^3^2^2^3^3 1^1^1^1^1^2^1^1 2^1 (k ➖ 2k+1).

7^(3x)=27 => 343^x=27 => x=ln27/ln343 => x=0.56457503405357961380455016717491

(2^(3)=8 2^(1) (n ➖ 2n+1).

good one

N=1/9

This could have been easily solved We know 1 to power anything is 1 so we can eliminate the 4^5 part Now we are left with 2^6^2 which is equal to 2^36 Now √2^36 is 2^18 which is 262144

First 2.5 minutes are proof this creator likes to waste time and has never done an olympiad.

This is also an answer K=e^-w(-ln5×e^(-4×ln5)). [Ans] Or simplify it,will be K=e^(-w(-ln5/5⁴) Well if you calculate this then the answer you will get which is ≈1.0025809314... ୧⁠(⁠＾⁠ ⁠〰⁠ ⁠＾⁠)⁠୨

√n = m 2^m = 8^(m^2) = 2^(3m^2) m = 3m^2 m(3m - 1) = 0 m = 0, 1/3 n = 0, 1/√3

1/2^3 1/2^1 /2^1 (x ➖ 2x+1).

5^(4)=625 2^3^(2^2) 1^3^(2^1) 3^(2) (k ➖ 3k+2).

1/9