I had a teacher like him. But he was very strict and used to best children who didn't study. I beat me too. I used to fail in maths till 7th grade every time successfully. But when He started teaching us. I got 56/100. I was shocked. Then in second exam I got 83/100. In finals I got 80/100. Many students in my class had perfect scores. He was a phenomenal teacher. It is because of him I am studying Physics Major in College. A good teacher can work miracles.
sir can you please please teach these chapters. I am fond of your teaching style and it is quick to pick up as well. I am in grade 12th from India. *this is priority wise order 1) CONTINUITY AND DIFFERENTIATION 2) RELATIONS AND FUNCTIONS 2) DIFFERENTIAL EQUATIONS 3) INTEGRALS 4) VECTORS 5) INVERSE TRIGNOMETRY
Thank you very much sir. I have only a question:, how were you able to calculate the reciprocal of the square of five so quicky, do you have some trick? However your lessons are always interesting.
I did the same thing until you approached 2^[2/{log5(x)] = -4 What I did next is multiply both sides by log5(x) so that: -4{log5(x)} = 2 Now move the -4 at the front to the exponent of x in the LHS(logarithm property) so that: log5(x^-4) = 2 Now we pair the base and the exponent(5 and 2 respectively) on one side and the argument on the other side(x^-4) Now, we made an equation so that: x^-4 = 5^2 Now multiply both sides by -1/4 so that: x=5^(-1/2) Or, x=1/sqrt(5) If the question asks for the value too, put it on the calculator and the approximate value is 0.447 upto 3 decimal places
If I had a teacher like YOU! Always so clear! I am almost ashamed to be unable to solve it, though SO SIMPLE!!!
If I had a teacher like him. I would be far in life
No you won’t
@@whatever9515 I would be in NASA or on the Moon
😂
Yeah, he is good
I had a teacher like him. But he was very strict and used to best children who didn't study. I beat me too. I used to fail in maths till 7th grade every time successfully. But when He started teaching us. I got 56/100. I was shocked. Then in second exam I got 83/100. In finals I got 80/100. Many students in my class had perfect scores. He was a phenomenal teacher. It is because of him I am studying Physics Major in College. A good teacher can work miracles.
Amazing explanation👏 Keep up the good work!
Thank you! Will do!
Outstanding!
sir can you please please teach these chapters. I am fond of your teaching style and it is quick to pick up as well. I am in grade 12th from India.
*this is priority wise order
1) CONTINUITY AND DIFFERENTIATION
2) RELATIONS AND FUNCTIONS
2) DIFFERENTIAL EQUATIONS
3) INTEGRALS
4) VECTORS
5) INVERSE TRIGNOMETRY
nice solution✌
greate Teacher !
X= 1/sq.rt.(5)?
Correct
Simply great, this is awesome, many thanks, Sir!
My pleasure 🙏
All support for you sir❤
Thank you! 😊
Good video
Very good.
I wish I had this math teacher
As a jee aspirant i solved the sum by seeing only the thumnail and came here to verify my answer which is right
ME TOO
VERY EASY QUESTION 😂
Thank you very much sir. I have only a question:, how were you able to calculate the reciprocal of the square of five so quicky, do you have some trick? However your lessons are always interesting.
I used a calculator : )
How does he write with the chalk like that…standing in that position
Is it valid to instead go from 2^(2/log5x)=1/16 to log2(1/16) = 2/(log5x) to log5xlog2(1/16) = 2 to log5x = 2/log2(1/16) which is x = 5^(2/log2(1/16)?
I did the same thing until you approached 2^[2/{log5(x)] = -4
What I did next is multiply both sides by log5(x) so that:
-4{log5(x)} = 2
Now move the -4 at the front to the exponent of x in the LHS(logarithm property) so that:
log5(x^-4) = 2
Now we pair the base and the exponent(5 and 2 respectively) on one side and the argument on the other side(x^-4)
Now, we made an equation so that:
x^-4 = 5^2
Now multiply both sides by -1/4 so that:
x=5^(-1/2)
Or, x=1/sqrt(5)
If the question asks for the value too, put it on the calculator and the approximate value is 0.447 upto 3 decimal places
First-rate resolution!
Why does the 2/-4 suddenly become -1/2, without log5x changing?
Love your videos, thank you!
He just change it to its lowest form, even if you dont do that you will still arrive with the same answer.
He just simplified the fraction from 2/-4 to -1/2 into its simplest form.
1/5^1/2
didn't get the first yellow line...
(trying to remember all that from 25yrs ago)
🤣