Here's another quick method: 1. Cancel the fraction on the left side with √k: (√k)/k = 1/√k 2. [Optional] Rewrite as follows: 1/√k = √(1/k) 3. Now you have the equation √(1/k) = √6, which is only correct if the respective terms under the roots are equal, therefore: 1/k = 6 [You could also arrive to this by squaring both sides.] 4. Take reciprocal: k = 1/6 But, dude, I feel insulted by this clickbaity title. There is no chance in hell that 99% of all students failed this basic problem, and in f'ing Harvard this won't even happen if you'd made all students drunk before presenting them with the math problem. Plus, Harvard isn't in Japan. I don't like to be lied to (and your title is clearly lying to us), therefore I'm downvoting your video. Be better next time. Don't insult and lie to your viewers.
2^3 (k ➖ 3k+2).
k/k² = 6
k = 6k²
k-6k² = 0
k(1-6k) = 0
k ≠ 0
1 = 6k
k = ⅙
Here's another quick method:
1. Cancel the fraction on the left side with √k:
(√k)/k = 1/√k
2. [Optional] Rewrite as follows:
1/√k = √(1/k)
3. Now you have the equation √(1/k) = √6, which is only correct if the respective terms under the roots are equal, therefore:
1/k = 6
[You could also arrive to this by squaring both sides.]
4. Take reciprocal:
k = 1/6
But, dude, I feel insulted by this clickbaity title. There is no chance in hell that 99% of all students failed this basic problem, and in f'ing Harvard this won't even happen if you'd made all students drunk before presenting them with the math problem.
Plus, Harvard isn't in Japan.
I don't like to be lied to (and your title is clearly lying to us), therefore I'm downvoting your video.
Be better next time.
Don't insult and lie to your viewers.