I wasn't able to solve it. So I decided to watch solution. But then he told this : 1:40 (similar to 5 pirates and treasure). I again paused the video and solved the puzzle successfully. 👍
I understand your approach, but in my opinion, a better option would be that the man be cut into 65 equal pieces. (I don't know if there is any way one can do that, but hey, you said that the demons are very intelligent.) Thus, no demon would die, and all of them would sleep forever. I think this can be a solution as well...
U mean , in case of 3 demons? Then - Let's consider 3 demons as A, B, and C.. A will think if he eat the person, he will fall to sleep and nothing will happen... Coz if either B or C eat A , then B or C will fall to sleep ..
But still there will be an issue; the demons are highly intelligent and greedy too. So in case of even number if a demon kills another demon the total number of demon will become odd again and then the killer can eat the sleeping demon. So at the end of the day all demons will kill each other and the village will be free of demons...😉
Hello Amaar I have a different view on this , for me this pattern can not be generalized for more than 7 demons. Let us see how but before that I must write the assumption that I have made - As your puzzle said that demons are highly and equally intelligent (definitely have different physical capabilities)and does not anywhere tell that they are not creative. So I assume that they are creative also. 2. Fear of being eaten increases progressively with increase in numbers if certain anomaly happen at some point. So it starts like this -If there is only one demon (he will surely eat the sleeping man) -If there are only two demons ( no one will definitely eat the person because other demon has 100% chance of then eating the demon 2, so group of 2 has 100% probability that they will not eat the sleeping person) - if there are only three demons( then one of the demon will definitely eat the sleeping person because of 100% group of 2 demons not to eat them) - if there are 4 demons ( no demon will eat because surety of g3 demons to then eat him) Similarly pattern follows for G5 and G6 and G7 but things started to getting interested for group of 8 demons. Now if anyone from the g8 demon eat the sleeping person then the seventh demon will not be able to eat 8th demon as confidently as it was suggested by the odd / even concept because here the concept of randomness is cleverly introduced by the 8th demon so by using this fear 8th demon can safeguard himself from being eaten(as other demon are intelligent so they will not rule out meagre 1% probability of being eaten). So why this not started from the 4th or 6th demon - for 4th demon he can not introduce such fear in the mind of 3rd demon because of 100% probability of 3rd demon not being eaten by the 2nd demon. But why not with 6 ( because simply it is more closer to 4 and then to 2 , in short it is more closer to absolute events so the concept of randomness can't be introduced.
They can overcome fear or chances or probabilites coz they're highly intelligent. That's why this postulate is mentioned that they all are highly intelligent. There is not game of fear or chance or probability. It's clear one-sided win-lose game.
I believe that you made a mistake here when you generalize between an odd and even number of demons. Only when there are exactly 2 demons, no one can eat the sleeping man. With three or more, the fastest demon can eat the man and the rest will not dare to eat the sleeping demon. No matter if the remaining number of demons is odd or even.
What about 4 demons? Demon a,b,c and d. Demon a eats the human and then there exists no reason for b to not eat a. Therefore it is not beneficial for demon a to eat the human.
Appreciate your comment.. but there is an issue with your approach. Suppose there are 4 demons, and as per your approach, one demon eats the man and falls asleep. Now there will be one sleeping being and 3 demons. Just like you said, if there are 3 demons, one will eat the sleeping being. So the sleeping demon is going to die, which invalidates the condition that the demons don't want to die.... they are intelligent, so they will do the calculation correctly. That's why with even count of demons, no one will dare to eat the sleeping man. Pls let me know if this helps.
@@LOGICALLYYOURS OK, but then we get: sleeping being is only safe when there are 2 demons left that is the case with 2 demons and 3 demons where the fastest one can eat the man 4 demons - no one touches the man because of the 3 demon situation (sleeping being can be eaten) and the first demon to eat the man will be eaten himself which they all know My point is that you generalize between odd and even number of demons. What if we have e.g. 8 demons? Where is it different from 9 demons?
If the demons can eat other demons, I expect them to fight among themselves (taking a 50% risk of losing) over a 100% risk of dying by feeding from the man. Though a demon might also hide, fooling others into thinking the odds are favorable.
Think like a demon...then 'solves' it with logic and rationale instead of trickery and lies... Are you sure you're following the 'think like a demon' rule? 😁 Thanks for the video 💖💖💖
If the demons are highly intelligent, they would realize that sleeping forever and dying are the same thing. So they would not eat anything that would make them fall asleep forever because staying alive is their highest priority. To get the result you want, you have to make them fall asleep for a finite length of time.
0:50 : read it if you are literate (They want to eat any sleeping being) Also read last point at 1:10 The riddle was very clear with all assumptions clearly stated.
The riddle specifies only that the man will sleep forever. It says demons fall asleep after eating but not that they won't wake up. Honestly not sure why they bothered to say that the man sleeps indefinitely in the first place. I don't see how the puzzle is any different if he is sleeping normally.
Why would a demon be confident enough to eat the man and not risk being eaten itself, based on whether the remaining number of demons is odd or even? "OH! If the others comprise an ODD number, they will eat me but if it is an even number, they won't!"
Great puzzle idea that's poorly presented. Solvers need to know several things at the beginning that are crucially omitted: demons don't die of hunger, demons don't fear acts of nature killing them when they're asleep (animal attacks, buildings decaying and collapsing, etc.), the "sleeping forever" idea isn't a problem, demons are not all equally fast (so that the actually can be one who beats the others to someone to eat), etc.
I have a doubt. You initially told that demon's life is highest priority. So demon knows that if it sleeps it would be eaten... So why any demon will eat the sleeping man because it knows that it would be eaten.
I think you approach of generalizing between even and odd is wrong in this problem. The demon will not eat the man only in the case of 2 demons. In the case of 4 demons, when 1 demon eat the man and falls asleep, the remaining three will not dare to eat the sleeping demon as if they eat the sleeping demon, then the then remaining can eat him. So, in the case of more than 2 demons(3,4,5,6,7,8,........), the fastest demon eat the man and falls asleep and the remaining will not eat the sleeping demon.
But after the first fastest demon sleepnesss.... the second fastest demon will think again like this and they will eat the sleeping demon..... Unless there are only 2 demons.... Because in case of 2 demons no one will eat sleeping demon/man Ps. If demons are in large number, then why a fastest demon take risk of eating..!
@@manishkumarsharma6507 Then according to you, in all the cases except case of one demon, all demons remains hungry and not eat the sleeping man. It also contradicts the solution given in this video.
You got it wrong. If one of 4 demons eats the human, the fastest of the remaining 3 will it him, cause that will only leave two demons and as you said yourself, in case of 2 demons they won't eat because they themselves will be eaten. So why would the 3 demons hesitate to eat the 4th when they know that if they do, the remaining two wont eat them?
This riddle is missing one important rule. It isn’t enough that the demons be highly intelligent. It isn’t even enough that each demon know all the other demons are highly intelligent. Each demon has to know that all demons know that all demons are highly intelligent (to infinite recursive depth). If even one demon doubts what the other demons might do, the chain is broken and he can’t eat safely.
If demons are odd then also, each demon will think that he has to remain alive just like in even case. So in odd also Nothing will happen in the village and hence no one will eat the sleeping man.. I think I am right. Actually I don't understand your approach, that in odd case how can you assume that demon will not be eaten by another demon just like in case of even no. Of demons
I realize it's out of the context of the riddle, but if these demons are intelligent they'll figure out there's no-to-little food here, and leave since there's nothing keeping them in the village.
My solution was a bit different and while it has flaws the outcome is more or less the same. Basically, a demon can move the sleeping human to a place where no one can find it and then eat it and fall asleep. This way, only one demons falls asleep, the rest remain hungry and sleep deprived )) My solution is not clean by any means, but whatever.
I didn't consider nothing happening as an option because I thought they were all out to find some way to eat and not die. I was trying to think how they could do this. Maybe I thought too much into it.
I do not understand how odd number and even number fit in this puzzle. After all any demon who eats the sleeping man stands the risk of being eaten and since staying alive is the highest priority then the final result is the man remains asleep and no demon touches him.
Nice video!! Btw can you code, it would be really awesome if you could put a coding solution there... Anyways I'm still a student But with ur explanation I can code mist of ur problems... and I'd like to volunteer and give solutions1
if one demon can eat another demon after eating the sleeping man, then why not the demons eating themselves prior to eating the sleeping man? in this case , there might be 1 demon left and he then eat the sleeping man and sleep himself without tension...
*paused the video at 1:30. my answer: the way i see it. if there are an ode number of demons the man will be eaten and if even then the man will not be eaten. so he will be eaten and 64 demons will stay hungry
Lol !!! dont agree with the solution at all. 3 key things here are 1) it does not mention that if the demon eat the sleeping man it will fall asleep FOREVER 2) there is no mention if the demon can always find a sleeping man or sleeping demon 3) it does not mention that the demon can't leave the village . Therefore, if they can't find the sleeping man nothing happened. If one demon find a sleeping man. He will try to find the spot that not it unlikely for other demon to find. If the time for all demon to search through all the spot very long and it will much longer than the time the demon fall to sleep. He can take a calculated risked to eat the man. Since it is a calculated risk, there is a chance he will be found. However the next demon will have greater chance to live since there is less demon to do the search he will decide to eat the sleeping demon after finding a good spot to hide. Anyways, the result can be everything 1) nothing change 2) man and one demon die 3) man and two demon die etc.
The 1st point you've mentioned is actually mentioned in the video if u watch carefully.... And this is just a mathematical logcial question not a real life situation. You're raising points like it's an open world game lol. Chill out man
Why is that in case of even demons , one of them would not eat the person and why in odd case it would eat. And if there is a possibility of demon to choose to be in hunger permanently, then the initial info is insufficient and misguiding.
Yeah good but why not eating a demon who has eaten the human but a demon who had fallen asleep or just kill one an eat it.If you are creative you cam find solution.Btw i want comments on this beacuse I wana know your oppinion,beacuse maybe I am wrong.
There are only 2 cases where you can think out of the box: - It's stated in riddle to think out of the box - there is no possible answers within the stated assumptions. In this riddle, it's neither of case. Answer is possible within the box.
This is clearly wrong. In any case other than one demon, some demon will be on the chopping block so no demons eat and it will stop. Odd and even only matters IF it reduces to the case with one or two demons. But this problem does not reduce like that. Why will I ever eat if I am vulnerable?
You know you're vulnerable but you also know that all other demons and your too are highly and equally intelligent. That's why you all will do these calculations and will know what's gonna happen at the very end of eating one-another chain. Then only you'll take any step forward
Kabi lame: lets share the sleeping man among all the 65 demons after that they all being asleep.
Sharing is caring😜
Simple bro✌
😂😂same thought
I also thought the same reason
😂😂yeah why complicate things when solutions are simple..
Wrong . If you share the man who will be the one do the first bite ? remember if you the last one to sleep you can eat all
I wasn't able to solve it. So I decided to watch solution.
But then he told this : 1:40 (similar to 5 pirates and treasure).
I again paused the video and solved the puzzle successfully. 👍
Awesome riddle! It might help to know, however, that the demons cannot die of hunger.
Exactly
Ye baat to batayi hi nahi
I understand your approach, but in my opinion, a better option would be that the man be cut into 65 equal pieces. (I don't know if there is any way one can do that, but hey, you said that the demons are very intelligent.) Thus, no demon would die, and all of them would sleep forever. I think this can be a solution as well...
Trivial solution 😀
Very clever indeed.
That can't be a solution because demon can only eat either sleeping (man or demon ) not the dead one..
@@KMSAPNA-zh1tp it means, demons can share the sleeping man !!
I think the same they can start eating at the same time and in equal amount 🤓
Good logic... but as time passes by, hunger will be high priority than dying in sleeping...😇😆
2:37
Think from the perspective of a demon ... 😀
I really tried, Ammar.
I ate my girlfriend...
I felt that
👏👏nice puzzle
02:48
In A Demons Case.
Why demon 1 eats the man?
It is equally possible that no demons going to eat that man.
U mean , in case of 3 demons?
Then - Let's consider 3 demons as A, B, and C..
A will think if he eat the person, he will fall to sleep and nothing will happen... Coz if either B or C eat A , then B or C will fall to sleep ..
Cracked this question
Without seeing solution ✊✊
This is a fantastic puzzle.Great explanation and excellent graphics. Gopu Natarajan
But still there will be an issue; the demons are highly intelligent and greedy too. So in case of even number if a demon kills another demon the total number of demon will become odd again and then the killer can eat the sleeping demon. So at the end of the day all demons will kill each other and the village will be free of demons...😉
But demons are immortal
No demon wants to die!
@@pramodrk15 Demons are possessed humans, nothing else! Ghosts are immortal!
Hello Amaar I have a different view on this , for me this pattern can not be generalized for more than 7 demons. Let us see how but before that I must write the assumption that I have made -
As your puzzle said that demons are highly and equally intelligent (definitely have different physical capabilities)and does not anywhere
tell that they are not creative. So I assume that they are creative also.
2. Fear of being eaten increases progressively with increase in numbers if certain anomaly happen at some point.
So it starts like this
-If there is only one demon (he will surely eat the sleeping man)
-If there are only two demons ( no one will definitely eat the person because other demon has 100% chance of then eating the demon 2, so group of 2 has 100% probability that they will not eat the sleeping person)
- if there are only three demons( then one of the demon will definitely eat the sleeping person because of 100% group of 2 demons not to eat them)
- if there are 4 demons ( no demon will eat because surety of g3 demons to then eat him)
Similarly pattern follows for G5 and G6 and G7 but things started to getting interested for group of 8 demons.
Now if anyone from the g8 demon eat the sleeping person then the seventh demon will not be able to eat 8th demon as confidently as it was suggested by the odd / even concept because here the concept of randomness is cleverly introduced by the 8th demon so by using this fear 8th demon can safeguard himself from being eaten(as other demon are intelligent so they will not rule out meagre 1% probability of being eaten).
So why this not started from the 4th or 6th demon
- for 4th demon he can not introduce such fear in the mind of 3rd demon because of 100% probability of 3rd demon not being eaten by the 2nd demon.
But why not with 6 ( because simply it is more closer to 4 and then to 2 , in short it is more closer to absolute events so the concept of randomness can't be introduced.
They can overcome fear or chances or probabilites coz they're highly intelligent. That's why this postulate is mentioned that they all are highly intelligent. There is not game of fear or chance or probability. It's clear one-sided win-lose game.
I like this approach.
I believe that you made a mistake here when you generalize between an odd and even number of demons.
Only when there are exactly 2 demons, no one can eat the sleeping man. With three or more, the fastest demon can eat the man and the rest will not dare to eat the sleeping demon. No matter if the remaining number of demons is odd or even.
What about 4 demons? Demon a,b,c and d. Demon a eats the human and then there exists no reason for b to not eat a. Therefore it is not beneficial for demon a to eat the human.
Appreciate your comment.. but there is an issue with your approach.
Suppose there are 4 demons, and as per your approach, one demon eats the man and falls asleep. Now there will be one sleeping being and 3 demons.
Just like you said, if there are 3 demons, one will eat the sleeping being. So the sleeping demon is going to die, which invalidates the condition that the demons don't want to die.... they are intelligent, so they will do the calculation correctly.
That's why with even count of demons, no one will dare to eat the sleeping man.
Pls let me know if this helps.
@@LOGICALLYYOURS OK, but then we get:
sleeping being is only safe when there are 2 demons left
that is the case with 2 demons and 3 demons where the fastest one can eat the man
4 demons - no one touches the man because of the 3 demon situation (sleeping being can be eaten) and the first demon to eat the man will be eaten himself which they all know
My point is that you generalize between odd and even number of demons. What if we have e.g. 8 demons? Where is it different from 9 demons?
@@cibercafe3052 You can generalise the approach from 5 demons to 8 or 9 demons just like he did in the video.
I am with you. We cannot generalize between even and odd. The demon will not eat the man only in the case of 2 demons.
If the demons can eat other demons, I expect them to fight among themselves (taking a 50% risk of losing) over a 100% risk of dying by feeding from the man.
Though a demon might also hide, fooling others into thinking the odds are favorable.
Think like a demon...then 'solves' it with logic and rationale instead of trickery and lies... Are you sure you're following the 'think like a demon' rule? 😁
Thanks for the video 💖💖💖
Finally got your lovely comment... :) thanks Jessica
I was able to solve this easily since I had already seen the Pirates puzzle before ..
Same logic...
Interesting! Thanks for sharing!
Alttough I cannot really get the difference between dying and sleeping forever, that is still a very beatiful riddle.
If the demons are highly intelligent, they would realize that sleeping forever and dying are the same thing. So they would not eat anything that would make them fall asleep forever because staying alive is their highest priority.
To get the result you want, you have to make them fall asleep for a finite length of time.
0:50 : read it if you are literate
(They want to eat any sleeping being)
Also read last point at 1:10
The riddle was very clear with all assumptions clearly stated.
@@manusarda Too bad you are not highly intelligent like the hypothetical demons.
The riddle specifies only that the man will sleep forever. It says demons fall asleep after eating but not that they won't wake up.
Honestly not sure why they bothered to say that the man sleeps indefinitely in the first place. I don't see how the puzzle is any different if he is sleeping normally.
Assalamu Alaikum Wa Rahmatullah.... You're really awesome!! Thanks for sharing ❤❤🌿🌿
Never miss your riddles love from Gujarat ❤️
I like the video first and then watch.. Awesome channel!! 😀
Excellent explanation 👍
Why would a demon be confident enough to eat the man and not risk being eaten itself, based on whether the remaining number of demons is odd or even? "OH! If the others comprise an ODD number, they will eat me but if it is an even number, they won't!"
Great puzzle idea that's poorly presented. Solvers need to know several things at the beginning that are crucially omitted: demons don't die of hunger, demons don't fear acts of nature killing them when they're asleep (animal attacks, buildings decaying and collapsing, etc.), the "sleeping forever" idea isn't a problem, demons are not all equally fast (so that the actually can be one who beats the others to someone to eat), etc.
If I were a Demon, I would have changed the village allready
I wish I be a genius😪
I think you should have added that when multiple demons want to eat the man at the same time, the fastest/an arbitrary demon gets to eat the man.
I was gonna say that lol
ShAriNg iS cArIng
But he mentioned it multiple times that the fastest gets the man. Did you even listen?
I considered the solution as my first guess but thought it's too easy and he says it's a hard riddle lmao!
please keep wirte details in descriptions because i have some diffecult to understand audio english
I have a doubt. You initially told that demon's life is highest priority. So demon knows that if it sleeps it would be eaten... So why any demon will eat the sleeping man because it knows that it would be eaten.
Demon will know that he'll not get eaten by all these calculations. That's why he'll eat the man.
Very Intriguing... Amazing ❤️
Easy puzzle... Great explanation... Amazing animations🤩
I was thinking that demons would cut the man in 65 pieces and each demon would eat 1 piece, but that would be gruesome.
I thought the same, in this way no demon will die and everyone's hunger will be satisfied.
@@mbvkgp maybe 1/65th part of human will not satisfy their hunger 😅
I think you approach of generalizing between even and odd is wrong in this problem.
The demon will not eat the man only in the case of 2 demons.
In the case of 4 demons, when 1 demon eat the man and falls asleep, the remaining three will not dare to eat the sleeping demon as if they eat the sleeping demon, then the then remaining can eat him.
So, in the case of more than 2 demons(3,4,5,6,7,8,........), the fastest demon eat the man and falls asleep and the remaining will not eat the sleeping demon.
But after the first fastest demon sleepnesss....
the second fastest demon will think again like this and they will eat the sleeping demon..... Unless there are only 2 demons....
Because in case of 2 demons no one will eat sleeping demon/man
Ps. If demons are in large number, then why a fastest demon take risk of eating..!
@@manishkumarsharma6507 Then according to you, in all the cases except case of one demon, all demons remains hungry and not eat the sleeping man. It also contradicts the solution given in this video.
You got it wrong. If one of 4 demons eats the human, the fastest of the remaining 3 will it him, cause that will only leave two demons and as you said yourself, in case of 2 demons they won't eat because they themselves will be eaten. So why would the 3 demons hesitate to eat the 4th when they know that if they do, the remaining two wont eat them?
This riddle is missing one important rule. It isn’t enough that the demons be highly intelligent. It isn’t even enough that each demon know all the other demons are highly intelligent. Each demon has to know that all demons know that all demons are highly intelligent (to infinite recursive depth). If even one demon doubts what the other demons might do, the chain is broken and he can’t eat safely.
If demons are odd then also, each demon will think that he has to remain alive just like in even case. So in odd also Nothing will happen in the village and hence no one will eat the sleeping man..
I think I am right. Actually I don't understand your approach, that
in odd case how can you assume that demon will not be eaten by another demon just like in case of even no. Of demons
I realize it's out of the context of the riddle, but if these demons are intelligent they'll figure out there's no-to-little food here, and leave since there's nothing keeping them in the village.
Well there is something to keep them in village.
Apni mitti. 🙏
@@manusarda Maybe nope. Apni mitti usually won't apply if you find a waaay better place to live peacefully.
@@BrainPermaDeD it depends on person to person.
It actually doesn't make sense of if its even or odd one eats the human but the in the other case they dont eat the human.
My solution was a bit different and while it has flaws the outcome is more or less the same. Basically, a demon can move the sleeping human to a place where no one can find it and then eat it and fall asleep. This way, only one demons falls asleep, the rest remain hungry and sleep deprived )) My solution is not clean by any means, but whatever.
I didn't consider nothing happening as an option because I thought they were all out to find some way to eat and not die. I was trying to think how they could do this. Maybe I thought too much into it.
What is the name text-style/font-family you have used here ?? I liked it so ,much pls tell me
Love from srilanka
Nice riddle
Very nice riddle
👌👌👌
As always it was a great riddle.
But not all viewers are as intelligent as demon.
As always they are unable to understand the answer.
I do not understand how odd number and even number fit in this puzzle. After all any demon who eats the sleeping man stands the risk of being eaten and since staying alive is the highest priority then the final result is the man remains asleep and no demon touches him.
Nice video!!
Btw can you code, it would be really awesome if you could put a coding solution there...
Anyways I'm still a student
But with ur explanation I can code mist of ur problems... and I'd like to volunteer and give solutions1
Demon's can't eat sleeping man . But can eat after killing human .
Two trains are in same track going in opposite direction and you don't have any red colour sign flag how do you stop it
Both trains are going in opposite direction( far from each other)
if one demon can eat another demon after eating the sleeping man, then why not the demons eating themselves prior to eating the sleeping man? in this case , there might be 1 demon left and he then eat the sleeping man and sleep himself without tension...
Coz Demons aren't dumb
Why is the man sleeping
.
.
.
OUTSIDE the house.
Got in feud with his wife
0.40
cannot be eaten by another demon
Bro can u explain how 3 people can share 2 apples without cutting them and each person must get an apple
*paused the video at 1:30.
my answer:
the way i see it.
if there are an ode number of demons the man will be eaten and if even then the man will not be eaten.
so he will be eaten and 64 demons will stay hungry
nice one past self..
Nice one
Who disliked this video 😠
Great 👏 👏
I appreciate ur effort, I saw all ur vedios this vedio u didn't have any confident in saying
Video*
@@ashaparekh5898 what
It doesn't say demons would die of hunger.
Wonderful
So those demons will starve to death?
Lol !!! dont agree with the solution at all. 3 key things here are 1) it does not mention that if the demon eat the sleeping man it will fall asleep FOREVER 2) there is no mention if the demon can always find a sleeping man or sleeping demon 3) it does not mention that the demon can't leave the village . Therefore, if they can't find the sleeping man nothing happened. If one demon find a sleeping man. He will try to find the spot that not it unlikely for other demon to find. If the time for all demon to search through all the spot very long and it will much longer than the time the demon fall to sleep. He can take a calculated risked to eat the man. Since it is a calculated risk, there is a chance he will be found. However the next demon will have greater chance to live since there is less demon to do the search he will decide to eat the sleeping demon after finding a good spot to hide. Anyways, the result can be everything 1) nothing change 2) man and one demon die 3) man and two demon die etc.
The 1st point you've mentioned is actually mentioned in the video if u watch carefully.... And this is just a mathematical logcial question not a real life situation. You're raising points like it's an open world game lol. Chill out man
Smart demons😈
That man and Demons won't die of hunger?
So its not that who ever will act first will be safe ..
First comment
Why is that in case of even demons , one of them would not eat the person and why in odd case it would eat. And if there is a possibility of demon to choose to be in hunger permanently, then the initial info is insufficient and misguiding.
I think I applied for the wrong job. Why does this doorknob not work?
Man will survive i guess
The demons will all start fasting
awesome
Yeah good but why not eating a demon who has eaten the human but a demon who had fallen asleep or just kill one an eat it.If you are creative you cam find solution.Btw i want comments on this beacuse I wana know your oppinion,beacuse maybe I am wrong.
There are only 2 cases where you can think out of the box:
- It's stated in riddle to think out of the box
- there is no possible answers within the stated assumptions.
In this riddle, it's neither of case.
Answer is possible within the box.
I think you have taken lot of implicit assumptions that have lead to odd/even cases
But this pattern will keep on going
10th❤️
This is clearly wrong. In any case other than one demon, some demon will be on the chopping block so no demons eat and it will stop. Odd and even only matters IF it reduces to the case with one or two demons. But this problem does not reduce like that. Why will I ever eat if I am vulnerable?
You know you're vulnerable but you also know that all other demons and your too are highly and equally intelligent. That's why you all will do these calculations and will know what's gonna happen at the very end of eating one-another chain. Then only you'll take any step forward
Asleep or dead whats the difference.
When they're being eaten , they'll get awake lol
Wow
Agastya Chauhan is dead...don't overspead guys!!
Kuch bhi... Jab odd honge to demon nahi sochega kya ki baake ke usko kha gaye to...fir us case me bhi nothing will happen in the village
Ofd hoga to use pta hoga baki demons nhi khaenge use , so he'll eat the man
Chutiyapa phailane ki ninja technique
Please upload a video of what is the minimum number of knights required to cover whole chessboard
4th
2nd
And they will die because of hunger gg
I solved it in 30 seconds!
Generalise, not 'generalize'.
Awwww
It is equally possible that no demons going to eat that man....
Your answer is wrong and it's about probablity.......
This puzzle is wrong
Why are you unable to prove that's it's "equally possible" that no demon will eat the man ? And just said that puzzle is wrong ? Pathetic boy !
Wring argument, wrong conclusion
There is no logic in your solution.. I Totally disagree.
There is Logic. Can u tell why there isn't logic acc to u ?
that dosent seems logical
Totally Logical
this doesn't make sense sorry
It totally does man. It's a mathematical logcial question. Not a real life .
Excellent