Motion up an inclined plane with friction

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  • Опубліковано 1 жов 2024
  • In this video, we identify all the forces (or their components) acting on a block being moved up an inclined plane. And, using equilibrium of these forces, get an equation for acceleration of the block.

КОМЕНТАРІ • 8

  • @SurenderKumar-he7ul
    @SurenderKumar-he7ul 6 років тому +3

    Sir you are awesome plz upload as much as you can...

    • @ssjagtap66
      @ssjagtap66  5 років тому +2

      Thank you for watching :-)

  • @akashkunal8774
    @akashkunal8774 5 років тому

    If a weight of an object is w and alpha is angle of inclined plane and phi will be angle of friction then force required to drag will be when it is just impending is equal to

  • @christianjourneytv1003
    @christianjourneytv1003 4 роки тому

    Is it always constant that the force that will take an object up the incline plane will be at angle theta, then I'll have to resolve to the horizontal. Or is it that what your considering is another case of the force taking an object upwards?

  • @christianjourneytv1003
    @christianjourneytv1003 4 роки тому

    You solution is what I've been looking out for. I will subscribe.
    What software do you use Sir?

  • @madhusingh-fq2gd
    @madhusingh-fq2gd 5 років тому

    I think there's a bit of mistake at the specification of components for mg at starting.How can one make angle of inclined= angle bw the mg component.It should be (90- angle of inclination) bw components of mg by construction.

    • @ssjagtap66
      @ssjagtap66  5 років тому

      madhu singh , that can be proved using similarity of triangles. Can mail you the proof if you share your email address.

  • @wongsuper1
    @wongsuper1 4 роки тому

    sir thank you so much the world needs more people like you