NET FORCE - Inclined Planes Practice Problems

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  • Опубліковано 19 лис 2024

КОМЕНТАРІ • 58

  • @robxnguyen
    @robxnguyen 7 років тому +17

    I know that he messed up with the 9800, but imo he did a better job than my professor LOL. Nice video man.

  • @Stvrfiire_
    @Stvrfiire_ 7 місяців тому

    Sir please keep making physic 20 videos. I’ve watched over 100 teachers on this app, but NOBODY has ever helped me so much, I’m literally gonna cry, thank you

  • @blade913
    @blade913 7 років тому +1

    Thank you so much for the help...I've been having so many problems with people being unable to properly label, or keep things simple and with as little diagrams as possible. I've seen people draw up to 4 triangle on that type of diagram, and can't word anything into a comprehensible thought. I was able to grasp this, which I was sure I was just not bridging some simple piece of information, and you helped! Thanks again!

  • @nickl.9856
    @nickl.9856 10 років тому +16

    Yeah, like a couple people here have already said, he was off by 1 decimal point (he had 98,000 when he should have had 9,800); so he was almost right, just divide all his numbers by 10. :-)

  • @Kayla-dr5hv
    @Kayla-dr5hv 10 років тому +14

    Brilliant, thank you so much! Simple and easy to understand.

    • @sciencepost
      @sciencepost  10 років тому +2

      Kayla de Beer Got to keep it simple. Thanks for the good vibes!

  • @tashajones4299
    @tashajones4299 11 років тому +3

    Static and Kinetic are types of friction. Static means that an object is stationary, or not moving. Kinetic refers to moving objects, but only if they have a constant speed. Hope this helps!

  • @Cobba7
    @Cobba7 9 років тому +5

    The mg value should be a positive value... correct me if I'm wrong... and the friction value should be negative.

  • @noahlegge411
    @noahlegge411 8 років тому +49

    9800N........ Not 98000😂

    • @deesse4531
      @deesse4531 6 років тому

      I even try it to my calcu... HAHAHA

  • @ayubjulany3824
    @ayubjulany3824 7 років тому +2

    being at rest doesn't mean that the forces sum is zero. it means that the velocity is zero, not the forces. when the acceleration is zero, that means that the sum of forces is zero. right? it could be at rest, but have forces acting on it and accelerating...

  • @InclinedWerld
    @InclinedWerld 11 років тому +2

    I'm so happy right now.

  • @hornedlobster
    @hornedlobster 10 років тому +2

    THANK YOU! i needed this video!

  • @apalmer12
    @apalmer12 10 років тому +1

    You're the BEST!

    • @sciencepost
      @sciencepost  10 років тому

      apalmer12 You are too kind! Best wishes learning!

  • @sharonli3076
    @sharonli3076 9 років тому +1

    Helped me a lot. Thanks!

  • @jalalahmadfarooka7543
    @jalalahmadfarooka7543 7 років тому +5

    how can weight be 98000 N when w=mg makes it (1000)(9.8)=9800N

  • @KarimLaaiadiVlogs
    @KarimLaaiadiVlogs 11 років тому +1

    If we need to figure out the acceleration , do we have to add up all forces or use F II or F parallel ??? thanks

  • @lala-qr4mh
    @lala-qr4mh 3 роки тому

    Thank you so much this really really helped!!

  • @sarahgo7811
    @sarahgo7811 11 років тому +10

    i hink it should be 9800??

  • @RocksmithPdl
    @RocksmithPdl 8 років тому +1

    Nice and clear 👍🏼

  • @guzmanxp4906
    @guzmanxp4906 7 років тому

    You are the best!

  • @1ultimate100
    @1ultimate100 10 років тому +17

    its wrong, 9.8 x 1000 = 9800 not -98,000 lol.

    • @vissvaalan7535
      @vissvaalan7535 10 років тому

      you are wrong lol.. you gotta convert the kg to N first then multiply..

    • @phasmafortis1926
      @phasmafortis1926 10 років тому +9

      ***** nope, it should be 9,800. kg times m*s^-2 equals N.

  • @suneethapurli3722
    @suneethapurli3722 10 років тому +7

    Isn't 9.8 multiplied with 1000 , 9800

  • @siddhantrahulpatil
    @siddhantrahulpatil 3 роки тому

    Thanks!

  • @tosonaldam-tajima1936
    @tosonaldam-tajima1936 3 роки тому +2

    wow all these comments are so old. i wonder where everyone is now

    • @siddhantrahulpatil
      @siddhantrahulpatil 3 роки тому

      Still here :) I have a test on this tomorrow, how about you?

  • @lesmayjacobs5468
    @lesmayjacobs5468 3 роки тому

    Thank you

  • @19jewels95
    @19jewels95 8 років тому +1

    THANK YOU

  • @adeosunbhimbie4105
    @adeosunbhimbie4105 8 років тому +1

    thanks man

  • @niccatipay
    @niccatipay 10 років тому +3

    Many of my brain cells died...
    Nuff said

  • @alanzollner3381
    @alanzollner3381 5 років тому

    Fg calculation aside, nice job explaining the components and friction force, but the value you found for the coefficient of static friction would only be correct if the object was just on the brink of sliding, or if you found the kinetic coefficient of friction if the object was sliding at a constant velocity. Recall that for static friction, the friction force is written as an inequality: Ff

  • @patrickmole9645
    @patrickmole9645 7 років тому

    thank you sir

  • @arifhakiminadnan4880
    @arifhakiminadnan4880 9 років тому +1

    thanks

  • @makabongwemdluli3907
    @makabongwemdluli3907 10 років тому +1

    thanks a lot this video was helpful

    • @sciencepost
      @sciencepost  10 років тому

      That is awesome to hear. Best wishes in learning.

  • @hamiltonmabep441
    @hamiltonmabep441 3 місяці тому

    Is it static friction?

  • @dlfinnan911
    @dlfinnan911 10 років тому +1

    no he is right you don't convert kg to n mg is equal to mass times force of gravity....units of mass are in kg and force of gravity is in N....then you multiply them together and get 9800 NOT 98000 1000*9.8 is NOT 98000

  • @Music-lv8xf
    @Music-lv8xf 11 років тому

    hi sir i am confused. is friction , kinetic friction , static friction are different from each other?? if the question asking only for friction then if i have the parallel F that is equal to friction right? that is what you said but what if the question is asking for kinetic friction do i need to use the formula coefficient of kinetic friction multiply to FN?

    • @hamiltonmabep441
      @hamiltonmabep441 3 місяці тому

      When the object slides down I think it would experience Kinetic friction. It's resting so thus it should be static friction

  • @keithenaficionadobrown4853
    @keithenaficionadobrown4853 10 років тому +1

    9,800×sin(15)
    =2,536.42664198

  • @anjusaraswat9584
    @anjusaraswat9584 6 років тому

    Koi bat nhi error to god sebhi ho jati hai but sir thnks

  • @snowpro5ryusmc
    @snowpro5ryusmc 9 років тому +1

    OMG! It is 9,800, not 98,000!

  • @amhaaygoda7142
    @amhaaygoda7142 7 років тому

    you asked for the value of fiction not for the value of coefficient of friction.

  • @huwsamuel6227
    @huwsamuel6227 11 років тому

    Yep he dropped a decimal point folks , shouldn,t happen

  • @treeky3
    @treeky3 11 років тому

    1000*9.8=9,800

  • @kiruuthayanan4910
    @kiruuthayanan4910 3 роки тому

    9810 i swear its 9.81

  • @lucasondo3603
    @lucasondo3603 8 років тому +1

    hey why g= - 9,8 ???? it must be g = 9,8

    • @mzain325
      @mzain325 8 років тому +1

      +Lucas Ondo its minus because gravity is acting downwards.

  • @barcorn6991
    @barcorn6991 5 років тому

    I THINK IT IS 9810 N

  • @tabaicanking3701
    @tabaicanking3701 6 років тому

    kkkkkkk

  • @Gorguduck
    @Gorguduck 2 роки тому

    The reason why he put 98000N instead of 9800 is because the 1000 is in kg, not N, to convert kg to N the 1000 must be multiplied by 10. So the calculation not shown is 1000 x 10 = 10000 x (-9.8) = -98000 N