Calculation of Rich Methane - Air equilibrium composition

[@danishaman291]

Kindly upload all your lectures. Very helpful to understand. Jazak Allah.

[@Dr.Awad_Alquaity]

Thanks @danishamam! Wa iyyakum, I will try to upload more in the coming months in sha Allah

[@danishaman291]

@@Dr.Awad_Alquaity Many Thanks

[@danishaman291]

Aoa. Why there is CO in the product although the mixture of CH4 is rich? & how to decrease its quantity in the product?

[@danishaman291]

Now i understand if we increawe the 02 then there will complete combustion..

[@Dr.Awad_Alquaity]

@@danishaman291 : Walaikumsalam Danish. CO is always in the product side due to incomplete combustion. In reality, we never have complete combustion but we only approach complete combustion in some cases which means that CO will still be there but in small amounts. For a rich flame, there is not enough oxygen for all the carbon to form CO2 so some of it ends up as CO. In other cases where there is enough oxygen, we still get CO because of dissociation of CO2 into CO and O2 at high temperatures