Look I’m not going to lie I sat down in class and nearly screamed because this confused me so much but literally watching this video made it click to me. I swear your a genius and your videos are very descriptive. Please continue to make more chemistry videos and help educate the confused
Yall I been in love with this man. An ywaays I'm here cuz I ain't do no type of chemistry during this learning thing and I got like 3 more days before final days so.
Thanks for the vid! This helped me a lot during the quarantine because I learn through interaction with other people and seeing examples, but my chem teacher gave us a PowerPoint and a worksheet, so I was really confused. Thanks again!
Professor Organic Chemistry Tutor, thank you for a Graphical and Analytical explanation of Solubility Curves in AP/General Chemistry. Solving practice problems using graphical tools /methods is an excellent way to visualize and understand the material. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
Y’all need to like up the video cause outta 150k views, only 2.1k of y’all found it helpful? I know some of y’all would be failing hard rn without these vids 💀💀
Hi, with Q7 (d), I multiplied the solubility of 50 g of KNO3 in 100 mL at 30 degrees C, by 0.25 (1/4) in order to get it to the same value of Volume. This resulted in a solubility of 12.5 g in 25 mL. This meant that given that the Conc. of 15 g of KNO3 in 25 mL was greater than (>) the solubility of 12.5 g of KNO3 in 25 mL. Thus C > S, therefore arriving at the same answer of super saturated. Now given that in the video you calculated to make both conc. and solubility in terms of 100 mL, which makes finding the answer on the solubility curve more of a possiblity. I am wondering if my method is acceptable if I was simply comparing conc. to solubility and not looking at the solubility curve? Thank you, Papa
For the last question, u found the answer for per 200mL. Would the answer still be correct if I calculated for per 100mL, with respect to the graph? So like u got 125g per 200mL I got 62.5g per 100mL. Your question did not specify in what quantity of mass the answer was required for.
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information and how to apply.
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information on how to apply,which course to study,name of the school and other vital information, I am waiting to hearing from you,Thank you sir and may GOD strengthen you.
At 2:29, he did 100 divided by 40, which is equal to 2.5. Kind of like fractions, he then proceeded to do 250 divided by 2.5 which is equal to 100. It was just a way of finding x.. Another way you could have done it is proportionally: You do 250 times 40, which is equal to 10,000.. Then you can do 10,000 divided by 100. Basically you multiply, then divide. 250 times 40 divided by 100 is 100. I'm not a math expert, but I hope this helped
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information on how to apply,which course to study,name of the school and other vital information, I am waiting to hearing from you,Thank you sir and may GOD strengthen you.
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information and how to apply.
Concentration Formula Sheet: bit.ly/3YfzBTf
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Next Video: ua-cam.com/video/74Y6UMsEZ3s/v-deo.html
Look I’m not going to lie I sat down in class and nearly screamed because this confused me so much but literally watching this video made it click to me. I swear your a genius and your videos are very descriptive. Please continue to make more chemistry videos and help educate the confused
The way you say "water", "forty", an "volume" gives me life.
Fowdy
🤣
i realize Im kinda randomly asking but does anybody know of a good place to stream new tv shows online?
@@vanmartin2013 Besides Netflix and Hulu idk.
😂😂
Why on earth, would anyone dislike this guy's UA-cam videos? They are cutting edge, revolutionary, the best there is. 💔
Envious teachers
fr, his explanation is on point plus my native language isn't even english and I understand every single thing from this video
i hope u live a good life
Yall I been in love with this man. An ywaays I'm here cuz I ain't do no type of chemistry during this learning thing and I got like 3 more days before final days so.
Thanks for the vid! This helped me a lot during the quarantine because I learn through interaction with other people and seeing examples, but my chem teacher gave us a PowerPoint and a worksheet, so I was really confused. Thanks again!
Professor Organic Chemistry Tutor, thank you for a Graphical and Analytical explanation of Solubility Curves in AP/General Chemistry. Solving practice problems using graphical tools /methods is an excellent way to visualize and understand the material. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
Pretty underrated tbh. Thanks for the video.
How much can I thank you..
God is your eternal reward!
Thank you so much! im in 9th grade and i just started high school and have been getting straight A's thanks too you :D!
Thanks to you I passed this on my exam🤗
Y’all need to like up the video cause outta 150k views, only 2.1k of y’all found it helpful? I know some of y’all would be failing hard rn without these vids 💀💀
Like it up🗣🤡
THANKS FOR THE EXPLANATION. My chemistry teacher left the school without teaching us this and we have examinations thanks again
Thanks for the lecture. It was quite interesting and easy to understand graphically. However, I want to also confirm if the answer can be 62.5g/100ml.
at 15.43 , I think we don't have a supersaturated solution .we have a solution with undissolved particles thanks for video btw.
Thanks dude i pased my alevel exam thanks to you❤
I apreciate these videos i was confused now I understand it now clearly thank u :0
(Well is becuz my teacher didn't teach us this lol)
tysm for the vid, it helped a lot :)
Ngl these channels are saving my grades
Hi, with Q7 (d), I multiplied the solubility of 50 g of KNO3 in 100 mL at 30 degrees C, by 0.25 (1/4) in order to get it to the same value of Volume. This resulted in a solubility of 12.5 g in 25 mL. This meant that given that the Conc. of 15 g of KNO3 in 25 mL was greater than (>) the solubility of 12.5 g of KNO3 in 25 mL. Thus C > S, therefore arriving at the same answer of super saturated. Now given that in the video you calculated to make both conc. and solubility in terms of 100 mL, which makes finding the answer on the solubility curve more of a possiblity.
I am wondering if my method is acceptable if I was simply comparing conc. to solubility and not looking at the solubility curve?
Thank you,
Papa
Papa Amponn-Nyamekye I was honestly thinking the same thing
I got an 39 on a quiz about this and I’m about to take a test. thank for making this video
how did it go
@@graysonschnellhardt835 got a 83
THANK YOU SOO MUCH YOUR ABSOLUTELY AMAZING 🤩😊❤
Thank you very much for this...
THANK YOU SO MUCH I HATE ONLINE SCHOOL IDGAF IM going back to public school caps*
I LOVE U,, IM GONNA PASS NOW BC OF U
ilysm thank u good sir
For the last question, u found the answer for per 200mL. Would the answer still be correct if I calculated for per 100mL, with respect to the graph? So like u got 125g per 200mL I got 62.5g per 100mL. Your question did not specify in what quantity of mass the answer was required for.
SIR I LOVE YOU THANK U SO FUCKING MUCH
Can somebody tell me Ce2SO4 have the less S. ?
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information and how to apply.
When u make a proportion do u always put 100 mL on the right side numerator ?
God bless you sir,amen. how can I apply
for question 6 where did u get the 100 mL from?
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information on how to apply,which course to study,name of the school and other vital information, I am waiting to hearing from you,Thank you sir and may GOD strengthen you.
Thank u ☺️ 🙏
I really love you so much
Solubility and Solubility Curves
ua-cam.com/video/7H93tvD0lkM/v-deo.html
Ha the rescue before exam
i don't get the 3 question where is the 2.5 ? and how did you get that please help 😭
At 2:29, he did 100 divided by 40, which is equal to 2.5. Kind of like fractions, he then proceeded to do 250 divided by 2.5 which is equal to 100. It was just a way of finding x.. Another way you could have done it is proportionally: You do 250 times 40, which is equal to 10,000.. Then you can do 10,000 divided by 100. Basically you multiply, then divide. 250 times 40 divided by 100 is 100. I'm not a math expert, but I hope this helped
Hi
THANK YOUUUUUU
Kon kon india se ha😂
very cool
Yo, thanks man
8:35
The good thing, kids, is that you can grow up to be Physicists instead... this Chemistry is just a class to punish 9th graders.
Thanks
God bless you
myStar
I didn’t understand some part!!!!!!!!!!!!!!!!!!
get a new mic
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information on how to apply,which course to study,name of the school and other vital information, I am waiting to hearing from you,Thank you sir and may GOD strengthen you.
Hell sir, my name is Victor, i am a student in Nigeria. I graduated as an SS3 student in Bammy international school, I have being waiting for months. Sir,i need information and how to apply.
When did u graduate last year