Thank you SO MUCH for he whole walkthrough. I am currently failing my class and we have a second chance to bump our grade on the upcoming midterm. Understanding the step by step and the formulas that can be used to find the answers is amazing. Thank you! will continue to look at the next videos!
I'm very glad you found the information useful! If you want to find example problems, search for 'MET 320 9' on my channel. This will find all the videos from chapter 9 of the textbook I use for my course, number MET 320. That chapter is all about gas power cycles, and I always cover the ideal Otto, Diesel, Sterling, Brayton (with regeneration), Ericsson, and Jet Engine cycles, as well as isentropic efficiency. Best of luck in your class!
I'm sorry, I teach full time and am very busy helping my local students. It may help to see problems related to the jet cycle: ua-cam.com/video/fI6tO7qte5Y/v-deo.html for a simple Brayton cycle, ua-cam.com/video/w8jeQBCHp7Y/v-deo.html & ua-cam.com/video/ABFPqeGDNds/v-deo.html & ua-cam.com/video/E1SgmCL8TbA/v-deo.html for Brayton cycle, ua-cam.com/video/iEIesVP0WhU/v-deo.html & ua-cam.com/video/GYTFIiVdmNQ/v-deo.html for Brayton cycle with regeneration, ua-cam.com/video/Li_cUW-RlqM/v-deo.html & ua-cam.com/video/Vp2NjI9913Y/v-deo.html for a simple Jet cycle, ua-cam.com/video/4-d1ypE3Xyk/v-deo.html for a Jet engine.
Damon Sisk its ok sir, thank you. But still i will keep supporting this channel and share to it to my friends. This is a hidden gem in youtube tutorials. If you dont mind sir, what does this part of question means." The engine is designed to handle a 90lb of air per second under sea level static conditions and 116lb of air per second at a flight velocity of 800 ft/s at sea level." I dont know why the mass differs at static conditions and flight
@@xavierramirez6183 Perhaps it is because as the engine moves through the air during flight, it is 'scooping up' air as it goes. Another way to say it may be that the static pressure of the air in front of the moving engine would be higher than when it is stationary. Both of these ideas suggest that the mass flow rate of air through the engine will be higher when the engine is moving forward during flight.
Again, thank you sir. This is a really helpful analysis and a piece of a puzzle in solving this problem by myself. I hope one day I will be able to teach and be as good of a professor you are.
Thank you professer, I’m korean mechanical engineering student.
Your lecture is so helpful.
Thank you.
The exact topic I was looking for.. Thank you so much😊
Glad it was helpful!
Thank you SO MUCH for he whole walkthrough. I am currently failing my class and we have a second chance to bump our grade on the upcoming midterm. Understanding the step by step and the formulas that can be used to find the answers is amazing. Thank you! will continue to look at the next videos!
I'm very glad you found the information useful! If you want to find example problems, search for 'MET 320 9' on my channel. This will find all the videos from chapter 9 of the textbook I use for my course, number MET 320. That chapter is all about gas power cycles, and I always cover the ideal Otto, Diesel, Sterling, Brayton (with regeneration), Ericsson, and Jet Engine cycles, as well as isentropic efficiency. Best of luck in your class!
thankyou so much
i missed my own college course but now i have understood this subject
You are most welcome
Thank you sir... very helpful
هل من مصل على النبي محمد صل الله عليه وسلم وبارك الصلاة الإبراهيمية
This is great sir! May I send you a problem regarding jet propulsions. I cant really solve it, Its a part of licensure examination in our country
I'm sorry, I teach full time and am very busy helping my local students. It may help to see problems related to the jet cycle: ua-cam.com/video/fI6tO7qte5Y/v-deo.html for a simple Brayton cycle, ua-cam.com/video/w8jeQBCHp7Y/v-deo.html & ua-cam.com/video/ABFPqeGDNds/v-deo.html & ua-cam.com/video/E1SgmCL8TbA/v-deo.html for Brayton cycle, ua-cam.com/video/iEIesVP0WhU/v-deo.html & ua-cam.com/video/GYTFIiVdmNQ/v-deo.html for Brayton cycle with regeneration, ua-cam.com/video/Li_cUW-RlqM/v-deo.html & ua-cam.com/video/Vp2NjI9913Y/v-deo.html for a simple Jet cycle, ua-cam.com/video/4-d1ypE3Xyk/v-deo.html for a Jet engine.
Damon Sisk its ok sir, thank you. But still i will keep supporting this channel and share to it to my friends. This is a hidden gem in youtube tutorials. If you dont mind sir, what does this part of question means." The engine is designed to handle a 90lb of air per second under sea level static conditions and 116lb of air per second at a flight velocity of 800 ft/s at sea level." I dont know why the mass differs at static conditions and flight
@@xavierramirez6183 Perhaps it is because as the engine moves through the air during flight, it is 'scooping up' air as it goes. Another way to say it may be that the static pressure of the air in front of the moving engine would be higher than when it is stationary. Both of these ideas suggest that the mass flow rate of air through the engine will be higher when the engine is moving forward during flight.
Again, thank you sir. This is a really helpful analysis and a piece of a puzzle in solving this problem by myself. I hope one day I will be able to teach and be as good of a professor you are.