Nice integral. I got 7/32*zeta(3) instead of 7/64*zeta(3) and wolfram confirms numerically what I got. So you must have an extra 1/2 somewhere. By the way, I used the fourier series of log(sin) and log(cos) from the very beginning without intermediary steps. Faster.
Hey friend😊. I solved it. But yeah I had to look up one thing, that's the fourier transform of ln(sinx), I don't know fourier 😢. After that I did it on my own. It was a brilliant sum.
Hi Maths 505, absolutely awesome integral presented in this video!! Here is a (first) request from me of sqrt(sin(x)) integrated through (0, pi/2). My classmates and I are confused by the elliptic integral approach and are curious if there is a simpler solution (using the tricks mentioned in your channel).
Hi Kamal , hope you doing good , you’re name Means perfection in Arabic , you’re content means a lot to me, that’s why I created this channel to Do maths videos …
Hey, I wish to learn more about calculus after I am done with my JEE advanced next month, I aim to start out with self study. Can you recommend me any sources of information to go ahead, books or websites or other videos perhaps ? I am good with the basics, so I have a strong foundation to build on.
Hi,
"ok, cool" : 0:10 , 6:20 , 7:24 , 9:11 , 10:41 , 11:54 , 16:31 , 16:51 , 19:52 ,
"terribly sorry about that" : 4:48 , 9:51 , 11:37 , 19:14 .
Nice integral.
I got 7/32*zeta(3) instead of 7/64*zeta(3) and wolfram confirms numerically what I got. So you must have an extra 1/2 somewhere.
By the way, I used the fourier series of log(sin) and log(cos) from the very beginning without intermediary steps. Faster.
I checked with wolfram too and the use of 7/64*zeta(3) matches the answer to the integral. I don't think he's wrong.
I think this is the most beautiful result I've seen on your channel! 😊😊
And Catalan is such a top G it survived that cancellation in the last step 😂
This is awesome. Thank you for featured effort.
sin(koi/2) is is zero when k i even but when k is odd it depends on the form of this odd number, if k=4n+1 it is 1, if k=4n+3 it is -1
16:35 (-1)^(k-1) is always identical to 1 , for odd k
Very nice video!!(and also very funny,log2 never hurts😂😂)
Answer is (pi^2)/16 * ln 2
Hey friend😊. I solved it. But yeah I had to look up one thing, that's the fourier transform of ln(sinx), I don't know fourier 😢. After that I did it on my own. It was a brilliant sum.
Thats a tough 1
What material do you use to make these videos, I mean ipad, tablet, applications? Thanks.
Keep up the great work 💪
Hi Maths 505, absolutely awesome integral presented in this video!! Here is a (first) request from me of sqrt(sin(x)) integrated through (0, pi/2). My classmates and I are confused by the elliptic integral approach and are curious if there is a simpler solution (using the tricks mentioned in your channel).
Google geometric form of beta function. Followed by reaction between beta and gamma functions. It'll get you the answer super quick.
@@maths_505 Worked it out!! Thank you!!! The answer is sqrt(2)/sqrt(π)*gamma(3/4)^2 isn't it -> beautiful numbers!
Hi Kamal , hope you doing good , you’re name Means perfection in Arabic , you’re content means a lot to me, that’s why I created this channel to Do maths videos …
Hey, I wish to learn more about calculus after I am done with my JEE advanced next month, I aim to start out with self study. Can you recommend me any sources of information to go ahead, books or websites or other videos perhaps ?
I am good with the basics, so I have a strong foundation to build on.
Advance ke baad waise bhi karna padega bro engineering maths mein yein sab rehta hein.
Mai bhi multi variable calc shrur karuga advance ke bad@@venkatamarutiramtarigoppul2078
Basics ke liye Dr. Terfor bazzett
it is possible to integrate it without limits because i doubt for the results, thanks.
I tried wolfram with the inner integral and just a constant for tan(y) and wolfram said, “No, thank you.”
i love you maths 505
that's a lot of stuff
Not the aprey's constant🫣
Nice
No audio
Good that's what I was going for.
@@maths_505 lol