A bar having a length of 5 in. And cross-sectional area of 0.7 in^2 is subject to an axial load of 8000 lb. If the bar stretches 0.002 in., determine the modulus of elasticity.
A little late but I hope it helps, but you dont actually square it as its inches squared which is a unit of area, you cancel out the 5 and .002 which are both measured in inches and leave lb/in^2 which leaves you with the end result of 28571428 PSI, as in pounds per square inch.
Straight to the point clear and concise! great video.
Thank god I found this video. Directions where very clear 👍
Honestly explain perfectly
This is a Godsend. I was so lost until now
If you still reading comments, thank you!
E=28571428 psi in the video lecture means that the sample in question will break apart at this pressure?
really helpful! thanks
Please is it a gradient
What is the difference between Young's Modulus and the Elastic Modulus?
its the samething just different names
when you were calculating in your calculator did you forget to square the .7?
A little late but I hope it helps, but you dont actually square it as its inches squared which is a unit of area, you cancel out the 5 and .002 which are both measured in inches and leave lb/in^2 which leaves you with the end result of 28571428 PSI, as in pounds per square inch.
What if I dont have the Ao and lo
can you work 3-5?