OMG OMG OMG OMG, YOU ARE absolutely the best at this! I have searched the web for an explaination and cant find one that makes sense, till now. THANK YOU FROM THE BOTTOM OF MY HEART!!!
Thank you, thank you, thank you!!! I got my question right all because of your post and it's the only one on youtube that actually shows the entire math, which I needed desperately! Thanks again!!!
Linda, ln( 2.52E-5 / 3.16E-3 ) actually comes out to -4.83148, not -4.83945, as shown, resulting in a small error in the final value for Ea. But apart from this, a nice worked example for those meeting the Arrhenius equation for the first time.
Im sure after 7 years you've figured this out but for those just reading the question the formula in the video is correct as is BUT if you switch K1/K2 for K2/K1 then you have to add a negative sign to the formula to the right. They both equal the same thing. The point is not to get negative activation energy for the problem. For added pointless complexity you can also switch the 1/T2 - 1/T1 for 1/T1 - 1/T2 and then take the negative back off 😵💫
So amazingly done, I've watched a lot of vids on youtube and yours are incredibly easy to follow. The fact that i'm even taking the time to comment should say a lot. I NEVER COMMENT =)
that is irrelevant as long as k2/k1=1/T1-1/T2 OR K1/K2=1/T2-1/T1 as long as the T1 and K1 correspond to each other as well as the K2 and T2 the equation is right, just depends what way is more comfortable for you or which one youre use to more
Great presentation and explanation. Even though some dogma states the Ea doesn't change with T many Arrhenius plots show a curve at either end tending towards each axis possibly reflecting that heat can be a catalyst in some endergonic reactions.
from what i understand if you choose k1 to be on the top, the first 1/T should be T1 as well. Correct me if I'm wrong I just know I wrote in my notes and circled it to remember. Confused..
It's spelled Kelvin, it's just a unit of absolute temperature used in many calculations. The R constant is equal to 8.314 J/mol-K, so you convert the Celsius temperature to Kelvin in order to cancel the unit and find Ea in J/mol
Well if u say ln(k2/k1) it'd be equal to -Ea/R but if you write as ln(k1/k2) it'd be equal to Ea/R it's only to get rid of the negative Ea, both give the same answer.
Yep. Depends on how a person wants to derive the equation. Also if you wanted Ln(k2/k1) but R to positive, you could do T1 - T2 instead. Just posting this here so others will see this as well.
+Jorge Lopez The units for activation energy is usually kJ/mol and the gas constant is J/mol*k. So for every problem you have to convert Ea to J or R to kJ so they match. She just left the constant in J and converted them to kJ at the end of the equation. You can convert before or after, it doesn't matter.
The best. Not only did you show the chemistry portion but you show the mathematical portion step-by-step. Great job
You are so well spoken & easy to understand. You're awesome, thank you for this video!!!
I have searched all over for something like this and you have done it!! Thank you so much!!!!! life saver.
OMG OMG OMG OMG, YOU ARE absolutely the best at this! I have searched the web for an explaination and cant find one that makes sense, till now. THANK YOU FROM THE BOTTOM OF MY HEART!!!
This video came in very handy at 1 o'clock in the morning. thank you.
Thank you, thank you, thank you!!! I got my question right all because of your post and it's the only one on youtube that actually shows the entire math, which I needed desperately! Thanks again!!!
Linda, ln( 2.52E-5 / 3.16E-3 ) actually comes out to -4.83148, not -4.83945, as shown, resulting in a small error in the final value for Ea. But apart from this, a nice worked example for those meeting the Arrhenius equation for the first time.
Thank you for much Linda for your video and efforts. This has given me clarity on the equation. Very handy when I have a test tomorrow!
confused: my textbook and another video has the formula ln (k2/k1)
I know I'm kind of off topic but does anyone know a good place to stream new tv shows online ?
@Milan Melvin i use FlixZone. You can find it on google =)
Im sure after 7 years you've figured this out but for those just reading the question the formula in the video is correct as is BUT if you switch K1/K2 for K2/K1 then you have to add a negative sign to the formula to the right. They both equal the same thing. The point is not to get negative activation energy for the problem. For added pointless complexity you can also switch the 1/T2 - 1/T1 for 1/T1 - 1/T2 and then take the negative back off 😵💫
Where were you when I was in highschool? Thank you for explaining. NOW...I get it... :)
So amazingly done, I've watched a lot of vids on youtube and yours are incredibly easy to follow. The fact that i'm even taking the time to comment should say a lot. I NEVER COMMENT =)
Same here, Thank you thank you thank you! I was almost in tears trying to do this from the book!!! This helped me solve the equations in there!
shouldnt it be in(k2/k1) not in(k1/k2)?
you're right. She has them flipped wrong
that is irrelevant as long as k2/k1=1/T1-1/T2 OR K1/K2=1/T2-1/T1 as long as the T1 and K1 correspond to each other as well as the K2 and T2 the equation is right, just depends what way is more comfortable for you or which one youre use to more
I did it both ways and got the same answer?? weird
Very helpful video! I have a question; if we have more than 2 data, always we choose the first and the last one, or it depends on the value?
Thanks I needed another problem for my exam !
the K1/K2 is kinda strange to me, 'cause my instructors and many text books have used the opposite. why?
Excellent Video!!
Great presentation and explanation. Even though some dogma states the Ea doesn't change with T many Arrhenius plots show a curve at either end tending towards each axis possibly reflecting that heat can be a catalyst in some endergonic reactions.
Thank you so much!! You did an amazing job at explaining this complete problem. I understand it now!!
You explain very well, Thank you !
Thanks for the video. For future videos you may want to speak more into the mic-- even with volume all the way up we can barely hear you
I can hear crystal clear
Been of great help thank you 🙏
YOU'RE A BEAUTIFUL CREATURE
omg thank you for posting this!!
from what i understand if you choose k1 to be on the top, the first 1/T should be T1 as well. Correct me if I'm wrong I just know I wrote in my notes and circled it to remember. Confused..
why is it some texts show k2/k1 and a negative Ea over RT?
Thanks so much , been working on this all day , this video made me get it!
Beautiful explanation! Thank you!!
Excellent, Thank you!
Perfectly explained...
better than my professor omg thank you
Thank you SO much! This helped immensely!
Thanks! This video was extremely helpful!
For some reason when I calculate the ln (2.52x10^-5/3.16x10^-3) I'm getting -18.646. What am I doing wrong?
This is wonderful.
How did you do the first part LN 2.52E-5/LN 3.16E-3 and get -4.83945 because i keep getting -18.64699387
Parentheses placement make a big difference. I got -18.647 as well, but when i put more parenthesis i got the same answer as her
Thank you!!!
Thank you 💖💖💖💖
Thank you so much!
Thank youuu!! You've saved me!
how did you find 8.31 for R?
Thats the gas constant, its always the same. When i take my exam the gas constant is given on a separate sheet, so you shouldn't have to remember it.
PS... what is Kalvin??? And how did u come up with a wierd unit like that?
Kalvin is a temperature to make it so there is never a negative degree. you just add 273 to Celsius and that's all it is
It's spelled Kelvin, it's just a unit of absolute temperature used in many calculations. The R constant is equal to 8.314 J/mol-K, so you convert the Celsius temperature to Kelvin in order to cancel the unit and find Ea in J/mol
Next time, write ALL the parenthesis we need to add in at a specific place, otherwise we're just going to get the wrong answer
This is great but you really explain how to solve ea if you're given 1 constant and 1 temperature instead of 2...
Thankyou
Thank you🤗
Wow thanks so much!!
+jiffycrimso hmm.. Thanks I think!! Haha
lol yes it does! you too
We love you
sound facts...
I'm pretty sure it's ln(k2/k1)
It doesn't matter as long as you subtract the inverse temperatures in the opposite order.
S. R. Yeah, but most people won't know that unless she points it out, and it could mess others up.
thank you.
Ln (k2/k1)
Well if u say ln(k2/k1) it'd be equal to -Ea/R but if you write as ln(k1/k2) it'd be equal to Ea/R it's only to get rid of the negative Ea, both give the same answer.
Yep. Depends on how a person wants to derive the equation. Also if you wanted Ln(k2/k1) but R to positive, you could do T1 - T2 instead. Just posting this here so others will see this as well.
LOVE LOVE LOVE
should be -EA ... you forgot the minus.
why dont you use 8.314x10^-3? why are you using 8.31? and when should i use it and when not to use it?
+Jorge Lopez The units for activation energy is usually kJ/mol and the gas constant is J/mol*k. So for every problem you have to convert Ea to J or R to kJ so they match. She just left the constant in J and converted them to kJ at the end of the equation. You can convert before or after, it doesn't matter.
When using k2 over k1 and t1-t2 you get 410.57 kj/mol. I beilve you made a mistake
Wait, my fault I found my error
Yeah.... I don't get it... Nor do I want to.
I'll stick with being a sophomore in highschool befor I move onto that confusing crap!
watch your sig figs people
nice nails....
Way too fast
nails are so dirty..