The Monty Hall Problem | Mathematigals

Can maths help you win on a gameshow? Your intuition might fail you when you're guessing which door conceals a prize on the Mathematigals Show...tune in to discover how to maximise your chance of winning!
Created by Caoimhe M. Rooney and Jessica G. Williams (Mathematigals). We are passionate about mathematics education - particularly for young women - and hope our videos showcase fun examples of mathematics in every day life.
Background music "Quiz Game Show Main Theme" (Waderman), "Make It Loud" (Eri), "Game Show Clock Timer" (Waderman), and "Clinical Trial" (Erik Vargas).

[@powaranga9]

Really well done! Thanks for the explanation :)

[@eigentheory]

This was the best explanation of The Monty Hall Problem, great job!

[@cre8iveone699]

You have one try, one door. The House has two tries, two doors. The house then gets rid of one bad door. IF the house had the one good door, they will always get rid of their bad door thus leaving their good door for you to trade with. ( I'm using "House" as a casino reference.)

[@nixboox]

The Monty Hall problem, however, is a fiction that doesn't actually exist in real life.

[@insignificantfool8592]

That is true. The reason for this is that in order for switching to be advantageous, you have to know the host's method of play. Will the host _always_ open one of the other doors with a goat, then switch. Will the host only open one of the other doors if your initial door had the prize, don't switch.
Will the host open a random door? Switching is 50/50.
As long as the host's method of play is not made known, all the information you have is that there are only two doors left. So, 50/50.