If "geniuses" fail to solve this problem, they must be American "geniuses!" This is an easy problem! You obviously see that you can rewrite this as (x^2 - 4)*(x^2 + 4) = 0 giving you 2 quadratic equations. What's supposedly hard about that? It's high school level stuff!
Nowhere in the problem (that I saw) did it specify you were working with complex numbers. People probably (correctly) assumed you were only working with real numbers, which is the standard assumption when imaginary numbers are not mentioned.
Stop it with the clickbait titles already. The only thing marginally tricky about the first problem is dealing with imaginary numbers to get two of the solutions. i is dealt with in elementary algebra. A good high school Algebra student solves this in about 30 seconds on the SAT. A genius might not even write down the intermediary steps and go straight to the solutions upon seeing the question. Don't be an asshat and get all clickbaity. Produce good content and you'll get the views.
What's this? How to make math complicated?
a^2-b^2=49 имеет три корня. Где а=(-7; 7; 25), b=(0; 0; 24). Для твоего ответа надо задать условия.
By inspection, x=2e^(i pi k/2), k any integer.
I think you mean *x = 2e^(i * pi * k/2)*
@@MarieAnne. That's what I meant. Thanks. Corrected
2....
Very simple 2x2x2x2=16-16=0, x=2
4 solutions
@@Dcmazters -2x-2x-2x-2=16 this are very simple
@@BackyardFarming-zj5vz Also: 2i × 2i × 2i × 2i = 16 and -2i × -2i × -2i × -2i = 16
@@MarieAnne. Also j2 and -j2, so six solutions (using a number system I made up and expect everyone to know about even when it's not mentioned).
x=2, x=-2, x=2i, x=-2i
Was there a stipulation for the second equation that both are nonzero values? Why can't a= 7 or -7 and b=0?
2
two
If "geniuses" fail to solve this problem, they must be American "geniuses!" This is an easy problem! You obviously see that you can rewrite this as (x^2 - 4)*(x^2 + 4) = 0 giving you 2 quadratic equations. What's supposedly hard about that? It's high school level stuff!
Why is this hard?
Потому что некорректно задано условие задачи.
Nowhere in the problem (that I saw) did it specify you were working with complex numbers. People probably (correctly) assumed you were only working with real numbers, which is the standard assumption when imaginary numbers are not mentioned.
Stop it with the clickbait titles already. The only thing marginally tricky about the first problem is dealing with imaginary numbers to get two of the solutions. i is dealt with in elementary algebra. A good high school Algebra student solves this in about 30 seconds on the SAT. A genius might not even write down the intermediary steps and go straight to the solutions upon seeing the question. Don't be an asshat and get all clickbaity. Produce good content and you'll get the views.