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My Math Tutor
Приєднався 22 лип 2024
Dive into the fascinating world of mathematics with us. Whether you're a beginner or a math enthusiast, we offer easy-to-follow tutorials, problem-solving strategies, and fun math challenges. From algebra to calculus, geometry to statistics, we break down complex concepts into simple, understandable lessons. Subscribe for regular updates and become a math master today!
A Beautiful Exponential Problem Many People Fail | Can You Solve This?
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Відео
A Beautiful Exponential Problem | Can You Solve This?
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Hello, welcome to my UA-cam channel. Please make sure to leave a like and subscribe for more math content! I upload daily, 3-5 videos per day. #maths #algebra #mathematics #mathematician #mathematicians #algebra #algebratricks #algebraformulas #algebrahelp #olimpiadas #olimpiadmath #algebraquestion #algebraquestions #geometry #easymaths #easymathematics #easymathematicsforyou #multiplication #d...
A Beautiful Exponential Equation | Math Olympiad
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Hello, welcome to my UA-cam channel. Please make sure to leave a like and subscribe for more math content! I upload daily, 3-5 videos per day. #maths #algebra #mathematics #mathematician #mathematicians #algebra #algebratricks #algebraformulas #algebrahelp #olimpiadas #olimpiadmath #algebraquestion #algebraquestions #geometry #easymaths #easymathematics #easymathematicsforyou #multiplication #d...
School Never Taught This Concept | A Beautiful Trick
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School Never Taught This! | Use This Trick To Get Better At Math
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A Beautiful Exponential Problem | Can You Solve This?
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Geniuses Fail To Solve This | The Hardest SAT Problem Ever
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The HARDEST SAT Problem To Exist
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A Challenging Exponential Equation | Can You Solve This?
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Solving An Impossible Equation | Bending The Rules of Mathematics
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Proof 0/0 = 2
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In todays video, I will be teaching you how to solve an interesting problem. Make sure to like, subscribe, and also comment any questions or video ideas you may have relating to math! #maths #algebra #mathematics #mathematician #mathematicians #algebra #algebratricks #algebraformulas #algebrahelp #olimpiadas #olimpiadmath #algebraquestion #algebraquestions #geometry #easymaths #easymathematics ...
Solve This If You Are A Genius | An Impossible Problem
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In todays video, I will be teaching you how to solve an interesting problem. Make sure to like, subscribe, and also comment any questions or video ideas you may have relating to math! #maths #algebra #mathematics #mathematician #mathematicians #algebra #algebratricks #algebraformulas #algebrahelp #olimpiadas #olimpiadmath #algebraquestion #algebraquestions #geometry #easymaths #easymathematics ...
A Nice Exponential Equation | Math Olympiad
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The EASIEST SAT Problem Everyone Failed To Solve | A Nice Math Challenge
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Hello, welcome to my UA-cam channel. Please make sure to leave a like and subscribe for more math content! I upload daily, 3-5 videos per day. #maths #algebra #mathematics #mathematician #mathematicians #algebra #algebratricks #algebraformulas #algebrahelp #olimpiadas #olimpiadmath #algebraquestion #algebraquestions #geometry #easymaths #easymathematics #easymathematicsforyou #multiplication #d...
School Never Taught This! | A Simple Math Trick To Solve Any Problem
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Hello, welcome to my UA-cam channel. Please make sure to leave a like and subscribe for more math content! I upload daily, 3-5 videos per day. #maths #algebra #mathematics #mathematician #mathematicians #algebra #algebratricks #algebraformulas #algebrahelp #olimpiadas #olimpiadmath #algebraquestion #algebraquestions #geometry #easymaths #easymathematics #easymathematicsforyou #multiplication #d...
How To Find 25% of Any Number | A Simple Math Trick
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How To Find 25% of Any Number | A Simple Math Trick
A Beautiful Problem For Geniuses | Can You Solve This?
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A Beautiful Problem For Geniuses | Can You Solve This?
Einstein Failed To Solve This, But a 9 year-old Did
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Einstein Failed To Solve This, But a 9 year-old Did
99% of People Fail To Solve This | A Tricky Olympiad Problem
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99% of People Fail To Solve This | A Tricky Olympiad Problem
A Beautiful Problem Many People Fail To Solve | Math Olympiad
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A Beautiful Problem Many People Fail To Solve | Math Olympiad
A Beautiful Concept School Never Taught | Can You Solve This?
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A Beautiful Concept School Never Taught | Can You Solve This?
The Hardest Easiest Problem In The World
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The Hardest Easiest Problem In The World
The Most Challenging Problem In The World | A Nice Exponential Equation
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The Most Challenging Problem In The World | A Nice Exponential Equation
The Hardest Problem In The World | Solving The Impossible Challenge
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The Hardest Problem In The World | Solving The Impossible Challenge
A Challenging Problem For Geniuses | Math Olympiad
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A Challenging Problem For Geniuses | Math Olympiad
Which One Is Greater? | A Nice Math Challenge
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Which One Is Greater? | A Nice Math Challenge
I don't believe "everyone got it wrong". I don't even believe most.
In examples like this, I always wonder what real life problem you are trying to solve. The equation presented makes no sense in the real world. It is only a construct to test the memorization of the term PEMDAS. When equations are written ambiguously, that is a problem.
0.25
here's the deception of it being divided,, 2 ÷ 2 = means two divided twice,, divide 2 once =1+1 now two cannot be divided again because there was only one (two) to divide and there's no second two to divide ! LOL doesn't make sense to me either,, either way,, it's all in your head stop thinking !
I just use the calculator,, clear to many variables for equations that are just so misleading,, makes no sense,, just do math without all the deceptions they have installed in math equations
Fun math fact, but the square of one number to the next is just the number and the next added to it's square. 10²=100 11²=121 (100 +10 +11) 12²=144 (121 + 11 +12) So 199²=200² -200 -199, so the difference is just them adding themselves into the other.
Solve 7 + 7 divided by 7 x 7 Note there are no brackets to separate the numbers only the division sign which signifies this equation is an algebraic equation for a fraction. 7 +7 = 14 which is the numerator in this fraction divide by 7 x 7 = 49 which is the denominator in this fraction Answer is 14 / 49 = 2/7. or where A = 7 7 + 7 = A +A = 2A and 7 x 7 = A x A = 2A divided by A x A = 2/A = 2/7 Algebra is fun when you know what it is. OR if you have used brackets in your equation which this equation does NOT have. 7 + (7/7) x 7 = 7 + 1 x 7 = 7 + 7 = 14 🤪🤪🤪🤪🤪🤪💪💪💪💪💪💪
You really over complicated it! I did it in my head…2 / 2 = 1, 1 / 2 = 1/2, 1/2 / 2 = 1/4. Why introduce the multiplication? BTW, it’s maths!
Is PEMDAS always used on test (SAT, GRE, etc).
Why in the world anybody would alter the order in which the operation was given?? You have to go left to right and that is the end of it since all the operations are the same (divide).
4
14
1:45 , How are you getting 20? Adding to -1 makes sense, its pretty similar to a quadratic equation in that regard but the 20? I have no clue.
They allow TI-83 calculators during the math test, so plug it into your calculator and you’ll get a decimal answer. Then press MATH then FRA (Fraction) and it will give you 1/4. 😂
turn up the mic gain
By the way, you can get 14 using different approaches: 1. + / x , 2. / x +…both get 14
I call bs that 'everyone got it wrong'. If I had to guess, I'd say most people who take SATs would get it right.
It’s simple. My 8yr old nephew solved it.
Which answer are most people giving? That's what I want to know.
high school kids actually missed this?
I answered it before I even started the video by basically doing it the way you did it except I did it in my head. The only difference is that I divided 1/2 by 2. Since dividing by 2 is, essentially, obtaining half of a number, 1/2 of 1/2 is 1/4.
.25
Likely a question not solvable for anyone who supports Donald Trump. These are methods learned in primary school
My 7 year old grandson explained this perfectly.. Not sure what kind on Olympiad this is presented in.
(0/0) = ((1-1)/(1-1)), because (x+y)/z = x/z + y/z, ((1-1)/(1-1)) = (1/1 - 1/1) = 1-1 = 0, so 0/0 is 0
6 to 1, half a dozen plus 1 to most
this is just awful... you just took parts of factor theorem and removing the ease of it. just use factor theorem instead of this
How would you use factor theorem for this?
@@crinas1548 you plug in values into the original equation, until it equals 0, so in this case, plugging in 5 as x is equal to zero, then you can solve using synthetic division
I am GLAD school did not teach this concept 🙏🙏🙏
Sophisticated bull !
This is so simple my cat could figure it out.
oh noes ...did you divide the rations and treats ? mad move !!! :p
👎👎👎👎👎 This formula is meaningless. Brackets are to be used. Period. Don’t waste our time with idiotic pseudo-controversy.
I immediately, in my head, came up with .25, but I went to school in the 50s and 60s. I guess that's where I went wrong.😂
What a crap way of working out!!! 2÷2=1 ....÷2= 1/2. ÷2 = 1/4 ... easy!
These math problems are so riduculous that they does not exist
4
40 to the 40th power / 100 to the 20th => 40 to the 40th / 10 to 2nd x 10to 20th => 40 to 40th / 10 to 40th => 4 to the 40th.
Questions of this type are just about remembering an arbitrary precedence convention rather than mathematics.
Log 32 divided by Log 16 = 1.25 => 16 to 1.25 power = 32
If A = 7 and B = 0 then, A squared - B squared = 49, and A + B = 7 and A - B = 7. You did NOT define that neither could be 0.
Unusual problem in that If I use PEMDAS I get 14, but if I just go left to right, I also get 14. Thus, the problem does not really determine whether a person understands PEMDAS. OOPS.
PEMDAS or whatever they call it in other countries is total BS. It's like first creating a non existing problem in order to provide a "solution" that's unnecessary in the first place. Coming from Europe, I was never taught that nonsense and have never used it. Please do not subject your kids to this idiotic "theory".
Only solution is x = 0
I like replacing "÷a" with "×(1/a)" So... 2÷2÷2÷2 Is 2×(1/2)×(1/2)×(1/2) = 2×(1/2)^3 = 2×(1/8) = 2/8 = 1/4 This technique is helpful with a÷b÷c÷d where left to right ordering is critical because it becomes a×(1/b)×(1/c)×(1/d) which IS same as a×(1/d)×(1/c)×(1/b) Check it out... I.E. 10÷2÷5÷3 =10×(1/2)×(1/5)×(1/3) =10×(1/30) =1/3 And, alternately =10×(1/3)×(1/5)×(1/2) =10×(1/30) =1/3
x - x/9 = 0 l • 9 9x - x = 8x = 0 <=> x = 0
At the very least, you omitted to specify from the beginning that both "a" and "b" must be positive integer numbers and that none of them can be zero. Instead, you slipped in those assumptions while you were moving along; which is not how math works. If this was indeed part of an SAT the way you presented it, I feel sorry for those kids; and the teachers who included it in the test in this format must be re-educated.
it's 1/4. I doubt if it is of any importance if someone does not know this. My calculator on Windows says the answer is 0.25.
Stop it with the clickbait titles already. The only thing marginally tricky about the first problem is dealing with imaginary numbers to get two of the solutions. i is dealt with in elementary algebra. A good high school Algebra student solves this in about 30 seconds on the SAT. A genius might not even write down the intermediary steps and go straight to the solutions upon seeing the question. Don't be an asshat and get all clickbaity. Produce good content and you'll get the views.
OMG. Say it ain't so Joe. This like grade 5 arithmetic.
So the math I learned in 1954 still works! Yay
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