B.Sc. II Year | Oxidation State of Lanthanides | लैन्थनाइड की ऑक्सीकरण अवस्था

[@LearnChemistryOnline]

There are some mistakes in electronic configurations of Tb to Yb. Kindly add one electron in each 4f of Tb to Yb.

[@khyatiii]

Sir aapne bhot achaa explain kia , thank you sir

[@krishnarathoree]

Your way of teaching is really osm..

[@varshajangra7467]

Thanks sir 👍👍👍

[@varshajangra7467]

Sir plz upload video on qualitative and quantitative analysis of Inorganic chemistry

[@LearnChemistryOnline]

ok

[@pranjalnamdev6993]

Sir bahut acha explain kiya aapne 👍

[@ChandankashyapLH]

There are some thermodynamic and kinetic reasons for which lanthanides show different oxidation state.

[@morisd5066]

Error: 2:50 from Tb to Yb all electronic configuration are incorrect
Tb = 4f9 5d0 6s2
Dy = 4f10 5d0 6s2
Ho = 4f11 5d0 6s2
Er = 4f13 5d0 6s2
Tm =4f13 5d0 6s2
Yb = 4f14 5d0 6s2
Lu = 4f14 5d1 6s2

[@LearnChemistryOnline]

Yes.
I have already mentioned it in pinned comment.

[@mirsaima3325]

In Er it is 4f12

[@adarshup9012]

Thank you sir or solve my doubt

[@GayatriDevi-ss5zs]

Thanq sir

[@komalshekhawat6351]

Sir jaise ce +4 e tyag kar xe ka sthai vinyas prapt kar leta hai lekin sir pr +3,+4 o.s rakhta hai i mean ye to 3,4 e tyag kar xe ka sthai vinyas parpt nahi karta xe ka vinyas parpat karne ke liye 5 e tyag ne hoge or is ki o.s +5 hogi lekin esa nahi hota hai kyu sir ??????

[@LearnChemistryOnline]

5th electron ko remove karne ke liye jayada energy ki requirement hoti h.

[@komalshekhawat6351]

Ok thanku sir

[@tajuddinsheikh313]

Nicely explain
thank you so much sir ❤️

[@AkshayKumar-vr4ss]

TQ sir

[@shahnavaz_]

Thanks

[@poojakashyap4289]

Error

[@Lmcreation26]

TB ka electronic configuration wrong hai

[@LearnChemistryOnline]

I have already mentioned it in pinned comment.