B.Sc. II Year | Magnetic Properties of Lanthanides | लैन्थनाइड के चुंबकीय गुण

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  • Опубліковано 19 січ 2025

КОМЕНТАРІ • 18

  • @ChandankashyapLH
    @ChandankashyapLH 10 місяців тому +1

    magnetic property of lanthanides are different from transition elements.

  • @arindamchakrabarty4649
    @arindamchakrabarty4649 8 місяців тому

    Thank you very much for this clear explanation

  • @Akash_3120
    @Akash_3120 2 роки тому +1

    Thank you very much sir 🙂

  • @vivekjhajhria6196
    @vivekjhajhria6196 3 роки тому +1

    thanks you so much

  • @varshajangra7467
    @varshajangra7467 4 роки тому +1

    Thank you sir

  • @sagnikamohanty1786
    @sagnikamohanty1786 2 роки тому

    Tq so much Sir

  • @kuldeepnathrj-1381
    @kuldeepnathrj-1381 4 роки тому +1

    tnx sir ji

  • @mridulajariwal1534
    @mridulajariwal1534 2 роки тому

    Sir then where will the formula u s+l = √4s(s+1)+l(l+1) be used

    • @LearnChemistryOnline
      @LearnChemistryOnline  2 роки тому +1

      When both orbital magnetic moment and spin magnetic moment contributed to value of magnetic moment.

    • @mridulajariwal1534
      @mridulajariwal1534 2 роки тому

      @@LearnChemistryOnline sir can this formula ve applied to the examples that you have explained in the video.

    • @LearnChemistryOnline
      @LearnChemistryOnline  2 роки тому +1

      This formula cannot be applied on first transition series elements. It is for 2nd and 3rd transition series elements.

    • @mridulajariwal1534
      @mridulajariwal1534 2 роки тому

      @@LearnChemistryOnline and on f block elements also?
      Sir I used this formula for the questions you explained in video but the answer came out to be wrong.

    • @LearnChemistryOnline
      @LearnChemistryOnline  2 роки тому +1

      For Lanthenides, u = g √J+(J+1) is used