Improve your Digital SAT score by 100 points, GUARANTEED! Our brand new Ultimate Digital SAT Course has 70+ hours of videos where I teach you everything you need to know to crush the Digital SAT. It's like having me as your private tutor for only $99/month! Check out the Free Trial for my Ultimate Digital SAT Course: www.preppros.io/sat-course. Our new Digital SAT Math Book is available now! Get your printed copy on Amazon (www.amazon.com/dp/173718382X) or a PDF copy on our website (preppros.teachable.com/p/my-downloadable-110389) Prepare for the SAT in 1 Week Or Less with our brand new Digital SAT Crash Course! www.preppros.io/sat-crash-course
in question 3 we can do it like this : 81=9*x/100 + 9 81=9*(1+x/100) 81/9 = 1+x/100 {81/9=9 so 9=1+x/100} 8=x/100 x=8*100=800 its kinda the same but i thought its more understandable like this
That's awesome. From your scalar factor, I developed a relation. IF two figures are similar, then: Let A and B be two similar figures. Length (A)/ Length(B) = Breadth (A)/Breadth(B) = Perimeter(A)/Perimeter(B) = √Area (A) / √ Area (B) = k ( scale factor), with this relation, this type of question becomes a piece of cake.
Ok, Consider, 50 is increased by 10%. We do: 10% of 50 = 5 And add it to the original 50, so the resulting sum becomes 55. We can bake this in a single equation: 50 + 10% of 50 = 50 or, (1 + 10%) = 50 or, 50 (1 + 10%) or 50 (100+10)% = 50 or (1 + 10%) of 50 or (100+10)% of 50 = 50 Yeah, we derived a formula. (1+ x%) of initial value = (100 + x) % of initial value = initial value + increased value This holds true of decrease, (100 - x) % of initial value = initial value - decreased value. Now, you know why we are multiplying instead of adding. Because, of = multiply
If it asks for the LEAST possible value, this question would be wrong. You can see it in the way he solves it: He uses b^2-4ac and he gets ac < and equal to 2401. If they ask for the smallest value then it would be negative infinity (Which does not make sense).
Hello! I got your course and I love it. I actually watched the august video and your predictions were spot on. I was wondering how you make these predictions. Is it based on whats been tested so far this year orrr
Hi, I'm glad to hear that! There's a bit of periodicity to the the concepts tested across the Digital SATs and repetition of particular question types across the given forms and months, so I am factoring that in along with some other data that I track.
This is an ACT question that I'm asking here because I'm not sure he'll see it in time, but I was wondering if I'm taking the digital ACT, should I still print out the practice ACTs or leave them as PDFs? Thank you so much! (And sorry for the off-topic question!)
since f(x)=a^x+b and when x is 0 ,f(x) or y=-342, input the x and y values to make a^0+b=-342, since anything^0=1 , 1+b=-342, rearrange the equation, so that b=-343. Next take the x intercept value of (3,0) and input in the equation to make a^3+b=0. Substitute the value of b from the first part to make a^3-343=0. Rearrange this to make a^3=343, and find the cube root of 343 which is 7. Thus a=7, b=-343 , 7+(-343)=-336
Improve your Digital SAT score by 100 points, GUARANTEED! Our brand new Ultimate Digital SAT Course has 70+ hours of videos where I teach you everything you need to know to crush the Digital SAT. It's like having me as your private tutor for only $99/month! Check out the Free Trial for my Ultimate Digital SAT Course: www.preppros.io/sat-course.
Our new Digital SAT Math Book is available now! Get your printed copy on Amazon (www.amazon.com/dp/173718382X) or a PDF copy on our website (preppros.teachable.com/p/my-downloadable-110389)
Prepare for the SAT in 1 Week Or Less with our brand new Digital SAT Crash Course! www.preppros.io/sat-crash-course
can you tell me from where I take real practice test other than blue book app
Can you upload a November predictions for the Nov 2 SAT?
the best sat tutor and youtuber imo
I got at least half of your predicted question types in today's exam! Thank you so much!
How was it?? Was the math section super hard?
Sameee
Same
@@zarzeezayzoo 1 st section was extremely easy but second module fr sucked
Do you remember which ones exactly?
Thank you so much for posting this video. Hope to see more useful content before the october SAT. 😊
Hope to get a 1600! This is my reminder here that I will recieve it - I worked hard until now. Taking test tomorrow, wish me good luck!
Good luck, bro.. me too!
what happened bro?
yoo what happenedddd
@@aslidd1n820 took it, feel okay about it now i need to wait like 2 weeks to get result. I'll post an update here on what I got!
@@lanadelrey.098 took it, feel okay about it now i need to wait like 2 weeks to get result. I'll post an update here on what I got!
Your videos helps me alot ,thank u so much for uploading this kind of usefull stuff,❤
in question 3 we can do it like this :
81=9*x/100 + 9
81=9*(1+x/100)
81/9 = 1+x/100 {81/9=9 so 9=1+x/100}
8=x/100
x=8*100=800
its kinda the same but i thought its more understandable like this
You can also do [(final - initial)/(initial)]*100 to get the percentage increase. final being 81 and initial being 9
@@leouladera never thought of doing that ill try it next time
Yeah that is what I did too. Just to avoid putting 8 as the answer.
@@leouladera Thanks bro this is so much easier cause the formula is also used for chem
Super helpful! Could you walk through some more examples of scale factors and unit conversions?
great video as always! can we get another video specifically for the second harder math module?
Thank you man, I hadn't known the statistics question.
That's awesome. From your scalar factor, I developed a relation. IF two figures are similar, then:
Let A and B be two similar figures.
Length (A)/ Length(B) = Breadth (A)/Breadth(B) = Perimeter(A)/Perimeter(B) = √Area (A) / √ Area (B) = k ( scale factor), with this relation, this type of question becomes a piece of cake.
Really helpful video. Thank you so much!
thanks for the crash course!!!!! my sat is in an hour tho 😅
how was it?
can you please tell me ,in Q3 why u are multiplying 1+x/100 by 9 instead of adding it by 9
Ok,
Consider, 50 is increased by 10%.
We do: 10% of 50 = 5
And add it to the original 50, so the resulting sum becomes 55.
We can bake this in a single equation:
50 + 10% of 50 = 50
or, (1 + 10%) = 50
or, 50 (1 + 10%) or 50 (100+10)% = 50
or (1 + 10%) of 50 or (100+10)% of 50 = 50
Yeah, we derived a formula.
(1+ x%) of initial value = (100 + x) % of initial value = initial value + increased value
This holds true of decrease,
(100 - x) % of initial value = initial value - decreased value.
Now, you know why we are multiplying instead of adding. Because, of = multiply
Vey helpful video thank you so so much i understood so many things thanks to you
3:49 if the awnser is asking for the rate in minuets squared, why do you square the minuets in the equation instead of leaving them as so?
Thank you
For Q1, what will be the answer if the question is asking for the LEAST possible value
If it asks for the LEAST possible value, this question would be wrong. You can see it in the way he solves it: He uses b^2-4ac and he gets ac < and equal to 2401. If they ask for the smallest value then it would be negative infinity (Which does not make sense).
Another way to put it is that if they ask for the least possible value, either a or c has to be a negative number.
Hello! I got your course and I love it. I actually watched the august video and your predictions were spot on. I was wondering how you make these predictions. Is it based on whats been tested so far this year orrr
Hi, I'm glad to hear that! There's a bit of periodicity to the the concepts tested across the Digital SATs and repetition of particular question types across the given forms and months, so I am factoring that in along with some other data that I track.
This is an ACT question that I'm asking here because I'm not sure he'll see it in time, but I was wondering if I'm taking the digital ACT, should I still print out the practice ACTs or leave them as PDFs? Thank you so much! (And sorry for the off-topic question!)
Sat real exam is conducted on bluebook or any other app
waiting for nov post
i learned from this
didnt understand question 4 anyone here to explain?
how can we solve Qs 13:13 with no calculator
since f(x)=a^x+b and when x is 0 ,f(x) or y=-342, input the x and y values to make a^0+b=-342, since anything^0=1 , 1+b=-342, rearrange the equation, so that b=-343. Next take the x intercept value of (3,0) and input in the equation to make a^3+b=0. Substitute the value of b from the first part to make a^3-343=0. Rearrange this to make a^3=343, and find the cube root of 343 which is 7. Thus a=7, b=-343 , 7+(-343)=-336
@@cupcakefanuzb5572 Isnt it 342 tho? the answer would be -335
the first question must be 2400 no?
cause it 2401 is greater or "equal" to the c, so the maximum of c can be 2401
@@user-bb3yd6zi I was confused about that why is it = and not just less than