Yeah I am wondering why does that happen myself. Your teacher with a PHD has been drilling some knowledge into you but you discover you are learning better from a youtuber.
Thanks for the detailed tutorial. For the people who find it hard to calculate break away point, just calculate characteristic equation 1+G(s)H(s) = 0, then find the equation in terms of s and with k on RHS. Now differentiate with respect to s or dK/dS and equate it to zero. From this you can find the solutions for s, which are break away and break in points.
@10:52 woah I'm mind blown by that equation for solving the break-in/break-away points. The method taught to us in class is differentiating the equation K = -1/GH and setting it to zero. It's naturally a bit tedious because the quotient rule for differentiation would have to be applied, but it yields the polynomial that's solvable through a hand calculator. I tried solving the equation here using shift-solve in the calculator and it's not able to get -3.0864. That being said, still a very helpful thing to know! I'm curious now how that is derived for solving the points :)
Your voice made me concentrate the whole 16 min video which my professor tried explaining throughout 3 sessions of 2 hour lectures each. Thank you so much!
about the angles its a stated thing - if Fp-Fz = 2 its gonna be 90, -90 if it's three then 60,-60, and 180 and if it's 4 then 45, -45 something I didn't remember the point is that - in RL you need an identical asymptote that will to in the other direction in the same angle from the same point on the Real axis (hope it helped) oh and thank you really helped me to understand how to draw the RL graph
oh and one more tip - instead of taking random K's you could just do the: (2*h+1)*180\Fp-Fz when h = Fp-Fw-1 the way you do it is you start from zero and work your way up to the value of -> Fp-Fw-1 ich time you put the results in the equation
Thanks for clearing that up, great video. Although I think at 0:48 is wrong to assume that the open loop T.F is done by only taking the top line, as this is only valid in unity feedback systems where H(s) = 1, when H(s) is not equal to 1, Open loop T.F is equal to G(s) * H(s)
Thank you so much ma'am You literally solved this problem and made it really easy to understand Other UA-camrs just wasted my time Thank you again ❤️❤️
I would have gotten an A in my ECE 460 class (Control Systems) if this lady was my professor. The one I had was a complete JOKE as are most university professors.
K (the gain) depends on where you select to put your closed loop poles. What you plot on the diagram is the potential locations. You typically have some sort of criteria that determines what your K should be. I recommend watching some of the other (later) videos in the control playlist that cover this part (look for ones about designing controllers).
Thanks for the video and i have one question mark. What if the degree of the nominator and denominator is equal so the degree of the system is equal to 0. How can we calculate the angle and the sigma value than ?
I think this is a pure maths question about dividing polynomials. I have videos about "polynomial long division" if you want to search for that on my channel or you could find it on the internet more generally.
16min video summed up what my professor was trying to explain in a 2hr lecture... Thank you so much
Literally the same man. I have a 72 page document on this from my prof and I understand in 16 minutes
love this
Yeah I am wondering why does that happen myself. Your teacher with a PHD has been drilling some knowledge into you but you discover you are learning better from a youtuber.
I thought it was a third world issue, but turns out it's global.
فضحتنا يا هشام
Why can't everybody on youtube make clear, concise, straight to the point videos like this one. 5 star rating, you are the bomb!!! lol
you are right!
This is, by far, the best video I've seen on root locus. The explanation was short, concise, the formulas and steps easy to follow.
This is exactly what I expect from a teacher, being direct and unbelievably precise! Thank you very much, teacher!
i'm literally going to cry, this was so helpful. my professor's 70 slides cannot compare to this 15 min vid.
Thanks for the detailed tutorial.
For the people who find it hard to calculate break away point, just calculate characteristic equation 1+G(s)H(s) = 0, then find the equation in terms of s and with k on RHS. Now differentiate with respect to s or dK/dS and equate it to zero. From this you can find the solutions for s, which are break away and break in points.
Im no stranger to UA-cam math videos and this by far is one of the best I've seen. Thank you!
The steps are so clear and helpful! Very efficient. Thank you!
Bless You
your videos are genuinely so good
I can't believe my eyes. How come a human can make such a great video. I am literally shocked. Thanks a lot Mam.
@10:52 woah I'm mind blown by that equation for solving the break-in/break-away points. The method taught to us in class is differentiating the equation K = -1/GH and setting it to zero. It's naturally a bit tedious because the quotient rule for differentiation would have to be applied, but it yields the polynomial that's solvable through a hand calculator. I tried solving the equation here using shift-solve in the calculator and it's not able to get -3.0864.
That being said, still a very helpful thing to know! I'm curious now how that is derived for solving the points :)
Your voice just literally made me understand this topic
The best Root Locus video. The 2 hours as discussed with my professor was to difficult to understand while with this clip, it is clear and concise.
Super helpful! Thanks, girl!
Thank you from Canada. Amazing work! Super clear, concise, and logical. You’re the best!
Too much helpful about understanding root locus , thanks a lot !!
Why didnt i found this video before my final exam. Thank you so much
Mine is next week. Glad I found it before 😇
@@ReussirSonProjetEtudesAuCanada good for you i still passed it but with a C.
Your voice made me concentrate the whole 16 min video which my professor tried explaining throughout 3 sessions of 2 hour lectures each. Thank you so much!
You are simply amazing !
Wow what a precise and clear lecture ❤
This was so clear and easy to understand!! Thank you so much!
Thank you for sharing. Greetings from Panama 🇵🇦
You saved my life! I've never watched a control systems lecture so objective, thank you!
Thank you so much, you gave me confidence in solving these problems now :)
I've nothing to say other than this is one of the most helpful videos I've ever come across
Absolutley amazing video! Can't get over how clear it is
Thank you very much. the Best video about the Root Locus. ❤🔥
Thank you! Straight and direct to the point with a nice simple example to actually help understand what's happening👌😁
about the angles its a stated thing - if Fp-Fz = 2 its gonna be 90, -90 if it's three then 60,-60, and 180 and if it's 4 then 45, -45 something I didn't remember the point is that - in RL you need an identical asymptote that will to in the other direction in the same angle from the same point on the Real axis (hope it helped)
oh and thank you really helped me to understand how to draw the RL graph
oh and one more tip - instead of taking random K's you could just do the:
(2*h+1)*180\Fp-Fz when h = Fp-Fw-1 the way you do it is you start from zero and work your way up to the value of -> Fp-Fw-1 ich time you put the results in the equation
Really too helpful for me
Really solved all my doubts I was having earlier
Thank you for making this video
you just 2 weeks into a nice 16 minute session. Thank you
Thanks a lot great sense of humor mam !!
Fantastic video, really clear and concise. Thank you so much!
first time a video deserves 0 dislike. great video thank you so much
Love your hand writing, looks really cool! xD
Awesome tutorial, thanks!
Thanks for clearing that up, great video.
Although I think at 0:48 is wrong to assume that the open loop T.F is done by only taking the top line, as this is only valid in unity feedback systems where H(s) = 1, when H(s) is not equal to 1, Open loop T.F is equal to G(s) * H(s)
thinking the same thing
This is the cutest voice I have ever heard !!
you are the best teacher,you deserve a bell
Thank you so much ma'am
You literally solved this problem and made it really easy to understand
Other UA-camrs just wasted my time
Thank you again ❤️❤️
These are great, thank you very much!
Nice video on root locus
Thanku for very nice explain 👌
Thank you so much..Amazing video, simple yet easy to understand and to the point.
Thank you so much! This was very helpful as I prepare for my exam!
Thank you so much. your worth much more then 1000 views.
omg she is adorable. thanks a lot
thank you so much . this is quite simplified, keep up the good work
you're a life saver, thank you for explaining this >.
Great work, i was confused with asymptotes
Great video thank you
Super explanation
This is really good explanation.thank you very much
Is there any video on Bode plot?
Woow.you made it too easy😊
Thank u so much ma'am it helped me alot u have explained everything so crystal clearly thanks alot
thanks... From Iraq 🌹🌺
Tyvm,even I’m not an English native speaker,I still understand 90%what ur saying ,ty
this saved my damn life
I can't believe a girl is teaching me
Your voice is so sweet.. It's easier to learn 😁
i love your voice the way you speak is fabulous.And you are so intelligent lol
Great video.
How do you do your video like that? Like what do you use to write on the background, and how do you record?
Thanks so much.
Explanation was perfect
Wouldnt you only join them starting at ODD poles/zeros
Actually my prof took a week , but I didn't understand what he wanted to teach..... Love you from BIHAR
Excellent !
Thanks that was so easy
thank you so much this video its perfect for me
You are great 👍 thanks for this
how to find " the range of gain for which the system is stable"?
Merci à toi ! très bonne explication
thanks mam love from INDIA
I would have gotten an A in my ECE 460 class (Control Systems) if this lady was my professor. The one I had was a complete JOKE as are most university professors.
Thanks thanks a lot. This was amazing 👏
❤️❤️ Paoools
ありがとうございます！！
Thank you very much 💖, this video really helped.
Hi I was wondering, when u found the asymptotes angles 90, 270 deg, can you instead can you write +_90 degrees? Cause the formula has +- Infront of it
best shit ive seen in a while. Great job! :D
Thank you! Very Clear.
I have a better understanding just after watching this video, please explain how the break away/break in is done in MATLAB .
what if a pole repeats? do you add it twice?
Yes
Thank you so much :) Saved my life !!!
Thanks a lot! You are helping now a student in 2024😂
You just saved my career
This is the shit, you did a great job on this. Teachers cant teach nearly as well as you did
Thank you from Thailand.
How are 90 and 270 repeating angles
Thanks for your clear explanation. I just have a question please. How to find 'K' coefficient in this exercise ? thanks :)
K (the gain) depends on where you select to put your closed loop poles. What you plot on the diagram is the potential locations. You typically have some sort of criteria that determines what your K should be. I recommend watching some of the other (later) videos in the control playlist that cover this part (look for ones about designing controllers).
One question: What if we had (s+6) / ((s+6)(s+1)(s+2)), then we have zero=-6 and pole=-6 ? What in that case?
Hi! Nice video! are you a student? what's your major?
Lovely
hi, at 8:15 i do not understand what you mean by repeating angles. could you explain?
LOL i owe my degree to youtube ... finally something that helps !! i was about to go crazyyyy
Thanks for the video and i have one question mark. What if the degree of the nominator and denominator is equal so the degree of the system is equal to 0. How can we calculate the angle and the sigma value than ?
I think this is a pure maths question about dividing polynomials. I have videos about "polynomial long division" if you want to search for that on my channel or you could find it on the internet more generally.
@@theryderproject5053 Omg I didn't even remember that I asked this question :) That was for my exam but thanks though I appreciate it :)
good job ryder
thank you!!!