*Timestamps:* 0:14 - Trigonometry 3:41 - Vectors 5:00 - Differentiation 12:28 - Integration 17:40 - Exponentials & Logarithms Would have been amazing if you could've gone over sequences and series as well but thanks so much for these - really helpful.
In the first question where did the 2 come from. I understand the previous step of substituting 1-sin(squared)x into cos(squared)x but can't see where the 2 is.
i have the same question. though i have to say, I suck at factorising so I always use the calculator. so when you factorise and you get the x values and you kinda work your way backwards (as in from the x values you try to get to the brackets) you will get the two. but I am still confused how it happened. i am really bad at explaining I hope this helped :D
I think ive gone through my working three times now and still can't figure it out. Trig identities is one of yhe things I'm really struggling with as well. My exam is tomorrow 😫 im so screwed
If you work backwards (3sinx-1)^2 = 2 can be written as 9sin^2 x - 6^sinx + 1 = 2 which it you take away 1 from both sides gives you the other equation
@@npdap Ahh okay, you posted your comment the day before the wjec paper so I thought you mightve been doing that one too. Turns out the wjec ended up putting questions on the exam about topics they took out of the specification 🥲
In a definite integral (one between limits) there is no need for a +c (constant of integration). If you did put one in it would get cancelled out when you substitute the limits.
you get 1-sin²x = 8sin²x - 6sinx then 1 = 9sin²x - 6sinx then add 1 to both sides 2 = 9sin²x - 6sinx + 1 if you expand (3sinx - 1)² = 2 you will get 9sin²x - 6sinx + 1 = 2
@@cobraaz2551 it is irregular as usually you wouldn’t have to add 1 to both sides of an equation but in this question, to prove they are equal you have to add 1 to both sides
Hey, so I was wondering if you could give a detailed explanation on the screen of how you get to each part with methods and what you did, but your explation was amazing thank you.
Arcsin(0.1381)=7.94, sin is negative in the 3rd and 4th quadrants, so to solve sin x = -0.1381 we have x= 180 + 7.94=187.94 and x = 360 - 7.94 = 352.06
You've been asked to find the equation of the tangent so you just use the value of dy/dx. You would use the negative reciprocal if you wanted to find the equation of the normal.
@@tonydebling oh so if only it says ''normal'' you do the negative reciprocal but when its tangent you use the normal gradient. the reason why I thought you did it was because tangents are perpendicular to the circle and my teacher said do the negative reciprocal
Hey, I can't really say. These days the A level syllabuses are much more closely aligned so there shouldn't be much difference in difficulty. I think the availability of resources and the level of service provided by the exam boards are more significant, but on these matters I cannot comment.
This man's tone of voice describes my enthusiasm for maths exactly.
lmfao
literally bro
*Timestamps:*
0:14 - Trigonometry
3:41 - Vectors
5:00 - Differentiation
12:28 - Integration
17:40 - Exponentials & Logarithms
Would have been amazing if you could've gone over sequences and series as well but thanks so much for these - really helpful.
Check out the Formula Booklet videos
again with the clutch. thanks buddy
@@tonydebling howcomes -300pi/r^2 differentiated to 600/r^2 and not 600pi/r^3???
@@tonydebling *600pi/r^2***
Iii
@22:41 second derivative of C should have final term 600pi/r^3 not 600pi/r^2, but reasoning remains the same [thank you SoupDragon]
Great video sir keep up your fantastic work. I make similar videos.
thank you very very much
In the first question where did the 2 come from. I understand the previous step of substituting 1-sin(squared)x into cos(squared)x but can't see where the 2 is.
i have the same question. though i have to say, I suck at factorising so I always use the calculator. so when you factorise and you get the x values and you kinda work your way backwards (as in from the x values you try to get to the brackets) you will get the two. but I am still confused how it happened. i am really bad at explaining I hope this helped :D
I think ive gone through my working three times now and still can't figure it out.
Trig identities is one of yhe things I'm really struggling with as well. My exam is tomorrow 😫 im so screwed
If you work backwards (3sinx-1)^2 = 2 can be written as 9sin^2 x - 6^sinx + 1 = 2 which it you take away 1 from both sides gives you the other equation
yeah me too!
great help cheers
Thank u so much!!
Good luck everyone for the paper🤝
You doing WJEC?
@@pip2162 im doing edexcel mate
@@npdap Ahh okay, you posted your comment the day before the wjec paper so I thought you mightve been doing that one too. Turns out the wjec ended up putting questions on the exam about topics they took out of the specification 🥲
Hey there.
Would there not be a 'c' variable when you integrate the equation within the brackets at 17:10?
In a definite integral (one between limits) there is no need for a +c (constant of integration). If you did put one in it would get cancelled out when you substitute the limits.
for the first question where did the equals 2 come from?
you get 1-sin²x = 8sin²x - 6sinx
then 1 = 9sin²x - 6sinx
then add 1 to both sides
2 = 9sin²x - 6sinx + 1
if you expand (3sinx - 1)² = 2 you will get
9sin²x - 6sinx + 1 = 2
@@usmaanafzal3743 why would you add 1 to both sides?
@@cobraaz2551 it is irregular as usually you wouldn’t have to add 1 to both sides of an equation but in this question, to prove they are equal you have to add 1 to both sides
@@usmaanafzal3743 this doesn't make much sense to me :/ would never think to add 1 to both sides in an exam
as it should be -1 on both sides
thank you so much :)
Hey, so I was wondering if you could give a detailed explanation on the screen of how you get to each part with methods and what you did, but your explation was amazing thank you.
I do do online tutorials. I charge £30 for 40mins. Let me know if you are interested. Email tonydebling@gmail.com
@@tonydebling if you can do an hour for £30 I will be interested
@@albinalex6435 Sorry don't negotiate on these rates.
@@tonydebling no worries, it's just I already have maths tutor and they do 1 hour for £35
@@albinalex6435 bros really negotiating with the maths teacher
can you make a similar video but on A2 stuff pls?
how did you get 352 for the trig identities?
Arcsin(0.1381)=7.94, sin is negative in the 3rd and 4th quadrants, so to solve sin x = -0.1381 we have x= 180 + 7.94=187.94 and x = 360 - 7.94 = 352.06
Can i use this for ocr???
Yep, It's fine for OCR.
for 12:00 shouldn't you do the negative reciprocal for the gradient? so it should be -2/7
You've been asked to find the equation of the tangent so you just use the value of dy/dx. You would use the negative reciprocal if you wanted to find the equation of the normal.
@@tonydebling oh so if only it says ''normal'' you do the negative reciprocal but when its tangent you use the normal gradient.
the reason why I thought you did it was because tangents are perpendicular to the circle and my teacher said do the negative reciprocal
@@1My3My9 Tangents aren't perpendicular (at right angles) to circles they touch the circumference (tangere is to touch)
@@tonydebling oh thanks
Got my maths AS exam tomorrow and still cant figure out how you got p=7.5 on that first log+exponential question 🤦
nevermind! figured it out! e^0 would equal 1 so 1p=7.5: p=7.5 this video is incredibly helpful ❤
@@poscii754 Man hope the exam went well, I have my year 12 mocks next week so practicing AS too.
Your vids are very helpful however i don’t get how you got the two in the first question
Add 1 + Sin(^2)x to both sides
Why do we have to add 1?
Hello to everyone watching this the night before exams ✌️
Which as level maths is easy Cambridge or edexcel?
Hey, I can't really say. These days the A level syllabuses are much more closely aligned so there shouldn't be much difference in difficulty. I think the availability of resources and the level of service provided by the exam boards are more significant, but on these matters I cannot comment.
Where is the sketching graph and binomial expansion
In the video before this one
Hi! not sure if this is a little late but its over here - ua-cam.com/video/ZyGlXmroHyo/v-deo.html
15:47
Can you make one of these for A2 please
I've done A2 Mechanics and A2 Statistics
@@tonydebling are you planning to make any videos for pure?
Where did you get this paper from?
I pulled questions from various revision sets provided by Edexcel.
@@tonydebling ah because I’m trying to find the model worked solutions
@@unknownzzz9089 what do you expect beyond text in videos?
@@tonydebling Yes as you need method to get full marks in exam
The first question, their is a another step to get to the required form which you don't show
Is this also with cambridge
Cambridge usually prefers writing an equation for ex. y = 2x+3 instead of y = f(x) most of the times.
At 5:42 why is -7/3x^-1/2, shouldn’t it be just to the power of 1/2, not -1/2 as -7^1/2*1/3x^-1/2=-7/3x^1/2
It's the brackets ...
(-7/3)x^(-1/2) = -7/(3x^1/2)
Hope that helps?
Where do u get ur questions from
Edexcel past papers and sample papers
@@tonydebling thanks mate love the vids helping me through a level
I’m gonna fail the exam
Did u fail?
me too(
i have mocks today hahahahahaha it’s in an hour im so fucked man
Ending up getting Ds in my y12 mocks, in the same boat g
I got my mocks tomorrow I’m finished
Can i use this for ocr???
Yes, OCR syllabus is the same as Edexcel