It looks maybe possible. And how can you convert xor-gate into transistor level circuit? And if circuit has pass-gates how can it be handled with this method?
the CMOS transistors only provides the complementary functions (outputs), to get rid of that complement at the end attach the output to an invertor which needs 1 NMOS and 1PMOS
Thanks for explaining
very easy and informative
Do you have video for NMOS logic implementation.
Thanks mam
It looks maybe possible.
And how can you convert xor-gate into transistor level circuit?
And if circuit has pass-gates how can it be handled with this method?
Thanks
Just now I related to pmos and. Nmos states nmos in dot with parallel
(A'+ BC)'.... How to solve this
Can we use inverter for A'... Or other method for simplification...
First generate A' using inverter, then implement the whole function. In CMOS logic, no other method is used.
@@ExploretheWAY can't we take directly A' ?
A' is not another variable. Which is derived from A. A' means complement of A. So we must use an inverter with input A.
what about the bar?
the CMOS transistors only provides the complementary functions (outputs), to get rid of that complement at the end attach the output to an invertor which needs 1 NMOS and 1PMOS
Hi I need some help
A.(B+C)+(D.E)
what happened to the complement of the boolean function then???
The structure of CMOS itself produces an output in complementary form.