Great question and nice way of solving it, fully understood and grasped what you did, we need a few more like these. A walk through video for PP1/2 would be appreciated.
Thank you for making insightful videos.👍 Have almost watched all your quant videos !!! Great content which helps in solving tough problems and saves a lot of time on the GRE.
u can assume that all numbers are consecutive, and the average is equal to the first and last num divided by two. then the least is 14 and the largest is 24. it is much faster.
I have done this in a different way and got it right. (Smallest num+largest num)/2 = 19 That means (x+2x-4)/2 = 19 That gives x=14, so largest num is 24. Median is 20. So second largest must be between 20 and 24. So the second largest is 23. Is my method okay? Or it just happened coincidentally?
Bro, you're taking way longer than an applicant has on an actual GRE/GMAT. There's gotta be some tricks to quickly figure out the answer. We may get questions like these right on the exam but may miss out on 6-7 points by being left out with questions yet no time. Appreciate your efforts though!
I feel bad for anyone who's studying for the GRE/GMAT and hasn't discovered your channel
Word
Your videos are wildly underrated.
Discovered your channel today, I have my GMAT in 5 Days and this feels like a boon. Thank you so much
Your channel is highly underrated!!!
Great going Phillip ! you devote a lot of time in research , I must say.
Great question and nice way of solving it, fully understood and grasped what you did, we need a few more like these. A walk through video for PP1/2 would be appreciated.
Amazing video!!! Finally got to understand the concepts of these type of questions!!!thank you so much!
Could you please make more videos on this?
I found this really helpful ,thank you!
Thank you for making insightful videos.👍 Have almost watched all your quant videos !!! Great content which helps in solving tough problems and saves a lot of time on the GRE.
Well done Manish! That's a lot of videos you have done
After a long time you come back...
Most awaited video.
Thank You Philip ❤️
Thanks Sumaiyaara. Won't be so long next time
Great video Philip! you should definitely do more of these
A fantastic summary question incorporating many different elements!
Thanks Philips . You are great
Great question! More GMAT questions please :)
Great video Philip! 👍
Another great video, thank you!!!
great going Philip!! almost done with your GRE quant videos. Any suggestions of best websites for GRE quant practice tests and quizzes??
i solved it in first try Um so happy 😊
Great question. Thanks.
Hello :) Thank you for making insightful videos. How do I reach out to you in case of doubts?
Thank you for your videos :)
u can assume that all numbers are consecutive, and the average is equal to the first and last num divided by two. then the least is 14 and the largest is 24. it is much faster.
Why would all numbers be consecutive? Mean doesn’t equal median
@@TheTestedTutor yes, u r right 😅, but unfortunately they have the same answer
More verbal questions please ☺️
I have done this in a different way and got it right. (Smallest num+largest num)/2 = 19
That means (x+2x-4)/2 = 19
That gives x=14, so largest num is 24. Median is 20. So second largest must be between 20 and 24. So the second largest is 23. Is my method okay? Or it just happened coincidentally?
The concept you applied is right too, but if the options were skewed betwixt 21, 22, 23, you'd still have had to apply further optimization...
i did
2x-7 = 20
13.5 ~ 14
using value of x in 2x-5
(2*14)-5 = 23
is it right to consider this approach
Thank you ❤️
what is pupose of median in this problem.
To give you a lower bound for the middle numbers
you sound fine even now :)
165 level question for sure
Bro, you're taking way longer than an applicant has on an actual GRE/GMAT. There's gotta be some tricks to quickly figure out the answer. We may get questions like these right on the exam but may miss out on 6-7 points by being left out with questions yet no time. Appreciate your efforts though!