19.2 How to Balance Redox Reactions (Half-Reaction Method) | General Chemistry
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- Опубліковано 5 сер 2024
- Chad provides a detailed lesson on how to balance redox reactions (i.e. oxidation-reduction reactions) specifically using the half-reaction method. The lesson begins with an introduction to redox reactions showing how to identify the species being oxidized and the species being reduced and then the reducing agent (aka reductant) and oxidizing agent (oxidant). Two examples of balancing redox reactions are then worked out. The first doesn't have any H+ in the net reaction and so there ends up being no difference between balancing it under acidic conditions vs basic conditions. But the second is balanced both under acidic conditions (the default) and basic conditions. Chad demonstrates that the difference between the two involves neutralizing all the H+ in the reaction.
I've embedded this playlist as a course on my website with all the lessons organized by chapter in a collapsible menu and much of the content from the study guide included on the page. Check this lesson out at www.chadsprep.com/chads-gener...
If you want all my study guides, quizzes, final exam reviews, and practice exams, check out my General Chemistry Master Course (free trial available) at www.chadsprep.com/genchem-you...
00:00 Lesson Introduction
00:27 Introduction to Redox Reactions
05:17 How to Identify Oxidizing and Reducing Agents
09:08 How to Balance Redox Reactions in Acidic Solution Example #1
21:17 How to Balance Redox Reactions in Acidic Solution Example #2
27:17 How to Balance Redox Reactions in Basic Solution
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You've been a life saver, Chad! We are using the same textbook, so these lessons line up perfectly. I wish I would've found you earlier in the semester!
Thanks for saying so - Happy Studying!
An absolute life saver. Thank you for making these videos!!!
You're welcome, Alyxia!
Brilliant video as always. Commenting for algorithm because you deserve everything and more your building the future of healthcare right now.
Very much appreciated - Thank you!
This man helped me secure an A+ in gen chem. I cant thank you enough for providing the service you do. Cheers Chad!
Kudos - glad to hear it!
Yep you just saved my grade yet again!!! Thank you so much, you're a blessing!!!
Glad to hear it - Happy Studying!
The best explanation I heard for them so far 👌🏻
Thank you
Know that we find these videos super helpful here at Lehigh University, great stuff:)
Glad to hear it, Veronica!
Amazing work. You're a great teacher.
Thank you very much!
Chad in true form. We chem students salute you!
All the best!
Dude thank you so much. You cleared this up for me.
Glad to hear it!
This is amazing! Thank you.
You're so welcome!
Best teacher out there wish I found this earlier in my chem gurney!!
Better late than never, I suppose. I wish you all the best on your journey as you travel on your gurney!
Great work 👏
Thank you
you are amazing, thank you!
You're welcome and Thank You!
❤ Thanks chad i really appreciate
You're very welcome.
I LOVE YOU CHAD
Glad the channel is helping you!
YOU ARE AMAZING!
Thank you!
Hey Chad! Love your videos. We just got to this chapter in my class, is there any way we can access the other videos early?
Hi Lexi! I don't have them available early. However, this playlist is simply a replacement for my old General Chemistry playlist. I've updated the curriculum (and improved the video quality), but this entire chapter is already complete in my old playlist as well. You'll find the first lesson for the chapter on electrochemistry here: ua-cam.com/video/J3KvS6M1YZs/v-deo.html
Hope this helps!
Nice sir!
Great!
Hi thank you soo much for this great content! You're truly a life saver! Can you please make a video on the oxidation number method in balancing? If not, can you please tell me when to use this method or that method cause it's kinda confusing, I'd be very thankful for that.
Hey Leen, are you struggling with a particular part of the video?
@@ChadsPrep no it's very clear 😊thanks a lot for your help
Hi, for the first reaction dont we add 6electron because (8-6=2) ?
Hey Malia! I see your reasoning but it is the reactant and product side of each reaction that must be balanced in that step rather than the oxidation reaction charge balancing the reduction reaction charge (writing the overall reaction those will cancel out in the end) So if we look at the top reaction with 8H+ on the product side, the reactant side has zero charge so the product side must add 8 e- to make the product side zero. Hope that helps!
In the beginning of the video why is the charge on oxygen -1 and not -2 like it usually is?
To balance the charge of the hydrogen
Do you by chance have any videos on redox titrations? Thank you!
Hey Katie, try this video: ua-cam.com/video/kSfs0WenLXo/v-deo.html
We'd never punch you, Chad.
Never say never! ;-)
Why punching? Why not a student loves your videos so much that they go to your house to give you a high five?
😁😁😁
I think it was an attention grabber!
Jesus! @@ChadsPrep
Jesus loves you!! Jesus died for your sins on the Cross amd today is the Day to surrender your life to Him!
@@neaworld3960 Indeed!
thank you im from Algeria
Happy to have you here!
@@ChadsPrep 🥰🥰🥰
Happy Studying!
AP chem hard :(
You can do it!
Punched in the face 😅
🫡💯
Thanks!