Units of h and Compton wavelength of particles

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  • Опубліковано 19 гру 2024

КОМЕНТАРІ • 39

  • @MikhailEschatologist
    @MikhailEschatologist 4 роки тому +38

    Your lectures are completely mind blowing, i'm binge watching them like some kind of TV show

  • @judesalles
    @judesalles Рік тому +2

    Thank you Professor Barton Zwiebach for such a delightful lecture. What a treat!

  • @shreeniwaz
    @shreeniwaz 4 місяці тому

    This lecture solved an ever standing mystery for me regarding the term 'electron spin'.. Thank you Sir..

  • @nataliiaproshunina-lc5gm
    @nataliiaproshunina-lc5gm 2 місяці тому

    Professor! Thank you for very inspirational lectures!

  • @stevestronghold7786
    @stevestronghold7786 6 місяців тому +1

    SIr does this length associated with a given mass at 6:20 is planck's length

  • @atikabrarsourov7500
    @atikabrarsourov7500 3 роки тому

    love u legend, love u MIT

  • @perriannesimkhovitch1127
    @perriannesimkhovitch1127 2 роки тому +1

    The equivalent of having access to lectures from a cell in the movie midnight Express

  • @nataliatarnovsky6997
    @nataliatarnovsky6997 5 років тому +3

    🏃‍♀️❤🖤💛Las matemáticas son tan interesantes como una gran obra de , Lev Tolstoy...😀😃🤷‍♂️🤦‍♀️🤷‍♀️🙋‍♀️🙋‍♂️🏃‍♂️🏃‍♂️🤦‍♂️🙋‍♀️😀😄😀😀😀

  • @Physics2001ideas
    @Physics2001ideas 3 роки тому

    Just awesome

  • @adriangheorghe2327
    @adriangheorghe2327 4 місяці тому

    h=(Uf.If.Tf).(k.Tf)=Wlu.Df. Uf=Qe/Re (V) ; If=Qe/Tf (A) ; Tf=1/Ff (s) ; Df=k.Tf (s) ; k =9.10^9 (unde) ;Pentru un foton oarecare, de frecventa Ff numarul de unde este ; Nlu=k.(Ff/Ffae) ; Ffae=1,23726.10^20 (Hz) este ffrecventa fotonului gama electronic de la anihilarea electronului cu pozitronul.
    Wlu=p.V=a^2.V=(L^2/T^4).L^3=(formula lui Poynting).L^3

  • @KadhumJehhef
    @KadhumJehhef 4 місяці тому

    very amazing good

  • @DR-kh9bl
    @DR-kh9bl 4 роки тому

    When do you use (h), and when do you use (h bar)??

    • @jacobvandijk6525
      @jacobvandijk6525 4 роки тому +3

      h-bar times c = almost 200 Mev.fm ; it's just a convenient number in calculations. Watch the previous video (L3.1).

    • @athul_c1375
      @athul_c1375 3 роки тому +1

      hbar is equals to h over 2pi

  • @jyotishrajthoudam
    @jyotishrajthoudam 2 роки тому +1

    It is better with leaving something here rather than passing by without leaving anything.

  • @nibussss
    @nibussss 3 роки тому +1

    Buddha said not much attachment to things as it affects Ur happiness.....I notice I feel sorry for inanimate objects....it's an exercise in detachment?
    Not to be done always....?
    I dunno....I think I'm weirder

  • @nibussss
    @nibussss 3 роки тому

    R is back when center was earth?

  • @vychuck
    @vychuck 4 роки тому +5

    Square brackets means Dimensions rather than units

  • @tag_of_frank
    @tag_of_frank 4 роки тому

    So if a particle is standing still, it's potential energy = 1/2 m * c^2 ? Where does that come from? (Prof said it is rest energy of particle)

    • @eddyestevez500
      @eddyestevez500 4 роки тому

      Particle with mass have energy even when they are standing still (E = m c²). The total energy of a particle is this energy plus their kinetic energy.

    • @tag_of_frank
      @tag_of_frank 4 роки тому

      @@eddyestevez500 So just because they have energy means they have velocity? Why bastardize the notion of momentum?

    • @eddyestevez500
      @eddyestevez500 4 роки тому +5

      @@tag_of_frank So just because they have energy means they have velocity? No! A particle at rest has energy in the sense that their mass is equivalent to energy according to E =mc^2. This is Einstein's relativity. The fact that a particle at rest has energy (due to their mass) does not mean the particle is moving or has momentum.

    • @tag_of_frank
      @tag_of_frank 4 роки тому

      @@eddyestevez500 Thanks. I'm thinking about de Broglie wavelength lambda = h/p. Its weird to have a wave for a particle at rest.

  • @tylerfreeman5041
    @tylerfreeman5041 5 років тому +1

    I'd love to tell you where you lost me..... so specific

  • @marwanmaatouk6446
    @marwanmaatouk6446 2 місяці тому

    How do we stop watching this course? 😂

  • @nataliatarnovsky6997
    @nataliatarnovsky6997 5 років тому +1

    🏃‍♀️❤🖤❤Es el Mit ?😀🤓🤓🙋‍♀️🤦‍♂️👱‍♂️👱‍♀️👱‍♀️😀😀🙋‍♀️

  • @perriannesimkhovitch1127
    @perriannesimkhovitch1127 2 роки тому

    Any physics I might contribute was destroyed for I was raped, butchered and permanently disfigured in an interstate physicians ceremony
    With parts made near Hanford Nuclear facility

  • @abdou290
    @abdou290 5 років тому

    You mean dimensions of h

  • @jackmaxwell3134
    @jackmaxwell3134 3 роки тому

    "de Broglie" is pronounced "duh-BROY " (more or less)

    • @Labroidas
      @Labroidas 3 роки тому +1

      I've heard everything from "De-Brolie" over "De Broil" to "De Broggly", I don't think anymore that anybody really knows how to pronounce that name

    • @jackmaxwell3134
      @jackmaxwell3134 3 роки тому +2

      @@Labroidas Well, it's not so important. I guess nobody pronounces Arabic or Chinese names the way they pronounce it themselves so...

    • @AdenKhalil
      @AdenKhalil 3 місяці тому

      ​@@Labroidas" broggly'' is better since the guy was French

  • @benjaminkinga8304
    @benjaminkinga8304 6 років тому

    last.

  • @ゾカリクゾ
    @ゾカリクゾ 6 років тому

    first