Simplifying a Radical Expression in Two Ways

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  • Опубліковано 8 вер 2024
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КОМЕНТАРІ • 20

  • @andylee63
    @andylee63 11 місяців тому

    Nice trick!

  • @mcumer
    @mcumer 11 місяців тому

    Another way: we can factorize 17+12sqrt(2) and therefore we but a^2+b^2=17 and 2ab= 12 sqrt(2).. if we put a^2=8 and b^2=9 , we obtain a=2 sqrt(2) and b=3.. the factorization is (3+2sqrt(2))^2.. simplifying the radical it becomes a square root.. factorizing 3+2sqrt(2) is easy ( 3=1+2 ..).. finally we can simplifly the square root

  • @scottleung9587
    @scottleung9587 11 місяців тому

    I used a method similar to your second.

  • @SergeySvotin
    @SergeySvotin 11 місяців тому

    Also it's really simple sum, you can easily dissolve it as (3 + 2sqrt2)^2 which can be further dissolved as (1 + sqrt2)^4, all you have to do is to add +- when you apply sqrt on every step

  • @mbmillermo
    @mbmillermo 11 місяців тому +4

    Very cool. Another way to do it: Take the square root twice! Assume that √(17+12√2) has the form √a+√b. Then (√a+√b)² = a+b+2√(ab), so a+b=17 and ab=72. Thus a and b are 8 and 9 and we have √(17+12√2) = 3+2√2. Do it again and we get a+b=3 and ab=2, so a and b are 1 and 2 and our final solution is 1+√2.

    • @forcelifeforce
      @forcelifeforce 11 місяців тому +1

      (√a + √b)² = a + b + 2√(ab) You need grouping symbols for the radicand because it is a product.

    • @mbmillermo
      @mbmillermo 11 місяців тому

      @@forcelifeforce - I'm glad you were able to understand me! You probably know the binomial formula. Next time I'll use parentheses.

    • @mbmillermo
      @mbmillermo 11 місяців тому

      @@forcelifeforce - Oh, I can edit it. I'll do that now.

  • @alextang4688
    @alextang4688 11 місяців тому

    Simply two times for square root.😋😋😋😋😋😋

  • @SergeySvotin
    @SergeySvotin 11 місяців тому +1

    9:35 and that brings us to -1-sqrt2, (1+sqrt2)i and -(1+sqrt2)i

  • @tryingtomakeanamebelike7245
    @tryingtomakeanamebelike7245 11 місяців тому +1

    Method on how to solve
    Convert 12root(2) into 2root(72)
    Check roots that multiply to 72 and add to 17
    3 and 2root(2) work
    However these factors can also be simplified to (root(2) + 1)^2
    Meaning we have (root(2) + 1)^4
    Answer is root(2) + 1
    Edit: I know this thought process was basically method 2 but I did the problem before watching the video you gotta believe me

  • @miguellumbombo9886
    @miguellumbombo9886 11 місяців тому

    Mas... no primeiro método, k=1/2 também verifica. Basta racionalizar o denominador e aplicar propriedade comutativa.

  • @QuoraWorld
    @QuoraWorld 11 місяців тому

    Mind blowing sir😊😊👍👍👍👍🌹🌹🌹🌹🌹🌹🌹🌹🌹🌹🌹🌹🌹🌹

  • @teambellavsteamalice
    @teambellavsteamalice 11 місяців тому

    I used the second method in my head, very fast to factor 17&72 and then 3&2.

  • @giuseppemalaguti435
    @giuseppemalaguti435 11 місяців тому

    1+√2

  • @Murlica
    @Murlica 11 місяців тому

    simplifying brings me to 2 results: sqrt(2)+1 and -sqrt(2)-1

  • @pmccarthy001
    @pmccarthy001 11 місяців тому

    Channel a+bi... Having trouble searching for that. Getting numerous results. Does anyone know what channel he's referrng to?

  • @broytingaravsol
    @broytingaravsol 11 місяців тому

    very easy

  • @SergeySvotin
    @SergeySvotin 11 місяців тому

    8:06 so you lost to mere numbers once again and missed one real and 2 complex solutions for this one -_-