Squeeze Theorem Explained | Calculus 1

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  • Опубліковано 9 лис 2024

КОМЕНТАРІ • 9

  • @WrathofMath
    @WrathofMath  Місяць тому

    Support this course by joining Wrath of Math to access exclusive and early Calculus videos, original music, plus lecture notes at the premium tier! ua-cam.com/channels/yEKvaxi8mt9FMc62MHcliw.htmljoin
    Calculus 1 Exercises playlist: ua-cam.com/play/PLztBpqftvzxUEqGGgvL3EuIQUNcAdmVhx.html
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  • @rimuru-kun_x_ciel-chan
    @rimuru-kun_x_ciel-chan 19 днів тому

    The amazing simplicity of this video is going to save me from my calculus 1 exam tomorrow. I subconsciously knew what was going on but didn't understand consciously how to use the squeeze theorm.
    On a side note why does this video not have more views, this video simply explains everything very easily and simply. I also learned IVT, MVT and EVT from this and it helped a lot

  • @surfrb
    @surfrb Місяць тому +1

    This is actually so helpful wow my teacher is about to cover this tomorrow but this quick video is gonna give me a great head start. Thanks man!!!

    • @WrathofMath
      @WrathofMath  Місяць тому

      Glad to help, many more Calculus videos coming in my series! Good luck in your class!

  • @JenilMansuriya
    @JenilMansuriya Місяць тому

    Can you cover probability and statistics will be helpful for this semester 👍

    • @WrathofMath
      @WrathofMath  Місяць тому

      Yes, I am actually working on the statistics course now, which will of course get to probability eventually! ua-cam.com/play/PLztBpqftvzxXIKQH2GUoqrJOMLbvAckV5.html

  • @moazamabbasi1899
    @moazamabbasi1899 Місяць тому +1

    I think your diagram has a mistake since you have mentioned in the inequality that g(x) is less than or equal to h(x) for all x, then why the graph of g is above h near x=0😮, since you've mentioned it is an open interval.

    • @WrathofMath
      @WrathofMath  Місяць тому

      "near" x=0 just means some open interval centered at x=0, which can be as small as we need it to be. in the diagram g is greater than h on the left to show that it's fine if g is greater than h somewhere far from x=c, what's important is that eventually, as we approach c, there is some space around it where the inequality is satisfied

    • @moazamabbasi1899
      @moazamabbasi1899 Місяць тому

      @@WrathofMath wow, I actually don't know, what was I thinking about open interval at that moment when I commented. Your explanation is spot-on. 🌚👍😌