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I studied Calculus some 50 years ago during my high school years and later heavily used it during my college time. Since graduation, I had not used it and so I had almost forgotten how to prove it using limit theory. Recently I wanted to teach my son on Calculus. So, I watched your video and found your explanation very easily to understand. Thank you.
Beatiful explanation, much easier to understand and remember than the one on my textbook (which looks like a trigonometry properties show-off), thank you!
Thank you Ezra! I actually feel like I flubbed parts of this, but I'll leave it up for now and see if people generally find it helpful. I get pickier and pickier as the years go on, so maybe it's just me being a freak!
Math is really the only discipline based on the fundamentals. You have to know everything from grade school to trig in order to even hope to understand the big boy/girl language of science.
Because tan area is containing sector area and also sector area doesnt fill the tan area. Thats why this theorem only works with theta approaching 0 i.e. very small angles
That is technically circular reasoning. L'Hopital's rule requires you to take the derivative of sine. The derivative of sine relies on the limit we are trying to prove here.
Hey it's just a thought but we know sinx for very small values of x is similarly equal to x, right. Then the limit would be lim x-> 0 (x/x) . We can cancel out the x and get 1. Can this be a ideal solution though ?
@@WrathofMath You are right, I searched on it and came to know that it does come from this limit. Didn't know about it, I just kinda looked at the graphs, and some questions that use this approximation.
Nicely done! It's been nearly four decades, but I'm pretty sure this is how I learned it from Apostol. (The book, not the man; he'd retired from teaching freshmen the year before.)
Thanks Tom! This is always how I have seen it done in textbooks, though I've never had the pleasure of reading Apostol! I've been shopping for his books recently, they're just so expensive.
Good question, and this part of the otherwise excellent proof here is guilty of 'hand waving.' But yes, the best way is to do a proof by contradiction. Just assume that the order of the areas are not as he states and you'll find contradictions which will prove that the area inequalities are valid!
@@yemoeaung251you need to explain why that is, because there is nothing occurring which is circular reasoning, and the justification for the inequalities arises because of basic geometry and geometric arguments
@@immutabledestiny6377 The derivation of area involved that limit itself. A lot of the textbooks out that are doing this proofs which is not rigorous at all.
@@yemoeaung251People just don't care. What's in the video is more of an illustration, rather than a rigorous proof. Although, some of the book authors sometimes note that this illustration is not a proof with the same reasoning that u said
![Proofs: Lim sinx/x =1 and lim [cosx -1] /x =0 as x goes to zero from geometry](http://i.ytimg.com/vi/W0jiodfVGx0/mqdefault.jpg)
![Proofs: Lim sinx/x =1 and lim [cosx -1] /x =0 as x goes to zero from geometry](/img/tr.png)
Support this course by joining Wrath of Math to access exclusive and early Calculus videos, original music, plus lecture notes at the premium tier! ua-cam.com/channels/yEKvaxi8mt9FMc62MHcliw.htmljoin
Calculus 1 Exercises playlist: ua-cam.com/play/PLztBpqftvzxUEqGGgvL3EuIQUNcAdmVhx.html
Calculus 1 playlist: ua-cam.com/play/PLztBpqftvzxWVDpl8oaz_Co6CW50KtGJy.html
I studied Calculus some 50 years ago during my high school years and later heavily used it during my college time. Since graduation, I had not used it and so I had almost forgotten how to prove it using limit theory. Recently I wanted to teach my son on Calculus. So, I watched your video and found your explanation very easily to understand. Thank you.
😂😂
Beatiful explanation, much easier to understand and remember than the one on my textbook (which looks like a trigonometry properties show-off), thank you!
Best explanation on the internet of this theorem. Bravo, sir!😊
Thank you Ezra! I actually feel like I flubbed parts of this, but I'll leave it up for now and see if people generally find it helpful. I get pickier and pickier as the years go on, so maybe it's just me being a freak!
@@WrathofMath Picky is good in math! 😁
@@punditgi or sunao pandit ji tum yaha kya kar rahe 😂 btw me too bramhan (purohit ❤)
2:23 For mnemonic purposes, I'm going to note that the area formula with *Sin* is the *Smallest,* while the one with *Tan is the Tallest.* 😅
The best explanation so far.
Thank you!
thank you bro needed that proof for my studies
Thank You. Great explanation.
nice explanation, I saw this in my calc textbook but this explains the steps very well
Glad it was helpful!
sehr sehr strak, grüße aus Deutschland
What software are you using to write and annotate the explanation?
Great explanation.
Thank you!
Your videos are excellent!
Thank you!
Finally a channel that uses the squeeze theorem correctly 😅
Thanks for watching!
THE GREATEST VIDEO ON THE INTERNET!!!!!
THANK YOU SO MUCH SIR THIS WAS EXTREMELY HELPFUL
Math is really the only discipline based on the fundamentals. You have to know everything from grade school to trig in order to even hope to understand the big boy/girl language of science.
Can you use the squeeze theorem to prove that the limit as x approaches 0 of (cos(x) - 1)/x is 0?
How do you prove that the tan area is larger than the sector area? Since the sector is curved?
Because tan area is containing sector area and also sector area doesnt fill the tan area. Thats why this theorem only works with theta approaching 0 i.e. very small angles
Very nice, clear explanation, with simple, clear diagrams. Well done.
Many thanks!
thanks, this is a great explanation.
Glad it was helpful! Thanks for watching!
thank you
bro ur so energetic ty
Great explanation as always...you have knowledge and talent to deliver informatiin...Respect from lebanon
Thank you!
Great exercise, thank you
My pleasure - thanks for watching!
What a nice explanation
Thank you!
But what if we will take the radius of the circle other than 1??
I use hopital for the last problem. What are alternative approaches that we can use?
That is technically circular reasoning. L'Hopital's rule requires you to take the derivative of sine. The derivative of sine relies on the limit we are trying to prove here.
Hey it's just a thought but we know sinx for very small values of x is similarly equal to x, right. Then the limit would be lim x-> 0 (x/x) . We can cancel out the x and get 1. Can this be a ideal solution though ?
I would say the fact that sinx is similar to x near 0 is proven by this limit, certainly not the other way around!
@@WrathofMath You are right, I searched on it and came to know that it does come from this limit. Didn't know about it, I just kinda looked at the graphs, and some questions that use this approximation.
I loved this video
Thank you!
thanks a lot
limit((1-cos(x))/x,x=0) = limit((cos^2(x/2)+sin^2(x/2)-cos^2(x/2)+sin^2(x/2))/x,x=0)
=limit(2sin^2(x/2)/x,x=0)=limit(sin(x/2),x=0)*limit(sin(x/2)/(x/2),x=0)=0*1
I finally understand this concept after watching this clear explanation ! Thank you.
Glad to help - thanks for watching!
loved the explanation, thanks a lot 🫠🤩🤩
Thanks for watching!
Nicely done! It's been nearly four decades, but I'm pretty sure this is how I learned it from Apostol. (The book, not the man; he'd retired from teaching freshmen the year before.)
Thanks Tom! This is always how I have seen it done in textbooks, though I've never had the pleasure of reading Apostol! I've been shopping for his books recently, they're just so expensive.
Is there any proof for the order of areas?
Good question, and this part of the otherwise excellent proof here is guilty of 'hand waving.' But yes, the best way is to do a proof by contradiction. Just assume that the order of the areas are not as he states and you'll find contradictions which will prove that the area inequalities are valid!
@@PapaBavarianthanks man
wow
Thanks for watching!
Making use of area to derive the inequality is circular reasoning.
Pun intended?
@@zat5176 No, think of how area is being derived and see why it is circular.
@@yemoeaung251you need to explain why that is, because there is nothing occurring which is circular reasoning, and the justification for the inequalities arises because of basic geometry and geometric arguments
@@immutabledestiny6377 The derivation of area involved that limit itself. A lot of the textbooks out that are doing this proofs which is not rigorous at all.
@@yemoeaung251People just don't care. What's in the video is more of an illustration, rather than a rigorous proof. Although, some of the book authors sometimes note that this illustration is not a proof with the same reasoning that u said
make non sense
Because you are a fool