I told myself that when I became a licensed chemist, I would come back to your channel and express my gratitude. Your lecture videos were a huge help in solidifying my foundation in the basics, and your thermodynamics lesson greatly helped me in answering the theoretical questions in the board exam. Again, thank you, Chad's Prep, and all the staff behind this team. You helped me become a licensed chemist.
it has been said that q and w are not state functions however it has been also said that enthalpy is one of the state functions and equals to heat change while the reaction is actualizing under constant pressure. we are equalizing deltaH as a state function to qp which is not? i have an issue in there, do i think on the wrong way or missing out something? (p.s. you're excellent, t.y. 4 everything, you're saving me rn)
Sir you said enthalpy of formation forms 1 mol of a single product but as for NO in your last calculation example, it formed a double product of N2O + NO2. Why did you still call it an enthalpy of formation reaction.
based on how i understand it, he showed in the last example how enthalpy of formation can simplify calculating the enthalpy changes of a reaction. We can simply take sum of the enthalpies of formation of each product and reactant, which are experimentally determined, and then subtract the values of products and reactants to find the delta H of the entire reaction. hope that makes sense (I'm only studying for the mcat, so my knowledge is not in-depth)
I told myself that when I became a licensed chemist, I would come back to your channel and express my gratitude. Your lecture videos were a huge help in solidifying my foundation in the basics, and your thermodynamics lesson greatly helped me in answering the theoretical questions in the board exam. Again, thank you, Chad's Prep, and all the staff behind this team. You helped me become a licensed chemist.
Glad the channel was able to help you achieve your plans - Kudos and Congrats!
Whenever I feel hopeless on a chapter, I turn to chad's prep. Esp helpful since I got no lectures in my class
Glad the channel helps - Happy Studying!
Dear professor you are indeed a great teacher .God bless u with a lot of success.😊
Thank you very much. All the best to you.
You explain it so much easier and more concisely than my own professor, thank you!!!
Glad the channel is helping you, Nathan!
In which grade this topic is
@@ShaliniSingh-vj1lh this topic comes up on the last two years of high school, depending on your school's curriculum, in General Chemistry.
Thanks, Chad, you do a great job, and I'm grateful to have access to your expertise. Damian
You're welcome and Thank You.
Super high quality videos!
Thanks for saying so!
You’re an excellent teacher ✨.
Thank you.
u r the best ... from Algeria
Thank you from USA - Happy Studying!
thank you so much! this was helpful.
You're welcome!
You're a real Chad, Mr. Chad.
Haha, thanks!
Thank you so much u have really helped me
You're welcome - glad to hear it!
Keep making videos 🔥🔥🔥
Will do!
it has been said that q and w are not state functions however it has been also said that enthalpy is one of the state functions and equals to heat change while the reaction is actualizing under constant pressure.
we are equalizing deltaH as a state function to qp which is not?
i have an issue in there, do i think on the wrong way or missing out something?
(p.s. you're excellent, t.y. 4 everything, you're saving me rn)
Powerful 🙌🏿🔥
Thank you
You are goated Kind sir 🙏🏾🔥
Thanks!
Love your video and your videos system ❤️
Excellent!
I have my AP Chemistry Midterm exam tommorow. Wish me luck :)
All the best!
A little confused, how do you know when to use hess's law or enthalpy of formation?
THEY CALL HIM CHAD FOR A REASON
😁😁😁
I love you so much😭😭😭😭❤️❤️❤️❤️❤️
Glad the channel is helping you - Happy Studying!
Where can thermodynamic data be found? Will it be provided in every problem?
you wouldn't be expected to memorize it so yes it will be provided unless you have a very mean Professor!
thanks you so much!!!!!
Very welcome.
Sir you said enthalpy of formation forms 1 mol of a single product but as for NO in your last calculation example, it formed a double product of N2O + NO2. Why did you still call it an enthalpy of formation reaction.
based on how i understand it, he showed in the last example how enthalpy of formation can simplify calculating the enthalpy changes of a reaction. We can simply take sum of the enthalpies of formation of each product and reactant, which are experimentally determined, and then subtract the values of products and reactants to find the delta H of the entire reaction. hope that makes sense (I'm only studying for the mcat, so my knowledge is not in-depth)
Chad: if you get enthalpy of formation kiss your professor
Me who’s homeschooled😢
Sir your teaching outstanding but please speak slower a bit.Meaning to say you are fast.
I get that a lot - best solution is you can adjust the playback speed in the settings. Happy Studying!
27:58 instructions unclear now i'm in jail
what are you struggling with?
He kissed his professor
haha... **disclaimer** Chad's Prep does not condone non-consensual physical contact with Professors...
I am not attending Chemistry lecture on this again
Why announce
Haha ha "bagel piehole. Bagel piehole" 😂 good video. Very informative)
Excellent!