i did really well at maths at GCSE but when it came to Alevel i felt useless. I got a U on mechanics 1 twice (dont ask how) and thought third time lucky, i think everyone lost faith, but finding these videos has helped so so much. Just recently got a B on my resit mock. so happy, going to keep practicing and watching these videos til I get that A! So thank you so so much, what you're doing is really great!
great video, thanks a lot, only thing is, how would you go about working out the answers if the string was extensible and/or the pulley was rough? you would have more than 2 unknowns..?
*maths would you ever consider incorporating the ccea syllabus? It's very similar although there irate different moments questions. There's not much online for ccea and it would be fantastic if there was something like what you do, just a thought
I'm a little confused to where I might have went wrong. I got T-6.79+2gSin30+2a Then I got T= 6.79+2gSin30+2a Substituting that into 4g - T = 4a got me 4g - 6.79+2gSin30+2a=4a Taking away 2a from both sides give me 4g-6.79+2gSin30=2a which is then 39.2 - 16.59 = 2a 22.61 = 2a a = 22.61/2 i got a as 11.305 Help me out please although Im going to redo the question and If anything changes Ill remove this comment or post another one
Check this out www.examsolutions.net/tutorials/resolving-forces/?level=A-Level&board=Edexcel&module=Mechanics%20A-Level&topic=1632 I hope it answers your question
Thank you for your clear explanation. I am really struggling with the mechanics. It's immensely helpful to have your videos to refer to.
i did really well at maths at GCSE but when it came to Alevel i felt useless. I got a U on mechanics 1 twice (dont ask how) and thought third time lucky, i think everyone lost faith, but finding these videos has helped so so much. Just recently got a B on my resit mock. so happy, going to keep practicing and watching these videos til I get that A! So thank you so so much, what you're doing is really great!
how did you do?
Thank You very much. M1 has been the toughest for me in my A Levels. Your videos give me a lot of confidence.
That's good - thanks.
Mechanics today! Thanks for the videos, best revision at home ever.
Good luck everyone
Thanks a lot!!!! I usually refer to your video's when it comes to revision. Clearly explained!
great video, thanks a lot, only thing is, how would you go about working out the answers if the string was extensible and/or the pulley was rough? you would have more than 2 unknowns..?
You are the clearest teacher of Mathis
good video!
*maths would you ever consider incorporating the ccea syllabus? It's very similar although there irate different moments questions. There's not much online for ccea and it would be fantastic if there was something like what you do, just a thought
thank you so much this helped me a lot i have my mechanics AS exam tomorrow wish me good luck
Well done. Keep at it and I am sure you will get there.
In OCR M1 would we ever be asked a question with a rough pulley or an extensible string?
Thank you Sir, M1 seem much easier after watching ur videos!!
Best wishes.
why we didn't consider the normal reaction on the pully if it is inclined?
How would you be able to tell which particle would move up or down for this? Is it just the masses?
It doesn't really matter which direction you pick, if you picked the wrong direction, you'd still get the same value for acceleration, just negative.
Watching from Kenya for my Architecture physics class.
You cleared this up for me, thanks. I would donate, but I have no income.
ah ok that's good, these videos have helped so much, when I get the chance I will donate (Y)
Amazing as always stuart
many thanks for the video!
Thank u soo much
You're welcome Kevin, glad you like it! Best wishes
That's good. No worries.
What if the question asked find the friction if the system in statics equilibrium
@imdaark Thank you very much
I would really appreciate that if you do. Thanks.
I'm a little confused to where I might have went wrong. I got T-6.79+2gSin30+2a
Then I got T= 6.79+2gSin30+2a
Substituting that into 4g - T = 4a got me 4g - 6.79+2gSin30+2a=4a
Taking away 2a from both sides give me 4g-6.79+2gSin30=2a
which is then 39.2 - 16.59 = 2a
22.61 = 2a
a = 22.61/2
i got a as 11.305 Help me out please although Im going to redo the question and If anything changes Ill remove this comment or post another one
idiot
@@SkillSasaBoy123 no need for that
I do not understand what u were on about when u said with sine you exclude the angle and with co sine you do not?
Check this out www.examsolutions.net/tutorials/resolving-forces/?level=A-Level&board=Edexcel&module=Mechanics%20A-Level&topic=1632 I hope it answers your question
thanks mate
how comes particle A uses the equilibrium method but for particle B you used f=ma ???
Simply put, the sum of forces that are perpendicular to the motion of the particle is equal to zero.
That's ok.
It accelerated from rest.
Too difficult to go into here. You would not get a question like that at this level.
why is tension up
how can A be at rest and have an acceleration? :S
No
And the surface is given frictionless at first
You use calculator for this? O_o
okay :(
*are not irate lol