Mechanism Monday #20: Cinnamon Spice!

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 21

  • @Total_Syntheses
    @Total_Syntheses 11 днів тому +1

    I think that rxn requires very strong acid like Sulfuric acid which can break the aromaticity.
    Maybe hydrogen is added on the para position from hydroxy group. At that time, carbocation of meta position is pretty stabilized because its resonance form makes carbonyl compound which is stable than carbocation.(due to octet rule)
    And then HSO4- eliminates a hydrogen from t-butyl group to afford products.(driving force : recovery of aromaticity)

    • @rojaslab
      @rojaslab  10 днів тому

      You’ve got a keen eye for the nuance of that protonation step!

  • @keikazazic3296
    @keikazazic3296 14 днів тому +8

    Great video as always, but the product is not cinnamaldehyde, it is not even an aldehyde

  • @Joseanfer-zs9zm
    @Joseanfer-zs9zm 14 днів тому +1

    Wow, that next week reaction looks crazy! Seems like a kind of retro-Friedel Crafts alkylation. My guess is, acid protonates the aromatic carbon holding the tertbutyl (which has more electrinuc density due to OH donating group), then the aromatic ring is restored by kicking out the tertbutyl gropu as a tertiary carbocation, which then forms isobutene in an E1 reaction, libersting a proton

    • @rojaslab
      @rojaslab  13 днів тому

      You are absolutely crushing it!

  • @lenoel7666
    @lenoel7666 14 днів тому +1

    yay, i this was the first mechanism i was able to come up with pretty much on my own!

    • @rojaslab
      @rojaslab  14 днів тому

      Boom! That's awesome news. Excited to see you get next week's mechanism too!

    • @lenoel7666
      @lenoel7666 14 днів тому

      @@rojaslab I'll try!

  • @faisalalaidy
    @faisalalaidy 12 днів тому +1

    Why do you suggest the E2 mechanism for the formation of the double bond instead of E1cb, which is typical of aldol condensation?

    • @rojaslab
      @rojaslab  12 днів тому +1

      This is a really excellent question. I have a long answer that will likely be unsatisfactory to many organic chemists. To start, I'm an INORGANIC chemist by training, and that means that the way I think about chemical reactivity is a bit different than trained organic chemists. I like to think about elimination reactions as a spectrum. On one end of the spectrum are E1 mechanisms being unimolecular, E2 mechanisms being somewhere in the middle of the spectrum as I've shown in the video, and then E1cb mechanisms being on the opposite end of the spectrum. You're absolutely right that aldol condensation reactions are typically taught as E1cb mechanisms, but for me, I've never really understood the point. To me, the transformation and the pathway are the same, the existence of the intermediate enolate/carbanion is really the differentiating factor. As an inorganic chemist, this subtle difference is irrelevant to me, especially since I don't think the enolate formation would be reversible and I don't think the final step in the E1cb mechanism would be the rate-determining step. I also think E1cb mechanisms require very basic conditions and while NaOH is obviously a strong base, since the reaction is in EtOH, that base will only be sparingly soluble limiting the basicity of the solution. Therefore, I think it's an interesting discussion to have that, to me, isn't really important in the long run. Because you get the same thing no matter what. I'm sure these statements are offending the world of organic chemists, but I'm used to that as an inorganic chemist. To be fair, I'd also be willing to fight anyone who suggests something like the Jahn-Teller effect is real, thus offending a host of inorganic chemists as well.

  • @chrisjones-fp5vd
    @chrisjones-fp5vd 14 днів тому +1

    That next one looks similar to the cumene process.

    • @rojaslab
      @rojaslab  14 днів тому

      The cumene process is pretty cool! This proceed through a more familiar and fundamental mechanism though!

  • @yusefsadik8730
    @yusefsadik8730 14 днів тому +1

    So you want me to dissolve NaOH in EtOH😮‍💨

    • @rojaslab
      @rojaslab  14 днів тому

      Haha. I didn’t say any of this would be fun!

  • @realhustl_
    @realhustl_ 14 днів тому +1

    Funny lol enolate chemistry I thinky

    • @rojaslab
      @rojaslab  13 днів тому

      You got it! But do you remember what the reaction is called?

    • @realhustl_
      @realhustl_ 13 днів тому

      @@rojaslabis it a Michael addition ? Or aldol the product is a 1,3 relationship so I think aldol since Michael is 1,4 I think

  • @user-mp4bc9qp2x
    @user-mp4bc9qp2x 14 днів тому +1

    this reaction is routinely performed by undergraduate students, but the product they isolate is dibenzylideneacetone. maybe you'd be able to get this product with excess acetone present

    • @rojaslab
      @rojaslab  14 днів тому

      I think it would depend on the stoichiometry and order in which the reagents were added. But that’s a great idea for a future mechanism problem!