I've seen many videos that explains this problem and this is the best one so far. The other ones just throw the formulas at you, but this one explains what are the variable and why we used them.
Wonderful video Scott, you explained the variable relations very well, it took me a while to completely understand how everything is related because of a A, r R, q Q, etc can get a little hectic but I got there. Cheers for the indepth explanation ^^ 3:00 - dq = "charge" charge = o [Surface Charge Density (o=Qtot/A)] * dA, [A=/=dA, A=(pi)R^2] 3:18 - Where dA is the total area of the ring = 2(pi)r [circumference] * dr [thickness] Thus the 2 comes from the dA (circumference), and R^2 comes from A=Area (pi)R^2 their pi's cancel 4:55: Hahaha no wonder........ that's on a formula sheet I sure didn't know where that was coming from.
Scratch that! I think a better question would be, is there another way to solve it instead of splitting the disk into tiny rings? The video explanation was very clear; I just needed to think some more before I spoke.
I think there should be, for example using a double integral, but I've been out of school for way too long to set it up that way. The small handful of textbooks I consulted split the disk into rings first. Also, the students I was teaching were comfortable enough with single integrals but they freaked out when I suggested setting it up as a double integral. Splitting it up seems to give a simpler explanation. Good luck!! :-)
@@nikhilkul3459 It's been nearly 20 years since I worked with double integrals and unfortunately I don't have the time to dig back into it. Best of luck to you though!
I've seen many videos that explains this problem and this is the best one so far. The other ones just throw the formulas at you, but this one explains what are the variable and why we used them.
Most descriptive video I have come across. Keep up the great work and thank you for your help!
Wonderful video Scott, you explained the variable relations very well, it took me a while to completely understand how everything is related because of a A, r R, q Q, etc can get a little hectic but I got there.
Cheers for the indepth explanation ^^
3:00 - dq = "charge"
charge = o [Surface Charge Density (o=Qtot/A)] * dA, [A=/=dA, A=(pi)R^2]
3:18 - Where dA is the total area of the ring = 2(pi)r [circumference] * dr [thickness]
Thus the 2 comes from the dA (circumference), and R^2 comes from A=Area (pi)R^2
their pi's cancel
4:55: Hahaha no wonder........ that's on a formula sheet I sure didn't know where that was coming from.
Thank you so much for your encouraging feedback!
THANK YOU SO MUCH SIR FOR HELPING ME THROUGH THIS VIDEO
nice explanation bro!!! THUMBS UP!!!👍👍😉😉😄😄
Thanks, Scott!
Hi Tom, you're welcome! I'm glad I could help!
thanks so much sir !!!!!! ,really very helpful
thx
Hi Scott, I have a question. Why do you have to split the disk into tiny rings?
Scratch that! I think a better question would be, is there another way to solve it instead of splitting the disk into tiny rings? The video explanation was very clear; I just needed to think some more before I spoke.
I think there should be, for example using a double integral, but I've been out of school for way too long to set it up that way. The small handful of textbooks I consulted split the disk into rings first. Also, the students I was teaching were comfortable enough with single integrals but they freaked out when I suggested setting it up as a double integral. Splitting it up seems to give a simpler explanation.
Good luck!! :-)
@@RedmondPhysicsTutoringVideo sir can you also tell with double integral do send the link sir if you will .
@@nikhilkul3459 It's been nearly 20 years since I worked with double integrals and unfortunately I don't have the time to dig back into it. Best of luck to you though!
Sooo confused