2(kx - n) = (-28/15)x - 36/19; In the given equation, k and m are constants and n is greater than...
Вставка
- Опубліковано 22 січ 2024
- Bluebook Digital SAT Test 4 Module 2 (Hard) Question 11:
2(kx - n) = (-28/15)x - 36/19
In the given equation, k and m are constants and n is greater than 1. The equation has no solution. What is the value of k?
KEEP IN TOUCH:
🤟🏾 Members ONLY - / @thesatmathguy
▶️ SUBSCRIBE - / @thesatmathguy
📈 FREE DIAGNOSTIC & AI SAT Prep - testprep.thesatmathguy.com
🌍 My website - www.thesatmathguy.com
📸 Instagram - / thesatmathguy700
📱Tiktok - / thesatmathguy
👨🏾💼 LinkedIn - / stephenajohnson1
🧑🧑🧒🧒 Facebook - / stephenajohnsontestprep
![Why you didn't learn tetration in school[Tetration]](http://i.ytimg.com/vi/Ea1_1aVfwl4/mqdefault.jpg)
![[August SAT Prediction] 3 Hardest Questions](/img/n.gif)
A simpler approach to this would be breaking the equation into 2 parts as y=2(kx-n) and so on, then as we know that parallel lines never meet so it automatically means that such a case would have no solutions. Therefore as parallel lines have the same gradient we can consider 2k as the gradient of the equation y=2(kx-n) which is equal to =28/15
LOVE it! Thanks for sharing
thank u smm ur a lifesaver
@@joeboxedyou200pumpedandthenpop you’re very welcome!!
Is there a way to do this with desmos or no?
Maybe.... but I wouldn't recommend it. You can definitely type this in to desmos and use a slider for both n & k, knowing that n is greater than 1. I'll see if anyone responds to this with more insight. I personally only like to use desmos if I am sure that it will save time. I do not get that sense with this question.
u can just do 2kx=-28/15x right? and then the x cancels out and u solve for k
Yes, see 2:50.
@@TheSATMathGuyohh I see, thank you!