Mechanical Properties of Materials and the Stress Strain Curve - Tensile Testing (2/2)

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  • Опубліковано 20 січ 2025

КОМЕНТАРІ • 46

  • @JoseLuisSarmiento
    @JoseLuisSarmiento 4 роки тому +2

    Best video on UA-cam about stress-strain curve. Thanks!

  • @samiraelena590
    @samiraelena590 5 років тому +6

    I really appreciate your video I came here because my lecturer explained this but I was hardly understand. And your videos are great. Super easily to understand!! Please make more videos about mechanical properties

  • @DarthCoco
    @DarthCoco 4 роки тому +1

    This video has helped me so much compared to most other videos, thank you.

  • @rachelneale7614
    @rachelneale7614 5 років тому +8

    This is a great teaching video, especially since i am an engineering student. I had a look at your channel for more but there didn't seem to be may. A video on phase diagrams and calculating alloy compositions would be awesome!

  • @googolplexian8009
    @googolplexian8009 7 років тому +3

    Thank you for refreshing my memory

  • @alexbarker4438
    @alexbarker4438 4 роки тому

    6:07 - "1 with 10, 9's" - lol - We knew what you meant. Great video 👍

  • @ruslankarimbaev7012
    @ruslankarimbaev7012 5 років тому +3

    How do you calculate ultimate tensile strength from yield strength?

  • @harishchauhan9475
    @harishchauhan9475 4 роки тому

    super, I have not understood in my engg class as much as by your video

  • @heesoolee3159
    @heesoolee3159 4 роки тому +2

    I really like your smile and voice. Thank you^^

  • @carolnewme3106
    @carolnewme3106 6 років тому

    I sincerely thank you , sir .

  • @chuntsuccess9835
    @chuntsuccess9835 5 років тому

    Hello do u know agglomeration about in CNT?

  • @nurmaniais2659
    @nurmaniais2659 6 років тому +2

    how to find elastic modulus for graphs such as rubber ?

    • @FuturefabOrgUk
      @FuturefabOrgUk  6 років тому

      I'm not an expert in non-linear materials but here is my understanding.
      Elastomer graphs look strange in comparison to the typical ductile graph. They're non-linear so have different values at different stages of extension. Here is some good information.
      files.hanser.de/Files/Article/ARTK_LPR_9783446416819_0001.pdf
      Rubber goes through a hysterisis cycle. When this is closed you can use something like MATLAB to differentiate the fucntion to find the slope of the graph at the point of interest.
      In the real world you'd likely just look of the "small strain" value of the rubber in a materials handbook.

  • @kamrankhankami7793
    @kamrankhankami7793 4 роки тому +2

    hi i like your teaching style with your smiley face brother, may ALLAH keep you smiling forever........
    #Kami_Khan_of_NUTECH (PAKISTAN)

  • @АднанХан
    @АднанХан 7 років тому +1

    very precise explanation. Thanks

  • @ainimilania236
    @ainimilania236 5 років тому

    Thank you for the explanation! Really helps

  • @frandelcastillo9566
    @frandelcastillo9566 5 років тому

    Thank you very much for this video, the best one i could find, easy to follow and understand.

  • @garethjackson4937
    @garethjackson4937 5 років тому

    Thank you! Makes so much more sense.

  • @omerstream3300
    @omerstream3300 2 роки тому

    brilliant teaching....in which university u are working for ? respect from sudan

  • @waltercarrillo6065
    @waltercarrillo6065 4 роки тому

    Excellent, thanks

  • @SODA-pc2yj
    @SODA-pc2yj 5 років тому

    good video man, thank you x

  • @progByExamples
    @progByExamples 6 років тому +1

    Good work

  • @MandeJoswa
    @MandeJoswa 8 місяців тому

    Thanks 👍

  • @vaishakhsajeevan3893
    @vaishakhsajeevan3893 6 років тому

    Thank you so much

  • @thamersal3135
    @thamersal3135 6 років тому

    THANKSSS FOR THIS NICE VIDEO

  • @soumalyasinha8093
    @soumalyasinha8093 6 років тому +1

    I didn't like when he said "stress" is a fancy word for "pressure". "Pressure" is a special case of equal normal stresses at a point irrespective of the orientation of the plane through the point on which the normal stress is calculated.

    • @FuturefabOrgUk
      @FuturefabOrgUk  6 років тому +3

      An excellent point and a very clear definition. This video was aimed at my 16 year old students and I think your definition might have gone over their heads! It is however, much more accurate. Thank you.

    • @soumalyasinha8093
      @soumalyasinha8093 6 років тому

      FutureFab CNC & 3D Printing I am quite impressed with your humbleness! I didn't notice that your lecture was intended for undergraduate students 😅

  • @blancaroca8786
    @blancaroca8786 5 років тому +2

    Anyone who needs formula triangles really needs to go and get a personal math tutor and in just a few hours learn basic algebra so you never need memorise sillyness again. Really those silly triangles say nothing more than if 4x5=20 then 4=20/5. Of course you need to understand why 4/5=4 divided by 5 and you also need to be able to rearrange stuff like (4/5)/(3/4)=(4x4)/(5x3) and you simply cannot memorise lots of triangle or quadrangles for every eventuality. Really algebra is easy ..just find a decent teacher or try some books or khan academy.

  • @mrezaalagheband5442
    @mrezaalagheband5442 7 років тому +2

    thanks it is helpful

  • @kishore5754
    @kishore5754 6 років тому

    a bro nice teaching

  • @tomhall1998
    @tomhall1998 6 років тому +1

    yes kev!!!

  • @ravenship2486
    @ravenship2486 7 років тому

    Doesn't explain difference between stress and pressure

    • @FuturefabOrgUk
      @FuturefabOrgUk  7 років тому +3

      +Vinay Agnihotri there isn't one for all practical purposes. Both measured in Pa and both calculated by f/a. Hope this helps.

  • @ravenship2486
    @ravenship2486 7 років тому +1

    Very very poor explanation, not explain any point clearly as well as you can't say elastic material a rigid.

    • @FuturefabOrgUk
      @FuturefabOrgUk  7 років тому

      +Vinay Agnihotri not sure what you're referring to there Vinay.

    • @soumalyasinha8093
      @soumalyasinha8093 6 років тому +2

      Vinay Agnihotri Almost all materials are elastic to some limit however small the limit maybe. A perfect rigid body is a hypothetical concept but we still apply the laws of Newtonian mechanics to bodies under the effect of a system of forces whose deformations are negligible in comparison to the actual dimensions of the body. That means we can approximate an elastic body as a rigid body under a given system of forces without any significant error in judgement only if the change in the dimensions of the body under the action of a system of forces is insignificant when compared to the original dimensions of the body.

  • @mickaaldering8874
    @mickaaldering8874 5 років тому +1

    Dikke 'VO

  • @pratik2583
    @pratik2583 7 років тому +1

    NOT for engineers...This is just general info

  • @MIKEY_IRAQ
    @MIKEY_IRAQ 10 місяців тому

    Wow are you life

  • @lalchandmahto5464
    @lalchandmahto5464 4 роки тому

    Stpess