General Organic Chemistry (Part-5) || Organic Chemistry || HCU PG Entrance (Chemistry) || RK Sir

[@subhendunayak]

Thanks

[@abhishek3503]

Thanks sir

[@soumensamanta8982]

Thank u sir

[@nethintitirupathi1237]

Tq sir

[@aswathysabu5584]

Sir in 75 qs the second structure will have S configuration, the rotation in anticlockwise direction according to priority and hydrogen not in above plane so we don't have to revert it then how it become R?

[@RamakrishnaSinguru]

In second structure H is on plane. Arrange groups in anticlockwise by putting methyl constant. Then we will get the configuration with H below the plane. Now connect 1,2,3 priority groups. Clockwise connection we will get. So it is R

[@aswathysabu5584]

@@RamakrishnaSinguru I didn't get it sir Hydrogen is in the plane so we can look away from it then assume priorit yso 1 Nh2,2nd cooh ,3rd ch3 anticlockwise wise .. pls clear my doubt Sir

[@RamakrishnaSinguru]

H should be away from the viewer i.e. below the plane, when we give R,S configuration. By putting CH3 as constant & arranging remaining three groups in anticlockwise direction, we will get configuration with H below to the plane. Now connect NH2, COOH, CH3 ...the connection will be clockwise...so it is R

[@aswathysabu5584]

@@RamakrishnaSinguru thnk you Sir