Transistor Current Source and Its Non-ideal Properties - Part-1 - AoE Chapters 2 Problem 2 Solution

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  • Опубліковано 23 січ 2025

КОМЕНТАРІ • 5

  • @emmanuelinnocent4505
    @emmanuelinnocent4505 4 роки тому +1

    Thanks for this excellent explanation.
    I enjoyed solving along.
    🤗
    However, I have a question.
    Why was 8.676V used for ΔVCE in the relationship: ΔVBE = -0.0001ΔVCE?
    Why not 0.3V?
    I was thinking 8.676V is just the max. voltage across the load for the current source to remain in the active region.
    Thanks in advance.

    • @emmanuelinnocent4505
      @emmanuelinnocent4505 4 роки тому +1

      Oh wow!
      @Smith Kerona, while thinking about the question after I dropped it.
      I thought: if KVL was taken round the output loop, we get: VCE = VCC - VL - VE.
      Where VL is the voltage across the load.
      Taking the change of the equation above:
      ΔVCE = -ΔVL
      As VCC and VE are constants.
      Could this be the reason?
      Please I'll still like to hear from you.
      Thanks.
      🙏🏾.

    • @SmithKerona
      @SmithKerona  4 роки тому

      @@emmanuelinnocent4505 You got it! Since IC is considered constant (the circuit is a current source), VE doesn't change. Also VCC doesn't change as you indicated. Therefore the only quantity that changes is the load voltage. The transistor adjusts the collector to emitter voltage to maintain constant collector current across the load as long as the compliance voltage isn't surpassed.

  • @videostzintzire
    @videostzintzire 5 років тому +1

    excelent explanation ; what is the name of the book?

    • @SmithKerona
      @SmithKerona  5 років тому

      Thanks and the name of the book is called The Art of Electronics 2nd ed.