Week7Lecture6: Evaluating an Improper Integral via the Residue Theorem

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 31

  • @MikeMagTech
    @MikeMagTech Рік тому +1

    I really can not thank you enough for creating this excellent course. Your patience, care, and attention to detail combine to make you a superb teacher!

  • @luislopez-tx4tl
    @luislopez-tx4tl 2 роки тому +1

    shes the moment, she’s that girl, ilyyy thank you :)

  • @saeida.alghamdi1671
    @saeida.alghamdi1671 Рік тому

    Very concise and valuable presentation on key steps to evaluate an improper integral using a combination of complex analysis theorems and limit analysis 🌿

  • @enricolucarelli816
    @enricolucarelli816 7 років тому +1

    I just finished watching all your lessons, the seven weeks. Marvelous. THANK YOU VERY MUCH!!

  • @unmoveablepenguin
    @unmoveablepenguin 8 років тому +9

    Thank you so much for uploading this brilliant Lecture series, I now have a fighting chance of doing well in my exams

  • @BurakAlanyaloglu
    @BurakAlanyaloglu Рік тому

    Dear Professor, thank you very much for this insightful explanation. It was very helpful for my final exam preparation. I am so glad to watch how you approach the problem step-by-step and explain every single action thoroughly. I hope this style of teaching inspires everyone :)

  • @mpicos100
    @mpicos100 Рік тому

    Thanks a lot for the course. Really well explained with detail and clarity.

  • @abdofred1914
    @abdofred1914 2 роки тому

    professor Petra B Taylor , i watched all your playlist on the analysis of complex functions , i cant thank u enough , thank u from the bottom of my heart

  • @MarcosdoHawaii25
    @MarcosdoHawaii25 4 роки тому +1

    Thank you so much for your time and patience to make a clear explanation. :-)
    It is awesome to understand step by step and in the end you can comprehend the whole question.

  • @vishwadeep4687
    @vishwadeep4687 2 роки тому

    Thank you so much for this wonderful course,

  • @achillesarmstrong9639
    @achillesarmstrong9639 5 років тому

    finished watching that, what a great series of videos.

  • @arkyin3860
    @arkyin3860 2 роки тому

    great course !! so many days and nights here

  • @jozef-aerts-wiskunde
    @jozef-aerts-wiskunde 5 років тому

    Thank you very much .. i have made 30 videos in dutch on youtube , describing Complexe Analyse , based upon your videos .. so again , thank you very much

  • @bouzzigismail4841
    @bouzzigismail4841 5 років тому +1

    Thank u so much ... Watched at 2020 ♥️♥️♥️😊

  • @saeida.alghamdi1671
    @saeida.alghamdi1671 4 роки тому

    Thank you! This is an informative example! ... it will be great if develop a set of examples on the the theory and applications of conformal mapping...!

  • @sigma239
    @sigma239 6 років тому

    please keep posting more lectures on complex analysis!

  • @teresafraile7474
    @teresafraile7474 4 роки тому

    Thanks for this lectures. They have helped me alot

  • @christophermoore5389
    @christophermoore5389 4 роки тому

    That’s a very cool trick also by substituting cosh(ix) for cos(x) you also get something in exponential form which can be evaluated that was my first though but your way saves some work

  • @ChristGodinyouItrust
    @ChristGodinyouItrust 7 років тому

    Very good video.

  • @nseminsimba5889
    @nseminsimba5889 8 років тому +2

    Very helpfull thanks

  • @du4140
    @du4140 7 років тому

    marvellous ma'am

  • @rajatgoyal8920
    @rajatgoyal8920 7 років тому

    Awesome!!

  • @jamesfortune243
    @jamesfortune243 2 роки тому

    Clearly and cleanly explained

  • @loverofthenight9150
    @loverofthenight9150 5 років тому

    Thanks a lot

  • @orangejamify
    @orangejamify 7 років тому

    Professor, how do you prove the integral exist? Is it part of the evaluating an improper integral that we need to prove the integral exist? Many thanks!

    • @Kyle-li8wi
      @Kyle-li8wi 7 років тому

      I believe that you prove it exists by bounding it. Since Cos(x) oscillates between plus or minus 1, the limit is determined by the denominator. So the integrand approaches 0 as x goes to infinity.

    • @orangejamify
      @orangejamify 7 років тому

      Thank you for your response!

  • @ybc8495
    @ybc8495 3 роки тому

    spolier: pi/2e

  • @enricolucarelli816
    @enricolucarelli816 7 років тому +4

    I just finished watching all your lessons, the seven weeks. Marvelous. THANK YOU VERY MUCH!!

    • @shb4344
      @shb4344 4 роки тому

      I finished too. I'm happy :)

  • @saeida.alghamdi1671
    @saeida.alghamdi1671 Рік тому

    Very concise and valuable presentation on key steps to evaluate an improper integral using a combination of complex analysis theorems and limit analysis 🌿