Sorry but I made a mistake explaining bending about the x-axis. Bending about the x-axis means the beam bending along the longitudinal axis - this will be the x-axis that spans along the length of the beam - accurately shown in the thumbnail image. My mistake is saying the x-axis is the neutral axis. This is not the true in this case, the neutral axis would be the z-axis as shown correctly by the thumbnail image.
Quynh Cao 0 seconds ago It is Ixc ... Not Ix.... If Ix =(bh^3)/3........................................... But For Your Case Ixc= (bh^3)/12.........................Not x Axis As Line Run Along Bottom of Beam... As Reference x Line.........But For Your Case, I Use Ixc=(bh^3)/12.............I See Now.... The Beam Cross Section Bent Around Centroidal Neutral Axis.....??
![Lp. Сердце Вселенной #60 РОЖДЕНИЕ ЛОЛОЛОШКИ [Финал] • Майнкрафт](http://i.ytimg.com/vi/YoR0pAV9FVQ/mqdefault.jpg)
Sorry but I made a mistake explaining bending about the x-axis. Bending about the x-axis means the beam bending along the longitudinal axis - this will be the x-axis that spans along the length of the beam - accurately shown in the thumbnail image.
My mistake is saying the x-axis is the neutral axis. This is not the true in this case, the neutral axis would be the z-axis as shown correctly by the thumbnail image.
@@eslamhegazy7224 Hello Eslam, please send me an email if you can to farouq@directhub.net
What would b be if you got a t or I beam?
The smallest width dimension.
@@directhubfeexam Thank you!!!!
@@DrewWilson-bj4cr you’re welcome!
Quynh Cao
0 seconds ago
It is Ixc ... Not Ix.... If Ix =(bh^3)/3........................................... But For Your Case Ixc= (bh^3)/12.........................Not x Axis As Line Run Along Bottom of Beam... As Reference x Line.........But For Your Case, I Use Ixc=(bh^3)/12.............I See Now.... The Beam Cross Section Bent Around Centroidal Neutral Axis.....??