Lecture 26: What is Paging? || Non-Contiguous Memory Allocation
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- Опубліковано 11 лип 2024
- This video provides an engaging glimpse of PAGING in Operating System
There is a lot to learn, Keep in mind “ Mnn bhot karega k chor yrr apne se nahi hoga ya maza nahi aara, Just ask 1 question “ Why I started ? “
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Slides: drive.google.com/file/d/1L9q1...
Notes: drive.google.com/file/d/1PSzT...
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TimeStamps:
00:00 - Introduction
02:13 - Promotion
03:03 - Paging in OS
10:50 - Address Translation using Page Table
25:26 - Context-Switching in Paging
28:42 - Why Paging is slow and how do we make it fast?
31:00 - Translation look-aside buffer (TLB)
38:12 - Context-Switching in Paging with TLB
Intro Sequence: We have bought all the required Licenses of the Audio, Video & Animation used.
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You have explained in such a way that we don't need to memorize anything. The logical progression of this lecture is phenomenal. Dil Se Shukriya Bhaiya
But we will surely have to revise to remember all the information clearly.
Thankyou bhaiya Roz aap hmare liye itni mehnat krte ho ❤️
Attendance marked
Lecture watching with notes 😀
Most of the time , i don't skip aid after 4 second when youtube allow me to skip , i just let it run so that i can pay fee indirectly to this great content creator..love this series ❤️
bro use adblocker to reduce ads and watch lecture distraction free
I use youtube vanced so can't do that 😢 . And also sponsored is auto skip
this playlist is very very helpful..... enjoying too much without spend any money.
Thank you so much bhaiya you are seriously weapon for us ❤ thanks you for helping .....
Your support are enough for us
Thank you so much bhaiya😄 excited for live session 😇😊
Thank you soo much bhaiya..pehli baar paging puraa samjh aaya hai🙏🏻
division of process into pages
page : process ka part
page size == Frame size {main memory ka segment} [alloted based on archietecture ]
Sir your videos are very good and clear crystall and i got like 23 out 24 through your videos only👍👍👍
this lecture was 🔥... mazza aa gya bhaiya
thank you so much for all the effort, It is HIGHLY appreciated
Thanks buddy!
Keep learning 😊
@@lakshaykumar7518 i'm a new student sir, i give my heartiest thanks to you. OS was always a favourite subject, but my college professor is rude enough for me to not understand a single thing. but from your lectures, i'm close to completing OS (placement-wise) within one month.
Thanks a lot. Amazing lectures.
aag laga diye bhaiyaji
Amazing explanation🔥
Thanks bhaiya for your superb lectures
Thank you for your hard work❤
Sir you have worked really hard to make best and easily understandable note. I have never seen notes which I can understand just by reading by the way I finished this whole playlist in just 2 days.
we can easily understand your lecture thank you so much 💯💯💯💯💯💯💯💯💯
Thankyou bhaiya Roz aap hmare liye itni mehnat krte ho
thank you for the best explanation
Thank you!!!
Present Bhaiya. OS ki course ki consistency bahut sahi hai
Always superb ☺️
Great Work!
Thank you so much bhaiya you are seriously weapon for us ❤ thanks you for helping .....
Your support are enough for us ❤
Thanks buddy!
Keep learning 😊
Bahi Dil se thank you.
Thanks for this informative lesson
Awesome video 🔥
Thankyou so much bhaiya
Boht acha smghaye sir
Thank you sir😊
Super video Sir
Thank you guru ji ❤️
QUALITY OF CONTENT 🔥🔥
Very hi nice explanation.😊
Thanku bhaiya
Thanks
mza aa gya bhai shahb😉😉😉😉😉
Dil se thanks !
mazza aagaya bhaiya
Love babbar bhaiya and os vale bhaiya.
Dil se thank you ❤
naam to bol do laskhay h
great
Fabulous
kaafi In-Depth lecture tha.... Hope these questions are important
theyre not
@@pranav288 so what are the important ones..please emphasize a little bit
paging is important ....it came in my interview from foxconn
WoW . . .
consistency++
you are better then apna college wali
Bhaiya moj kr dii
If the size of the logical address space is 2^m, and a page size is 2^n bytes, then the high-order m − n bits of a logical address designate the page
number, and the n low-order bits designate the page offset.
Maine Video Pura dekha
Day 26 Done ✓
Love you
What if the process size is of 24KB, then first page(for 0-16KB) will completely occupy the frame, but the second page(17-24KB) will occuply half frame, and when the internal fragmentation of some number of such pages is combined, will it not cause external fragmentation? As the space will be empty and the total empty space will also be enough to accomodate a process of 16 KB.
TLB is simply works like DP.
You are awesome dude !!
Lakho bacho present future me OS ka problem solve ho gaya..
Best content of OS in any platform any professor ....
🔥🔥🔥🔥
Bhaiya DBMS ka bhi kuchh karo..
Bahut problem hai usme kuchh smjh nhi aa rha..
🙏🙏
Thanks buddy!
Keep learning 😊
❤❤❤❤❤
Does in memory 1 byte is represented through 1 bit?
Bhaiya jee, Kab Linux kernel ko explain kere GE, I am very excited,
logical addresh ma frame kitni bit ka hona chya ya explain kra do?
Memoization is used in case of TLB
attendance marked
06/07/24 paging tlb cleared++ Lakshay bhaiyaa
op
buiteefuul..
Bhaiya Computer Networks ka playlist be lao, please.
Reach++
How are we fixing the 2 bits for page number, what if a process has more than 4 pages?
Bhaiya DSA ki videos constant dallo plzz
how did we convert 01 to 111 in frame 7 at 21:19
Sir, I don't understand how paging is a non-contiguous memory allocation if the size of the page is fixed.
Bro because we are adjusting data in RAM non- contiguously..
Simply bol do ki TLB is just like DP array 😂
Day19
How many videos are left in DSA course??
Bhiya plz continue DSA placement course
Approximately how many videos are more on the way until the completion of this course ?
4-5 videos!
Day 26 done... 07/06/24
correction
addresses should be 0-127
and 0-63
I am excited giveaway participate and supported coad help by Babar
bhaiya ne dp ka real life example dikhlaya hai #tlb
nice observation
the bit representation of 25 is 11001 but you had written 011001
the usage of bytes is very much wrong here, this created a lot of confusion as we learnt that
1 byte=8 bits and then all of sudden you write 64 bytes will require 6 bits, it should be , the 64byte addressable memory will require 6 bits to represent the logical address space
tu hi pdhale na fir lodu
64 byte is 512 bits then how do we get 6 bit?? @16:42 Confusing
yaa. actually he mugged up theree. what he meant to say was , to represent 64 addresses in the logical address we need 6 bits, because 2^6 is 64 , so we can represent at max 64 byte addressable space in 6 bits
bump
20 din baad koi nya person aane wala tha, koi nyi series start honey wali thi but it's been more than 20 days but still no update regarding that.
Plzzzzz make subtitles available plzzzzzzz🙏🙏🙏🙏🙏🙏🙏
Bhaiya DSA waali playlist kaafi slow ho gyi hai
C++ playlist plzz
Bhaiya c++ ka video dalo nah pls bhaiya
What does over head means?
naukri dilwado sir
apse hi padha hai sab
IS PURE SERIES KA SBSE KHRAB VIDEO HAI
You have explained in such a way that we don't need to memorize anything. The logical progression of this lecture is phenomenal. Dil Se Shukriya Bhaiya
Present Bhaiya. OS ki course ki consistency bahut sahi hai
Thank you!!!