mam, for [Cr(CN)6]-3 , it has d2sp3 hybridization as inner vacant d orbital is available . but can you explain on the behalf of cyanide as strong field ligand, what would be the number of unpaired electron"? 3 or 1???? i m confused whether to pair or not in this case because of cyanide ligand. In book there is no pairing, but as per influence of strong field ligand there should have been pairing. and n must have been equal to 1( 1 paired and 1 unpaired ) can u advice me?
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mam, for [Cr(CN)6]-3 , it has d2sp3 hybridization as inner vacant d orbital is available . but can you explain on the behalf of cyanide as strong field ligand, what would be the number of unpaired electron"? 3 or 1???? i m confused whether to pair or not in this case because of cyanide ligand. In book there is no pairing, but as per influence of strong field ligand there should have been pairing. and n must have been equal to 1( 1 paired and 1 unpaired )
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True
mam, for [Cr(CN)6]-3 , it has d2sp3 hybridization as inner vacant d orbital is available . but can you explain on the behalf of cyanide as strong field ligand, what would be the number of unpaired electron"?
3 or 1????
i m confused whether to pair or not in this case because of cyanide ligand. In book there is no pairing, but as per influence of strong field ligand there should have been pairing. and n must have been equal to 1( 1 paired and 1 unpaired )
can u advice me?
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thank you so much Madam. i understand a little bit of hindi...but your explanation is so simplified that we can understand without understanding the language. thank you so much.
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Your teaching appealed to me to listen to the lecture even when I didn't want to. I truly wish more and more people discover your channel so their life becomes easier... Thank you ma'am.
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Thank you ma'am for such an amazing lecture. It was easy to understand and covered all points. You are a very good teacher, ma'am and it's your level of confidence that makes your teaching more effective. I am honoured to learn from you
thk very much even if i can't understand every word but you teach better than lecturer at my university
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mam, for [Cr(CN)6]-3 , it has d2sp3 hybridization as inner vacant d orbital is available . but can you explain on the behalf of cyanide as strong field ligand, what would be the number of unpaired electron"?
3 or 1????
i m confused whether to pair or not in this case because of cyanide ligand. In book there is no pairing, but as per influence of strong field ligand there should have been pairing. and n must have been equal to 1( 1 paired and 1 unpaired )
top class......teaching mam...
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Thanks Mam for this video
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Thanks mam
You are great maim
Good understanding
mem bahut achcha samjaya
thank you it's verry nice
Could you explain k3[Fe(CN)6]
[Ti(H20)]2+
[Ni(CN)6]4-
Why they are paramagnetic
Most most Thanks mam....
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Thnks mam...
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Tq mam
Mam we can't use ..the term strong field and weak field ligand in VBT Theory....we have to use low spin high spin..complex otherwise it will be wrong
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Super explanation mam
Thanks mom
could you also tell how [MnCl6]-3 is d2sp3 ?
wow very nice
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