Розмір відео: 1280 X 720853 X 480640 X 360
Показувати елементи керування програвачем
Автоматичне відтворення
Автоповтор
👋👋👋
EXCELLENTONIO!
((1+Sqrt[5])/2)^12=161+72Sqrt[5] I did it in my head.
I have noticed that the (1+sqrt(5))/2 is a version of phi. Do you think that it is possible to express in terms of phi or in terms of the relevant version of phi??? Just asking
0+1=1; 1+1=2; 1+2=3; 2+3=5; 3+5=8; 5+8=13; 8+13=21; 13+21=34; 21+34=55; 34+55=89; 55+89=144I'm out of breath. Φ=(1+√5)/2; Φ^12=144Φ+89=144(1+√5)/2+89=161+72√5=321.997...
Golden ratio !
{1x+1x ➖ }+{5x+5x ➖ }/2 ={2x^2+10x^2}/2÷12x^4/2=6x^4 3^2x^2^2 3^1x1^2 3x^2 (x ➖ 3x+2).{x^12+x^12 ➖}=x^24 x^4^6 x^4^3^2 x^2^2^3^2 x^1^13^2 x^3^2 (x ➖ 3x+2).
👋👋👋
EXCELLENTONIO!
((1+Sqrt[5])/2)^12=161+72Sqrt[5] I did it in my head.
I have noticed that the (1+sqrt(5))/2 is a version of phi. Do you think that it is possible to express in terms of phi or in terms of the relevant version of phi??? Just asking
0+1=1; 1+1=2; 1+2=3; 2+3=5; 3+5=8; 5+8=13; 8+13=21; 13+21=34; 21+34=55; 34+55=89; 55+89=144
I'm out of breath. Φ=(1+√5)/2; Φ^12=144Φ+89=144(1+√5)/2+89=161+72√5=321.997...
Golden ratio !
{1x+1x ➖ }+{5x+5x ➖ }/2 ={2x^2+10x^2}/2÷12x^4/2=6x^4 3^2x^2^2 3^1x1^2 3x^2 (x ➖ 3x+2).{x^12+x^12 ➖}=x^24 x^4^6 x^4^3^2 x^2^2^3^2 x^1^13^2 x^3^2 (x ➖ 3x+2).