Enzymes Stabilize Transition State

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  • Опубліковано 29 січ 2025

КОМЕНТАРІ • 52

  • @fibonacci101
    @fibonacci101 8 років тому +49

    I had never truly understood all the concepts in this video until I saw your explanation. You are truly a great resource to all students in biochem.

  • @Nunyabisinas
    @Nunyabisinas 10 місяців тому +3

    Im a 12th grade student. I had a hard time understanding the concepts of transition state and enzyme substrate complex. Read school textbooks, watched other lectures and still had so many doubts. Then i found your video, and i must say that you really are a saviour, sir. Amazing lecture, crystal clear explanation. Dont know if you would ever read this, but I'll still say it. You are helping a lot of students, and i hope you never stop doing this amazing work. May you and your loved ones lead a very happy and prosperous life❤️

  • @Bluebell072
    @Bluebell072 7 років тому +13

    bro you save my life ......Ak lectures are best

  • @yonatankebede7478
    @yonatankebede7478 8 років тому +7

    This can't get explained any better ! Thank you for sharing this Sir.

  • @joelryangeorge6557
    @joelryangeorge6557 3 роки тому +2

    After reading the book and watching your lectures, everything kinda make sense. Thank you!

  • @PaanParsons
    @PaanParsons 5 років тому +2

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  • @providencempano2986
    @providencempano2986 Рік тому

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  • @4evaItachisgirl
    @4evaItachisgirl 5 років тому +26

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    • @amythanh03
      @amythanh03 5 років тому +1

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    @kamalchaudhary4328 3 роки тому

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    @bahadurjawed668 4 роки тому

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  • @imagineabout4153
    @imagineabout4153 8 років тому +3

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  • @tinker3bellz1
    @tinker3bellz1 3 роки тому

    What a very clear explanation!! This is sooo easy to understand thank you very much!😄

  • @sayenasimron4602
    @sayenasimron4602 2 роки тому

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  • @lkjhgawertyui7452
    @lkjhgawertyui7452 3 роки тому

    This guy explains it all!

  • @gooddoctor6434
    @gooddoctor6434 6 років тому +1

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  • @dayitabiswas4295
    @dayitabiswas4295 5 років тому

    An actual lifesaver

  • @Jassixrare
    @Jassixrare Рік тому

    Amazing 😍😍

  • @ajinkyamehere5365
    @ajinkyamehere5365 2 роки тому

    I have following questions :
    1) If the activation energy is higher than ∆G (in this case, negative), then the energy required to overcome the activation barrier will be higher than the gains from the free energy difference between reactants and products. So this reaction should be endergonic, instead of endergonic, even though the free energy of products is lower than that of the reactants. Correct or not?
    2) How can exergonic uncatalyzed reactions be spontaneous, when you still need to input energy first to overcome the activation barrier.

  • @nimasabri4000
    @nimasabri4000 4 роки тому

    Amazing explanation.Thank you

  • @asmaaziz8576
    @asmaaziz8576 4 роки тому

    Amazing 👍👍

  • @nowweknow754
    @nowweknow754 8 років тому

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  • @janzi146
    @janzi146 6 років тому

    i will literally buy your merch thank u sweetheart for helping me

  • @anooprao6380
    @anooprao6380 9 років тому

    At 2:53, why/how does the difference in the energies of products and reactants affect the equilibrium concentrations of products and reactants? Thanks for the video :)

  • @meganwiseman7979
    @meganwiseman7979 7 років тому +1

    I don't understand how you get a negative value if you subtract the energy of the products from the energy of the reactants. Isn't the free energy of the products lower then the free energy of the reactants? hence if you subtract it you will get a positive integer? I think you mean to say instead "subtract the energy of the reactants from the energy of the products"?........ A little confused please explain. My understanding is free energy is lost in the reaction, so the system will experience an energy loss and hence delta g is negative as there is less energy in the products then the initial ground state of the reaction. please revise 1:50

    • @kietack1203
      @kietack1203 7 років тому

      nope, hes right. Delta G = G(final) - G(initial). Since G(initial) > G(final) so delta G is negative

    • @meganwiseman7979
      @meganwiseman7979 7 років тому

      but thats not what he said he said if you subtract the energy of the products(final) from the energy of the reactants(initial) aka. g(initial)-g(final)???? and by that logic delta g would be positive that is what I was trying to say that it should be the other way around, he should say subtract the reactants(initial) from the products (final). if I'm completely wrong please correct me.

    • @kietack1203
      @kietack1203 7 років тому

      Now i noticed, you're correct. Substract A from B means taking A away from B or B - A . So he might have misused his words. I'm sure he meant substract the energy of the products TO the energy of the reactants not FROM. :D

    • @meganwiseman7979
      @meganwiseman7979 7 років тому

      Ok good to know! Just because I'm studying chemistry right now and I was a little confused. Thanks for the clarification!

  • @casualcasual1234
    @casualcasual1234 3 роки тому

    Why does the enzyme activity-substrate concentration graph linear before it levels off?

  • @danazamer5280
    @danazamer5280 3 роки тому

    Thank you so much this is so helpful !

  • @nataliasalamanca3946
    @nataliasalamanca3946 4 роки тому

    thank you so much¡¡ you do the explanations very clears

  • @tahrimahmad5007
    @tahrimahmad5007 4 роки тому

    Best👍

  • @samahnour5423
    @samahnour5423 2 роки тому

    I have a question here , if enzymes speed up chemical reactions how do they decrease time needed to reach equilibrium? shouldn't it be the opposite ?

  • @bikashkisan9001
    @bikashkisan9001 7 років тому

    Sir u r just great.

  • @ridatufail628
    @ridatufail628 3 роки тому

    Thank u very much🤗🤗🤗

  • @roc7880
    @roc7880 10 місяців тому

    thanks for writing all those tiny letters, not only the content.

  • @dhooy7150
    @dhooy7150 9 років тому

    Do you have any videos on metal- ion catalysis, covalent-bonds, or any other ways to decrease the activation energy?

  • @tobinos8018
    @tobinos8018 7 років тому

    Wonderful videos but why is it that you dont respond to questions arising from your lectures?

  • @malluentertainer5041
    @malluentertainer5041 8 років тому +1

    I need to get next part of this lecture. please help me sir

  • @chemisthmh198
    @chemisthmh198 7 років тому

    thank you 😊

  • @Weejee456
    @Weejee456 8 років тому +4

    The Y coordinate of the graph is wrong, should be G, not delta G.

    • @d1ks4u
      @d1ks4u 8 років тому

      no it is delta Grx

    • @d1ks4u
      @d1ks4u 8 років тому +1

      just kidding youre right. Free energy, or G should be on the Y axis not delta G.

  • @prasantagiri3263
    @prasantagiri3263 5 років тому

    Sir ES is transition state or intermediate

  • @Reverse-e6c
    @Reverse-e6c 5 років тому

  • @edgarramirezhuerta1864
    @edgarramirezhuerta1864 4 роки тому

    genius

  • @Jake-tz6ye
    @Jake-tz6ye 5 років тому

    7:10

  • @zerakhu
    @zerakhu 6 років тому

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  • @debraputuka9811
    @debraputuka9811 6 років тому

    I should probably give it sometime to sink

  • @debraputuka9811
    @debraputuka9811 6 років тому +1

    I can't hear a thing😴