1:15:56 Q :- log [1+g(x)²] is an anit- derivative of ? Ans :- i did the differentiation of log[1+(g(x)²] I got the answer 2 × g(x) × g' (x) =------------------------. [g'(x) = f(x)] 1+ g(x)² => 2 g(x) f(x) ---------------- 1+ g(x)² Sir is this method correct Please reply ❤❤❤❤❤lu you teaching ❤❤❤❤❤❤
Sir I have a doubt sir....at 1:15:58 question 73 loo manam formula direct ga integral of f'(x)/f(x) formula use chesthe log f(x) vasthundhi kadha sir.....then option d vasthundhi kadha sir ....plz sir clear my doubt sir...🙏🙏🙏..any one plz clear my doubt...🙏
Thank you for the efforts sir Small doubt : 55:51 lo f(1/4) value 1/16 rasaru ... already akkada 1/16 undi ..then 4 to 16 ki multiply enduku cheyledu .... Please clear my doubt sir or if anyone knows then please ans me
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1:15:56
Q :- log [1+g(x)²] is an anit- derivative of ?
Ans :- i did the differentiation of log[1+(g(x)²]
I got the answer
2 × g(x) × g' (x)
=------------------------. [g'(x) = f(x)]
1+ g(x)²
=> 2 g(x) f(x)
----------------
1+ g(x)²
Sir is this method correct
Please reply ❤❤❤❤❤lu you teaching ❤❤❤❤❤❤
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Sir I have a doubt sir....at 1:15:58 question 73 loo manam formula direct ga integral of f'(x)/f(x) formula use chesthe log f(x) vasthundhi kadha sir.....then option d vasthundhi kadha sir ....plz sir clear my doubt sir...🙏🙏🙏..any one plz clear my doubt...🙏
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ANSWER C SIR 2:57:57
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Small doubt : 55:51 lo f(1/4) value 1/16 rasaru ... already akkada 1/16 undi ..then 4 to 16 ki multiply enduku cheyledu ....
Please clear my doubt sir or if anyone knows then please ans me
AS, f(x) = 1/16 (constant term ) doesn't contains any x term so, we did't substituted 1/4 in f(x)
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1:06:48
ANSWER A 2:57:00
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