Solving for Center, Vertices, Foci and Asymptotes of Hyperbola.

[@shushi_shann7257]

Underrated Chanel, I hope you continue to grow

[@MATHStorya]

Thank you

[@Parthkumar_vekariya]

great explanation

[@rueljohngumisad4382]

What a lifesaver, thank you very much for the help.

[@asayasjohnairizm.6369]

Thank you i finish my assignment

[@runonline4065]

Wow lifesaver

[@labyrinthforester6909]

Great video! Thaaank you for this

[@MATHStorya]

You're always welcome

[@juliaboo9163]

thank u so much, sir! 🤍

[@MATHStorya]

Welcome po…

[@anonymousakj9056]

Thank you Sir for this video

[@clynefaylafable]

sir pano po sa transverse axiis

[@MATHStorya]

2a...for this problem since a=3, so 2(3) = 6 is the length of the transverse axis.

[@loe7349]

@@MATHStorya pano po pag Vertical? Ganun din po?

[@MATHStorya]

@@loe7349 ua-cam.com/video/PRPokY2RX6g/v-deo.html

[@jovikimorbita8547]

Pwede po ito sa yung igraph?

[@MATHStorya]

pwede po using the center, vertices, and foci.

[@hipphipphurra77]

Nice but the general equation in this example is not a general hyperbola as the naive audience might expect - it has no rotation angle.

[@MATHStorya]

Thanks for this info sir... I always learned something from my viewers..

[@vonkaiser4241]

sir pano if may xy component

[@MATHStorya]

What is the given?

[@vonkaiser4241]

@@MATHStorya x^2 - 4 x y - y^2 + 2 x - 4 y - 8 = 0. Thank you po in advance