Sir,Is it possible to integrate sin x and 1 upon cos ^2 x individually. Means, integration of sin x is - cos x and we have 1 upon cos square x, therefore it is sec square x. Therefore, - cos x into tan x + c should be the answer. Sir,plz solve my doubt
A small typo: in 2:02, a /= -1, instead of 1 because when a = -1, the denominator will be 0, hence whole problem will not be solvable.
very tankful for this video, mate, U R the Best!!!
Glad it helps!
Can you do this without substitution
Yes, another way will be to express it as sec x tan x. The integral of sec x tan x is sec x + c.
Teşekkürler 💃💃💃
Wow it's just amazing
🎉🎉🎉🎉🎉woww thanks
You are welcome!
very nice tutorial
thank you
thank you you helped a lot
I am glad it helps
Thank you for the video
glad it helps!
Thanks ❤️
Youre welcome glad it helps
Just rewrite sinx/cos²x as secxtanx
Exactly🤣
Why to all this nonsense thing
Yeah its another thing we will…
Sir,Is it possible to integrate sin x and 1 upon cos ^2 x individually.
Means, integration of sin x is - cos x and we have 1 upon cos square x, therefore it is sec square x.
Therefore, - cos x into tan x + c should be the answer.
Sir,plz solve my doubt
It is not possible to integrate sinx and 1/cos^2x individually as it is not the correct way to solve this integration problem
Why are you not talk in hindi?🥺🥺🥺
I am understanding hindi better than English 🤗🤗🤗🤗
I wish i can! I hope somewhere can help me translate to hindi
U can let u =1/cosx for a faster solution
It is an alternative way to solve too