How to Derive the Roche Limit

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  • Опубліковано 15 жов 2024
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    Welcome, my name is Phil, and in this video I explain to derive the Roche Limit.
    The Roche Limit is the distance that a moon or satellite can be before the gravitational tides from a larger object, like a planet, pull it apart. At the Roche limit the gravitational tides from the planet are balanced by the self gravity of the satellite. At closer distances the satellite is pulled apart. When further away from the Roche limit the satellite can hold itself together under its own gravitational forces.
    In this video we balance these two forces and find an expression for the distance at which objects would be pulled apart by the planets tides.

КОМЕНТАРІ • 27

  • @TheLaughterAsylum
    @TheLaughterAsylum 3 роки тому +10

    Subscribed, There are only a few UA-camrs like you who do bring the mathematical rigor of Astrophysics, Appreciated the content Thanks!

  • @AngSH2024
    @AngSH2024 Рік тому +1

    Im going to have to start binging from the beginning of these videos to get to catch up lol!!

  • @vrsrinivas3550
    @vrsrinivas3550 2 роки тому +1

    Thank you. Wonderful explanation 👍👍

  • @sudeepdighe5702
    @sudeepdighe5702 3 місяці тому

    Won't the density of both the bodies be more difficult to obtain compared to the other result consisting of radius of the satellite?

  • @rtt1961
    @rtt1961 Рік тому

    Beautifully done.

  • @enriquelopezcabarcos2744
    @enriquelopezcabarcos2744 Рік тому

    Thank you for the nice explanation✌

  • @moonwalkhi
    @moonwalkhi 10 місяців тому +1

    how are the eqns for Ft and Fg derived? are they only serving a purpose in this case or do they have a more general application (ie do they apply for ALL objects on the surface of a sattelite orbiting another object?)

    • @AstroPhil2000
      @AstroPhil2000  10 місяців тому +2

      They are some what general as it is the gravitational force acting on an object at the surface of the satellite from the satellite and planet. All objects on the surface experience these forces, but if they are not on the closest face of the satellite towards the planet the tidal force will be lower. Physically this means the satellite would be pulled apart from the side facing the planet first, since this is where the tidal forces are strongest

  • @jibriel4918
    @jibriel4918 Рік тому

    Is Earth considered a rigid or fluid body? I mean if the earth was heading to a black hole, how would it deform before crossing the Roche limit, and what is the factor associated with its rigidity that we would have to use to calculate the Roche limit in such a scenario?

  • @ggxsky4811
    @ggxsky4811 7 місяців тому

    Do you have Tidal force formula Derrivation

  • @Buonarotti10
    @Buonarotti10 2 роки тому +2

    Can you calculate the Roche limit for the earth and the moon?

    • @AstroPhil2000
      @AstroPhil2000  2 роки тому +1

      Yes, you can do this for the Earth and Moon. The moon would start being pulled apart around 9,500km from the Earth, but that is from the centre of Earth. In reality this would happen just over a couple thousand km above the surface.

    • @Buonarotti10
      @Buonarotti10 2 роки тому

      @@AstroPhil2000 Thank you. This information makes me nervous!

    • @AstroPhil2000
      @AstroPhil2000  2 роки тому

      ​@XENENEX Yes it would break up at that point. However, it depends on how it approached this limit to whether a ring would be formed or not. If they were moving directly towards each other then it is likely that the material would just fall / collide with the Earth.

  • @lorenzocimino2827
    @lorenzocimino2827 2 роки тому +1

    Do you have a reference for the derivation with the "fluid satellite" ?

    • @AstroPhil2000
      @AstroPhil2000  2 роки тому +1

      Although not a proper reference, this shows how you get the slightly different version for a fluid satellite: en.wikipedia.org/wiki/Roche_limit

  • @vimalramachandran
    @vimalramachandran 2 роки тому +1

    Nice one!

  • @gigachad6844
    @gigachad6844 7 місяців тому

    Why tidal force is 2GMur/d^3?

    • @AstroPhil2000
      @AstroPhil2000  7 місяців тому

      The tidal force is the change in force over some small distance compared to the distance that separates the objects. When the change in distance is small compared the distance r it can be expanded and only the first term is used, the others can be neglected, leaving 2GMur/d^3.

  • @balram3183
    @balram3183 3 роки тому +1

    Thanku sir 😀

  • @akshat1719
    @akshat1719 2 роки тому +1

    Woahhhhhh.....
    I came to know about this from a book
    WHAT-IF by Randall Munroe
    I suggest it to u
    It's very interesting....
    Give it a read if u can😁

    • @AstroPhil2000
      @AstroPhil2000  2 роки тому +1

      Thank you for the recommendation, I can see how the Roche Limit would have found its way into that book. It is a great way to pull apart planet and moon sized objects.

  • @mrhaker6348
    @mrhaker6348 2 роки тому +1

    I am from india