Forgive what maybe a silly question. But what is the correct name for the board you are using to place the cards on? My son is getting into magic quite a bit now and i wanted to get him one of these boards. But i don't know what to search for or where to get one. Can you help
The explanation is actually pretty simple. After the piles are combined into two sets of eight cards, each pile contains two face-up Aces and six face-down cards. Flipping one pile reverses this, and dealing the cards into alternate piles doesn't change their order, it just makes the 16 cards consist of two intermingled series whose order hasn't changed (as if you performed a perfect riffle shuffle). Then dealing the cards into four piles sorts the cards into alternating series- piles 1 and 3 match, and piles 2 and 4 match. Thus when combining the piles, they need to be reversed, and this is the reason for "rolling" the four piles together. So for example if pile 1 has face-up Ace(s) and the rest face-down, pile 2 automatically has face-down Ace(s) and the rest face-up, and thus the two piles must be reversed, and so on. At the end, all of the Aces are in the original configuration along with the indifferent cards.
Great explanation. It makes me wonder if the exact number of facedown cards matters. I have a feeling that it doesn't (as long as all four aces get the same amount).
I believe the simple reason that the trick works is that it is only ever the four aces at the start that are face up. The piles of 3 cards added are face down. The packets are selected in pairs so this does not change the original orientation. The cards can go through as many steps as you like but the basic orientation does not change. It’s not a maths thing it’s simply the orientation of the four aces never changes, shuffling only changes the order not the base orientation as these are swapped in pairs of packets with each packet containing a single ace. David S
All misdirection !!! The collecting of the packets at the end before the ribbon spread gives the secret away, there are several self working card effects that use same method!! Not mathematical!!! Gary in dreamland; have a nice dream!!😊♥️🌟🌟🎲🎲🌠
Also works if you deal the four aces (or any same four numbers) face down and put the 3 cards face up on top of them. Then it’s a set-up, but has more of a surprise to it all and might lend itself to storytelling better.
I was thinking about engineering a trick like this the other day..a 4 Ace production, put the aces back into a shuffled deck, have the spectator deal four equal piles onto the deck, the last card in each pile is an Ace, each suit is in order.
Hey there, Uncle Steve, lol. This is really slick. I thought this trick was something like the cheek to cheek trick. Lol. But i was wrong. I read 2 or 3 comments who i believe have the right answer as to how / why this trick works like it does. The 4 aces are the only cards in the beginning that are face up. I also think things change when dealing 4 piles, one card at a time. Well, maybe that doesn't matter, 😊. There is no math involved. I just did the trick back wards, and it worked. I put the 4 aces face- down, and I put 3 cards face-up on each ace. I did the trick the same way, and the 4 aces were the only 4 cards face down. Lol. Thanks, man. Blessings to you and your family.
I think impossible self-working tricks have become my new favourite type of card tricks. Being that there is very little trickery [or even sleight of hand skill] used, it for some reason impresses me more that they are more ingenious.
Recently stumbled across your channel and subscribed.Tried this trick and cant believe it worked.Hope to see some more awesome content in the future.All the best.
I figured it out. The deal is that one stack is face up, and the other is face down. So, when you alternate cards to create one stack, every other card is face up. Except the aces, of course. Then, when you deal them out one at a time into 4 stacks, the 1st and 3rd stacks are face up, while the 2nd and 4th stack are face down. Well, when you "roll up" the 4 stacks, stacks 1 and 3 are flipped an odd number of times, so they end up flipped over. So, they were face up, but are now face down. Stacks 2 and 4 are flipped an even number of times, so they finish as they started, face down. Now, all 4 stacks are face down. Just as you started. All the shuffling makes it look like chaos, which is very helpful to the illusion. Try the same trick, but without the aces flipped differently. You'll see.
Excellent, Hi Steve, I can explain it up until you do every other card , that’s when I cannot , I will be doing this until I can understand it , but excellent.
Thank you for that tutorial Mr Steve I really enjoyed that mind-blowing trick it really is strange how that works I have no clue myself LOL but I will definitely be performing this one again I really do appreciate the video until next time take care of yourself your friend Billy Simmons
What a cool trick! I'll be doing this one at get togethers this year! And I'm right there with you, Steven! I should've paid more attention in math class, too! LOL
if you look through the final 4 piles as you turn them over you can see you are putting the aces back the same way and all the other cards are going back the opposite way. Freaken clever trick
My friend. You are need 4 cards in a 16 card game of 4 piles of 4. The order after you put one over the other one puts everything in order because they are even and 4x4 is 16. The best way to understand it is do it without mixing, because it really doesn’t matter and deal the cards one beside the other and you’ll understand it better than my explanation. Great trick though I didn’t see it at first. I’ve been dealing to my self for 11 hours after I got it jajaja. Abrazo!
1) The Aces face the opposite direction from the rest of the cards. 2) You flip half of the deck (let's call one half on the left the A cards, and the half on the right the B cards). 3) By alternately dealing, effectively performing a Faro shuffle, the cards get merged into one pile ABABABAB etc. etc. Let's assume the B side gets flipped. 4) You then deal this deck into four piles. The piles will be four A cards, four B cards, four A cards, and lastly four B cards. 5) By alternately flipping the four piles back into one, you effectively undo the flip from step 2). Try it only with the four Aces, or use two visibly different / distinct decks (one for A, the other for B) to see what I mean.
As stated below ... no actual "math" is involved in this trick. If you want to make the algorithm easier to follow ... just put ONE face-down card on those aces.
Consider the cards in each original pile named as follows: (a1 a2 a3 a4) (a5 a6 a7 a8) (b1 b2 b3 b4) (b5 b6 b7 b8) Grab two piles and shuffle them, and the other two piles and shuffle them. It doesn't matter which piles you grab due to symmetry. It also doesn't matter what order you shuffle them into as only the orientation of the cards matters. You can think of this symmetry as assigning the Ace to one of the random numbers in each pile. flip one of the shuffled piles. It doesn't matter which one you flip. (call the flipped cards A instead of a) now you have two piles: (A1 A2 A3 A4 A5 A6 A7 A8) (b1 b2 b3 b4 b5 b6 b7 b8) Deal them alternating between the two piles. (A1 b1 A2 b2 A3 b3 A4 b4 A5 b5 A6 b6 A7 b7 A8 b8) Now deal them in 4 piles: (A1 A3 A5 A7) (b1 b3 b5 b7) (A2 A4 A6 A8) (b2 b4 b6 b8) Flip the first pile 3 times, the second pile 2 times, and the third pile 1 time. (a1 a3 a5 a7) (b1 b3 b5 b7) (a2 a4 a6 a8) (b2 b4 b6 b8) Now all the piles have the same orientation as they did in the original piles. The order of cards in each pile may have changed, but the orientation is the same. If you want to make it easy to empirically show this, grab A-4 in each suit and look at the arrangement of the cards after each step.
It's done because of something called the Gilbreath principle. If you really want me to explain it to you then I will do for £1,000,000,000 or £1,000,000 and an IOU to pay me £2.20 a week for perpetuity. Hopefully everyone can see that the second option is obviously better for you but it's up to you which you go for. Anyway if you'd really like to know those are your options. 😂
Here is UNEXPLANABLE 2.0! It really has my head spinning 😅
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Forgive what maybe a silly question. But what is the correct name for the board you are using to place the cards on? My son is getting into magic quite a bit now and i wanted to get him one of these boards. But i don't know what to search for or where to get one. Can you help
Also subscribed so that i can show him your videos.
@@TKTrooper close-up pad
I chose the piles you chose
@@otallono Thank you
The explanation is actually pretty simple. After the piles are combined into two sets of eight cards, each pile contains two face-up Aces and six face-down cards. Flipping one pile reverses this, and dealing the cards into alternate piles doesn't change their order, it just makes the 16 cards consist of two intermingled series whose order hasn't changed (as if you performed a perfect riffle shuffle). Then dealing the cards into four piles sorts the cards into alternating series- piles 1 and 3 match, and piles 2 and 4 match. Thus when combining the piles, they need to be reversed, and this is the reason for "rolling" the four piles together. So for example if pile 1 has face-up Ace(s) and the rest face-down, pile 2 automatically has face-down Ace(s) and the rest face-up, and thus the two piles must be reversed, and so on. At the end, all of the Aces are in the original configuration along with the indifferent cards.
That's the correct and indeed very simple explanation, thanks for writing it down!
I also figured it out, but it works on almost everyone because it throws you off!
@@Noamiko613 only as long as it's not clear to the spectator that all asses get the same amount of cards on top.
Great explanation. It makes me wonder if the exact number of facedown cards matters. I have a feeling that it doesn't (as long as all four aces get the same amount).
What he said ...
I believe the simple reason that the trick works is that it is only ever the four aces at the start that are face up. The piles of 3 cards added are face down. The packets are selected in pairs so this does not change the original orientation. The cards can go through as many steps as you like but the basic orientation does not change. It’s not a maths thing it’s simply the orientation of the four aces never changes, shuffling only changes the order not the base orientation as these are swapped in pairs of packets with each packet containing a single ace. David S
Well done!!!!
@herberar sorry, not so well done. The correct and very simple explanation is given by Severian in the comments.
It's very easy. It's like one long false shuffle with the 4 aces returning to their original position of face up and the other cards face down.
All misdirection !!! The collecting of the packets at the end before the ribbon spread gives the secret away, there are several self working card effects that use same method!! Not mathematical!!! Gary in dreamland; have a nice dream!!😊♥️🌟🌟🎲🎲🌠
Fantastic this Steve learning lots from your channel I'm looking forward to performing these tricks on the Family at Xmas thank you🙏
Also works if you deal the four aces (or any same four numbers) face down and put the 3 cards face up on top of them. Then it’s a set-up, but has more of a surprise to it all and might lend itself to storytelling better.
That is insane 😳 Mindblown🎉 😮 Thanks for sharing 🎩 ✨️
Thanks Steve, very Clever mate 🙂
I was thinking about engineering a trick like this the other day..a 4 Ace production, put the aces back into a shuffled deck, have the spectator deal four equal piles onto the deck, the last card in each pile is an Ace, each suit is in order.
Hey there, Uncle Steve, lol. This is really slick.
I thought this trick was something like the cheek to cheek trick. Lol.
But i was wrong.
I read 2 or 3 comments who i believe have the right answer as to how / why this trick works like it does.
The 4 aces are the only cards in the beginning that are face up.
I also think things change when dealing 4 piles, one card at a time. Well, maybe that doesn't matter, 😊.
There is no math involved.
I just did the trick back wards, and it worked.
I put the 4 aces face- down, and I put 3 cards face-up on each ace. I did the trick the same way, and the 4 aces were the only 4 cards face down. Lol. Thanks, man. Blessings to you and your family.
Mind-blowing
I think impossible self-working tricks have become my new favourite type of card tricks. Being that there is very little trickery [or even sleight of hand skill] used, it for some reason impresses me more that they are more ingenious.
I totally agree I get the best reactions 👍
Another awesome trick for an amateur to add to their routine! Love your channel and thanks!
You’re very welcome!
Recently stumbled across your channel and subscribed.Tried this trick and cant believe it worked.Hope to see some more awesome content in the future.All the best.
Appreciate the sub mate!
I figured it out. The deal is that one stack is face up, and the other is face down. So, when you alternate cards to create one stack, every other card is face up. Except the aces, of course.
Then, when you deal them out one at a time into 4 stacks, the 1st and 3rd stacks are face up, while the 2nd and 4th stack are face down.
Well, when you "roll up" the 4 stacks, stacks 1 and 3 are flipped an odd number of times, so they end up flipped over. So, they were face up, but are now face down. Stacks 2 and 4 are flipped an even number of times, so they finish as they started, face down.
Now, all 4 stacks are face down. Just as you started.
All the shuffling makes it look like chaos, which is very helpful to the illusion.
Try the same trick, but without the aces flipped differently. You'll see.
I've seen a different version of this trick but this one is better imo. Great work
wow ! def legit a awesome trick... Gonna start adding that one right away.
Excellent, Hi Steve, I can explain it up until you do every other card , that’s when I cannot , I will be doing this until I can understand it , but excellent.
Thank you for that tutorial Mr Steve I really enjoyed that mind-blowing trick it really is strange how that works I have no clue myself LOL but I will definitely be performing this one again I really do appreciate the video until next time take care of yourself your friend Billy Simmons
Great trick
❤ Thanks for sharing!
What a cool trick! I'll be doing this one at get togethers this year! And I'm right there with you, Steven! I should've paid more attention in math class, too! LOL
Hope it goes well mate! Smash it!
Great trick to do on a video call where the person uses their own deck and you just direct them.
Thanks Steve, you r my hero 😊
if you look through the final 4 piles as you turn them over you can see you are putting the aces back the same way and all the other cards are going back the opposite way.
Freaken clever trick
Teach us some practical card controls please
fantastic trick, nice n easy with an amazing result 👍
My friend. You are need 4 cards in a 16 card game of 4 piles of 4. The order after you put one over the other one puts everything in order because they are even and 4x4 is 16. The best way to understand it is do it without mixing, because it really doesn’t matter and deal the cards one beside the other and you’ll understand it better than my explanation.
Great trick though I didn’t see it at first. I’ve been dealing to my self for 11 hours after I got it jajaja. Abrazo!
this man clearly punched a kangaroo recently.
Amazing. Another winner.
I can't find the video with 2M views. 🧐Please provide link, I'd like to see the original one too. Thanks
Brilliant 😊😊😊😊
Nice!
Wow you’ve done it again Uncle Steve 👍
Very cool!
Very nice, sir!
This trick also works if you put 6 cards on top of the Aces. Which makes the trick seem even more impressive.
Is that full deck of 52?
I love card tricks like these!! Thank you for sharing can't wait to show my family
No. it's 49 1/2 cards.
You have a special brain😮👍
Great
Nice
1) The Aces face the opposite direction from the rest of the cards.
2) You flip half of the deck (let's call one half on the left the A cards, and the half on the right the B cards).
3) By alternately dealing, effectively performing a Faro shuffle, the cards get merged into one pile ABABABAB etc. etc. Let's assume the B side gets flipped.
4) You then deal this deck into four piles. The piles will be four A cards, four B cards, four A cards, and lastly four B cards.
5) By alternately flipping the four piles back into one, you effectively undo the flip from step 2).
Try it only with the four Aces, or use two visibly different / distinct decks (one for A, the other for B) to see what I mean.
Etonnant non!
Bravo.
As stated below ... no actual "math" is involved in this trick. If you want to make the algorithm easier to follow ... just put ONE face-down card on those aces.
It's magic!
It’s not maths here it’s just the illusion created by flipping cards over twice and getting everything in the same order again
Nice trick though
👍👍
damn dude! someone owns a cat ha ha. Great video
My rabbit ripped my hands up.😅 cheers mate
It’s like the British Magical Nate Bargatze.
😂😂
I chose the piles you chose.
Immortal aces.
Stop overloading my old head with reputation making routines It could explode all over my computer work station
Haha I’ll calm down a bit for you
No he has a rabbit.
Consider the cards in each original pile named as follows:
(a1 a2 a3 a4) (a5 a6 a7 a8) (b1 b2 b3 b4) (b5 b6 b7 b8)
Grab two piles and shuffle them, and the other two piles and shuffle them. It doesn't matter which piles you grab due to symmetry. It also doesn't matter what order you shuffle them into as only the orientation of the cards matters. You can think of this symmetry as assigning the Ace to one of the random numbers in each pile.
flip one of the shuffled piles. It doesn't matter which one you flip. (call the flipped cards A instead of a)
now you have two piles: (A1 A2 A3 A4 A5 A6 A7 A8) (b1 b2 b3 b4 b5 b6 b7 b8)
Deal them alternating between the two piles. (A1 b1 A2 b2 A3 b3 A4 b4 A5 b5 A6 b6 A7 b7 A8 b8)
Now deal them in 4 piles: (A1 A3 A5 A7) (b1 b3 b5 b7) (A2 A4 A6 A8) (b2 b4 b6 b8)
Flip the first pile 3 times, the second pile 2 times, and the third pile 1 time.
(a1 a3 a5 a7) (b1 b3 b5 b7) (a2 a4 a6 a8) (b2 b4 b6 b8)
Now all the piles have the same orientation as they did in the original piles. The order of cards in each pile may have changed, but the orientation is the same.
If you want to make it easy to empirically show this, grab A-4 in each suit and look at the arrangement of the cards after each step.
Im definitely not that person either thanks for sharing
No mathematics here. Two bundles with access are flipped once and then flipped back again!
It's done because of something called the Gilbreath principle. If you really want me to explain it to you then I will do for £1,000,000,000 or £1,000,000 and an IOU to pay me £2.20 a week for perpetuity.
Hopefully everyone can see that the second option is obviously better for you but it's up to you which you go for.
Anyway if you'd really like to know those are your options. 😂
It is math. But pretty cool trick
UNEXPLENABLE??? NOt
I hate to be this guy but this is an extremely well-known trick that can absolutely be explained; others in the comments have already broken it down
It cannot be explained because it's math. 🙄
you have a cat?
Schon wieder eine KI-Stimme!
Dislike!